submit ajax form with condition - php

Question

hi i am working on an authentification page , so my code is the following
$(document).ready(function(){
var form = $("#connexion");
var login =$("#logins");
var password=$("#passe");
$("#go").click(function(e){
e.preventDefault();
$.ajax({type: "POST",
url: "check_con.php",
data: { email:login.val() , password:password.val() },
success:function(result){
if(result == 'true')
{
alert(result);
}
}});
});
});
i get the form , the login and password and i pass them to my php script .
<?php
//data connection file
//require "config.php";
require "connexion.php";
extract($_REQUEST);
$pass=crypt($password);
$sql = "select * from Compte where email='$email'";
$rsd = mysql_query($sql);
$msg = mysql_num_rows($rsd); //returns 0 if not already exist
$row = mysql_fetch_row($rsd);
if($msg == 0)
{
echo"false1";
}
else if($row[1] == crypt($password,$row[1]))
{
echo"true";
}
else
{
echo"false2";
}
?>
everything is goood , when i give the good email and password i get true otherwise i get false, that's not the problem , the problem is i am trying to redirect the user to another page called espace.php if the result is true so i've tried this .
$(document).ready(function(){
var form = $("#connexion");
var login =$("#logins");
var password=$("#passe");
$("#go").click(function(e){
$.ajax({type: "POST",
url: "check_con.php",
data: { email:login.val() , password:password.val() },
success:function(result){
if(result == 'true')
{
form.submit(true);
}
else form.submit(false);
}});
});
});
now even if the login and password are not correct the form is submitted , how could i manage to do that i mean , if the informations are correct i go to another page , otherwise i stay in the same page.

Answer 1

use json to get result from authanication page
<?php
//data connection file
//require "config.php";
require "connexion.php";
extract($_REQUEST);
$pass=crypt($password);
$sql = "select * from Compte where email='$email'";
$rsd = mysql_query($sql);
$msg = mysql_num_rows($rsd); //returns 0 if not already exist
$row = mysql_fetch_row($rsd);
$result = array();
if($msg == 0)
{
$result['error'] = "Fail";
}
else if($row[1] == crypt($password,$row[1]))
{
$result['success'] = "success";
}
else
{
$result['error'] = "try again";
}
echo json_encode($result); die;
?>
And in the ajax,, check what is the response.
$(document).ready(function(){
var form = $("#connexion");
var login =$("#logins");
var password=$("#passe");
$("#go").click(function(e){
$.ajax({type: "POST",
url: "check_con.php",
data: { email:login.val() , password:password.val() },
success:function(result){
var response = JSON.parse(result);
if(response.error){
//here provide a error msg to user.
alert(response.error);
}
if(response.success){
form.submit();
}
}});
});
});