PHP Search Array column for match - php

I have an array as below, which has multiple columns. I want to search in the first column for a specific value, and have the rows that match returned. Is that possible to do?
For example:
Array (
[0] => Array ( [id] => 1 [column2] => value2 [column3] => value3 [column4] => value4 [column5] => value5 )
[1] => Array ( [id] => 1 [column2] => value2 [column3] => value3 [column4] => value4 [column5] => value5 )
[2] => Array ( [id] => 2 [column2] => value2 [column3] => value3 [column4] => value4 [column5] => value5
)
So let's say I want to search the "id" column for "1" and have the results displayed. How can this be done? Thank you so much!

If you are using PHP >= 5.5, then you can use the new array_column(), in conjunction with array_keys() and array_map().
Given your array, $array:
$keys = array_keys(array_column($array, 'id'), 1);
$new_array = array_map(function($k) use ($array){return $array[$k];}, $keys);
See demo

Since you have an nested Array you need two iterations:
$filtered = array();
$rows = Your Array;
foreach($rows as $index => $columns) {
foreach($columns as $key => $value) {
if ($key == 'id' && $value == '1') {
$filtered[] = $columns;
}
}
}
This should do the job.

I found a much simpler solution that I think is worthwhile sharing with the world
in_array(1, array_column($yourArray, 'id'));
Tested on PHP >= 5.5

These steps will always return a row in an array that uses a unique id column (in this example in the first column, 0)
1) Get an array of just IDs
$ids = array_column($my_table, 0);
2) Find the row with my ID
$row_index = array_search($id, $ids); (where $id is a certain ID)
3) Then I could use
$my_table[$row_index][n] (where n is a given column)

Use this function :
global $result;
function array_searc_result($array,$key,$value)
{
global $result;
foreach($array as $k=>$v)
{
if(array_key_exists($key,$v) && ($v[$key] == $value))
{
$result[] = $v;
}
}
return $result;;
}
$data = array_searc_result($array,'id',2);
echo '<pre>';
print_r($data);
echo '</pre>';
$array is your given array variable.

I use this helper to find matches by key / value:
function array_search_by_key($array, $key, $value) {
if(!is_array($array)) {
return [];
}
$results = [];
foreach($array as $element) {
if(isset($element[$key]) && $element[$key] == $value) {
$results[] = $element;
}
}
return $results;
}

Related

How can I sort values from an existing array by data type?

I try to determine the data type of each array value from an existing array using foreach() and var_dump().
Let's say I have this array: example:
$arr = ['this','is', 1, 'array', 'for', 1, 'example'];
Now I have to take each value of this field and determine its data type.
I try this:
$str = array();
$int = array();
foreach($arr as $k => $val) {
if(var_dump($arr[$k]) == 'string'){
$str[] = $arr[$k];
} else {
$int[] = $arr[$k];
}
}
In other words, I try to sort the values from an existing array by data type and create a new array with only 'string' values and a second new array with only 'int' values. But it seems that my 'if' condition isn't working properly. How else could I solve this please? Thank you.
You need to use gettype to get the type of a value, not var_dump:
foreach($arr as $k => $val) {
if(gettype($arr[$k]) == 'string'){
$str[] = $arr[$k];
} else {
$int[] = $arr[$k];
}
}
Output:
Array
(
[0] => this
[1] => is
[2] => array
[3] => for
[4] => example
)
Array
(
[0] => 1
[1] => 1
)
Demo on 3v4l.org
Use gettype
$data = array('this','is', 1, 'array', 'for', 1, 'example');
foreach ($data as $value) {
echo gettype($value), "\n";
}

