I have a Path which is not valid:
C:\xampp\htdocs\laposte\app\webroot\img/Penguins.jpg
how to change the string having forward slashes only e.g
C:/xampp/htdocs/laposte/app/webroot/img/Penguins.jpg
my idea is to extract the words out of the string and then rebuild the string with forward slash.
how do you do that?
Use realpath function.
$str = realpath("C:\\xampp\\htdocs\\laposte\\app\\webroot\\img/Penguins.jpg");
echo $str; //C:\xampp\htdocs\laposte\app\webroot\img\Penguins.jpg
Or directly :
$str = str_replace('\\', '/', $str);
echo $str; //C:/xampp/htdocs/laposte/app/webroot/img/Penguins.jpg
I think that your path is OK for windows, except for the last slash. It should be backslash like this:
C:\xampp\htdocs\laposte\app\webroot\img\Penguins.jpg
It's better to use constant DIRECTORY_SEPARATOR rather than / to separate your path. It'll completely fix your problem.
Use string replace function in php:
echo str_replace("\\","/","C:\xampp\htdocs\laposte\app\webroot\img/Penguins.jpg");
Related
I'm curious as to how I would get a certain value after a delimiter in a URL?
If I have a URL of http://www.testing.site.com/site/biz/i-want-this, how would I extract only the part that says "i-want-this", or initially after the last /?
Thank you!
You want basename($path); It should give you what you need:
http://www.ideone.com/8hFSN
$url = "http://www.testing.site.com/site/biz/i-want-this";
preg_match( "/[^\/]*$/", $url, $match);
echo $match[0]; // i-want-this
You can use basename() but if you are on Windows, it will break on not just slashes but also backslashes. This is unlikely to come up as backslashes are unusual in a URL. But I suspect you could find them in a query string in a valid URL.
I'm importing data from a csv and I've been looking high and low for a particular regular expression to remove trailing slashes from domain names without a directory after it. See the following example:
example.com/ (remove trailing slash)
example.co.uk/ (remove trailing slash)
example.com/gb/ (do not remove trailing slash)
Can anyone help me out with this or at least point me in the right direction?
Edit: This is my progress so far, I've only matched the extension at the moment but it's picking up those domains with trailing directories.
[a-z0-9\-]+[a-z0-9]\/[a-z]
Many thanks
I don't know how it would compare to a regular expression performance-wise, but you can do it without one.
A simple example:
$string = rtrim ($string, '/');
$string .= (strpos($string, '/') === false) ? '' : '/';
In the second line I'm only adding a / at the end if the string already contains one (to separate domain from folder).
A more solid approach would probably be to only rtrim if the first / found, is the last character of the string.
not sure,
but you can try this,
if it is a $_SERVER['SERVER_NAME'] only then remove slash otherwise keep it
because $_SERVER['SERVER_NAME'] will return URL without any directory
try this
/^(http|https|ftp)\:\/\/[a-z0-9\-\.]+\.[a-z]{2,3}(:[a-z0-9]*)?\/?([a-z0-9\-\._\?\,\'\/\\\+&%\$#\=~])*$/i
you could test for a match on /[a-z]/, then remove the last charater if it's not found.
this is javascript, but it'd be similar in php.
/\/[a-z]+\//
var txt = 'example.com/gb/';
var match = txt.match(/\/[a-z]+\//);
if (!match) {
alert(txt.substring(txt,txt.length-1));
}
else {
alert(txt);
}
http://jsfiddle.net/xjKTS/
Try this, it works：
<?
$result = preg_replace('/^([^\/]+)(\/)$/','$1',$your_data);
?>
I have tested like this:
$reg = '/^([^\/]+)(\/)$/';
echo preg_replace($reg,'$1',$str1);//example.com
echo preg_replace($reg,'$1',$str2);//example.co.uk
echo preg_replace($reg,'$1',$str3);//example.com/gb/
?>
I want to replace // but not ://. I'm using this function to fix broken urls:
function fix ($path)
{
return preg_replace( "/\/+/", "/", $path );
}
For example:
Input:
a//a//s/b/d//df//a/s/
Output (collapsed blocks of more than one slash):
a/a/s/b/d/df/a/s/
That is OK, but if I pass a URL I break the http:// part, and end up with http:/. For example:
http://www.domain.com/a/a/s/b/d/df/a/s/
I get:
http:/www.domain.com/a/a/s/b/d/df/a/s/
I want to keep the http:// intact:
http://www.domain.com/a/a/s/b/d/df/a/s/
You can solve it rather easily using a negative lookbehind:
function fix ($path)
{
return preg_replace("#(?<!:)/{2,}#", "/", $path);
}
Note that I've also changed your delimiter from / to #, so you don't have to escape slashes.
Working example: http://ideone.com/6zGBg
This can still match the second slash if you have more than two (file://// -> file://). If this is a problem, you can use #(?<![:/])/{2,}#.
Example: http://ideone.com/T2mlR
return preg_replace("/[^:]\/+/", "/", $path);
Is it possible to remove the trailing slash / from a string using PHP?
Sure it is, simply check if the last character is a slash and then nuke that one.
if(substr($string, -1) == '/') {
$string = substr($string, 0, -1);
}
Another (probably better) option would be using rtrim() - this one removes all trailing slashes:
$string = rtrim($string, '/');
This removes trailing slashes:
$str = rtrim($str, '/');
Long accepted, however in my related searches I stumbled here, and am adding for "completeness"; rtrim() is great, however implemented like this:
$string = rtrim($string, '/\\'); //strip both forward and back slashes
It ensures portability from *nix to Windows, as I assume this question pertains to dealing with paths.
rtrim
Use rtrim cause it respects the string doesnt end with a trailing slash
Yes, it is!
http://php.net/manual/en/function.rtrim.php
how could I remove the trailing slashes and dots from a non root-relative path.
For instance, ../../../somefile/here/ (independently on how deep it is) so I just get /somefile/here/
No regex needed, rather use ltrim() with /. . Like this:
echo "/".ltrim("../../../somefile/here/", "/.");
This outputs:
/somefile/here/
You could use the realpath() function PHP provides. This requires the file to exist, however.
If I understood you correctly:
$path = "/".str_replace("../","","../../../somefile/here/");
This should work:
<?php
echo "/".preg_replace('/\.\.\/+/',"","../../../somefile/here/")
?>
You can test it here.
You could try :
<?php
$str = '../../../somefile/here/';
$str = preg_replace('~(?:\.\./)+~', '/', $str);
echo $str,"\n";
?>
(\.*/)*(?<capturegroup>.*)
The first group matches some number of dots followed by a slash, an unlimited number of times; the second group is the one you're interested in. This will strip your leading slash, so prepend a slash.
Beware that this is doing absolutely no verification that your leading string of slashes and periods isn't something patently stupid. However, it won't strip leading dots off your path, like the obvious ([./])* pattern for the first group would; it finds the longest string of dots and slashes that ends with a slash, so it won't hurt your real path if it begins with a dot.
Be aware that the obvious "/." ltrim() strategy will strip leading dots from directory names, which is Bad if your first directory has one- entirely plausible, since leading dots are used for hidden directories.