PHP file_get_contents by an 404 - php

Question

I'm getting JSON arrays with file_get_contents, but if the page doesn't exist I want to give an message: Player not found. But now I get this error:
Warning: file_get_contents(urlwithan404errorhere)
[function.file-get-contents]: failed to open stream: HTTP request
failed! HTTP/1.1 404 Not Found in -------
I don't get this error when the api gives me an correct JSON array.
This is the code is use:
$gegevens = file_get_contents('');
$array_2 = json_decode($gegevens, TRUE);
$summonerid = $array_2[$naam]["id"];

Answer 1

Your code could become like this:
$gegevens = #file_get_contents('');
if ($gegevens !== FALSE) {
$array_2 = json_decode($gegevens, TRUE);
$summonerid = $array_2[$naam]["id"];
} else {
$summonerid = 0;
}
Explanations:
* the # in front of file_get_contents is to stop showing php error in case the request failed.
* if the $summonerid equals to 0, then you have no player found

Answer 2

Try something like this:
if (($gegevens = #file_get_contents('')) === false) {
printf("<h1>Player not found!</h1>\n");
return;
}
// ... continue here ...
The # will suppress any error message if file_get_contents()fails. It will return falsein this case (use === for comparison to avoid confusion with empty files), which you can use for failure detection.