php - Multidimensional Array To Single dimension Array With Sum Up

I have this array:
Array
(
[one] => Array
(
[a] => 0
[b] => 1
[c] => 1
[d] => 3
[e] => 1
)
[two] => Array
(
[a] => 0
[b] => 3
[c] => 1
[d] => 4
[e] => 1
)
[three] => Array
(
[a] => 3
[b] => 1
[c] => 2
[d] => 4
[e] => 1
)
)
And I want to convert it into single array with the values are the sums of every value inside the inner array, so it could be like this:
Array
(
[a] => 3
[b] => 5
[c] => 4
[d] => 11
[e] => 3
)
How to achieve it?
EDIT
This was the best what I've done:
$rest = array();
foreach($result as $key => $value){
if(is_array($value)) {
foreach($value as $k => $val){
$rest[$k] = array_sum($value);
}
}
}
But it returns all values to be the same, i.e all 9 on every inner key.
You can get the keys from the first child array with array_keys, and then use array_sum and array_column to generate the array of sums.
foreach (array_keys($your_array['one']) as $key) {
$sums[$key] = array_sum(array_column($your_array, $key));
}
array_column does require php >= 5.5.
Incidentally, what you already had was really close to working. If you change
$rest[$k] = array_sum($value);
to
$rest[$k] += $val;
It should be good to go. What you had before was repeatedly summing the entire sub-array and assigning it to each letter key, but you just needed to add the current value to that letter key.
$rest[$k] += $val; will work, but give you undefined index notices for the first sub-array. You can fix that by checking isset before assigning, like this:
$rest[$k] = isset($rest[$k]) ? $rest[$k] + $val : $val;
I would say modifying your original code to work this way would probably be better than redefining array_column if you can't use it.
You have multidimensional Array , that why have to use two loop for understanding in beginning level. First loop will get Every Object of Array , Second Array will get the Params of Object.
$finalArray = array();
for($i = 0;$i<count($array);$i++){ // GET ALL OBJECT FROM ARRAY
foreach($array[$i] as $key=>$value){ // GET ALL KEY FROM OBJECT
$finalArray[$key] += $array[$i][$key];
}
}
print_r($finalArray);
Work on all version of PHP
You can use array_sum and loop over the first dimension
foreach ($array as $key => $values) {
$newArray[$key] = array_sum($values);
}
Credit to Don't Panic's answer above and this answer which is providing array_column() alternative for PHP version < 5.5
// if array_column function don't exist, add array_column function
if (! function_exists('array_column')) {
function array_column(array $input, $columnKey, $indexKey = null) {
$array = array();
foreach ($input as $value) {
if ( ! isset($value[$columnKey])) {
trigger_error("Key \"$columnKey\" does not exist in array");
return false;
}
if (is_null($indexKey)) {
$array[] = $value[$columnKey];
}
else {
if ( ! isset($value[$indexKey])) {
trigger_error("Key \"$indexKey\" does not exist in array");
return false;
}
if ( ! is_scalar($value[$indexKey])) {
trigger_error("Key \"$indexKey\" does not contain scalar value");
return false;
}
$array[$value[$indexKey]] = $value[$columnKey];
}
}
return $array;
}
}
// sum up the values
$rest = array();
foreach($result as $key => $arr){
if(is_array($arr)) {
foreach($arr as $k => $val){
$rest[$k] = array_sum(array_column($result, $k));
}
}
}

count of duplicate elements in an array in php

Hi,
How can we find the count of duplicate elements in a multidimensional array ?
I have an array like this
Array
(
[0] => Array
(
[lid] => 192
[lname] => sdsss
)
[1] => Array
(
[lid] => 202
[lname] => testing
)
[2] => Array
(
[lid] => 192
[lname] => sdsss
)
[3] => Array
(
[lid] => 202
[lname] => testing
)
)
How to find the count of each elements ?
i.e, count of entries with id 192,202 etc
You can adopt this trick; map each item of the array (which is an array itself) to its respective ['lid'] member and then use array_count_value() to do the counting for you.
array_count_values(array_map(function($item) {
return $item['lid'];
}, $arr);
Plus, it's a one-liner, thus adding to elite hacker status.
Update
Since 5.5 you can shorten it to:
array_count_values(array_column($arr, 'lid'));
foreach ($array as $value)
{
$numbers[$value[lid]]++;
}
foreach ($numbers as $key => $value)
{
echo 'numbers of '.$key.' equal '.$value.'<br/>';
}
Following code will count duplicate element of an array.Please review it and try this code
$arrayChars=array("green","red","yellow","green","red","yellow","green");
$arrLength=count($arrayChars);
$elementCount=array();
for($i=0;$i<$arrLength-1;$i++)
{
$key=$arrayChars[$i];
if($elementCount[$key]>=1)
{
$elementCount[$key]++;
} else {
$elementCount[$key]=1;
}
}
echo "<pre>";
print_r($elementCount);
OUTPUT:
Array
(
[green] => 3
[red] => 2
[yellow] => 2
)
You can also view similar questions with array handling on following link
http://solvemyquest.com/count-duplicant-element-array-php-without-using-built-function/
The following code will get the counts for all of them - anything > 1 at the end will be repeated.
<?php
$lidCount = array();
$lnameCount = array();
foreach ($yourArray as $arr) {
if (isset($lidCount[$arr['lid']])) {
$lidCount[$arr['lid']]++;
} else {
$lidCount[$arr['lid']] = 1;
}
if (isset($lnameCount [$arr['lname']])) {
$lnameCount [$arr['lname']]++;
} else {
$lnameCount [$arr['lname']] = 1;
}
}
$array = array('192', '202', '192', '202');
print_r(array_count_values($array));
$orders = array(
array(
'lid' => '',
'lname' => '',
))....
$foundIds = array();
foreach ( $orders as $index => $order )
{
if ( isset( $foundIds[$order['lid']] ) )
{
$orders[$index]['is_dupe'] = true;
$orders[$foundIds[$order['lid']]]['is_dupe'] = true;
} else {
$orders[$index]['is_dupe'] = false;
}
$foundIds[$order['lid']] = $index;
}
Try this code :
$array_count = array();
foreach ($array as $arr) :
if (in_array($arr, $array_count)) {
foreach ($array_count as $key => $count) :
if ($key == $arr) {
$array_count[$key]++;
break;
}
endforeach;
} else {
$array_count[$arr] = 1;
}
endforeach;
Check with in_array() function.

recursive search an array on the basis of key in php

I need a php function that will recursively search an array on the basis of key I provided. and want to get an array as return output containing all the values those are mapped with the searched key.
For e.g.:
[Case] => Array
(
[0] => Array
(
[CASE_ID] => 2233
[CHECK_ID] => 57
[CLIENT_ID] => 78
)
[2] => Array
(
[CASE_ID] => 9542
[CHECK_ID] => 45
[CLIENT_ID] => 18
)
)
If I would pass this array and key CHECK_ID, then it should return me an array containing 57,45. Kindly ask if you need more explanation. Thanks in Advance.
Walking the array and chucking found keys into a new one:
function find_matches($array, $value) {
$found = array();
array_walk_recursive($array,
function ($item, $key) use ($value, &$found) {
if ($value === $key) {
$found[] = $item;
}
}
);
return $found;
}
see http://codepad.viper-7.com/dVmYOT
Have you also considered using find('list') with a fields condition restriction?
Just check each element, filter based on key, convert the outcome to an array:
$filter = function($c, $key) {
return $key === 'CHECK_ID';
};
$filtered = new CallbackFilterIterator(
new RecursiveIteratorIterator(
new RecursiveArrayIterator($array)
),
$filter
);
var_dump(iterator_to_array($filtered, false));
Result:
array(2) {
[0] =>
int(57)
[1] =>
int(45)
}
function array_rfind($find, $arr) {
$found = array();
foreach($arr as $key => $val) {
if($key == $find)
$found[] = $val;
elseif(is_array($val))
$found = array_merge($found, array_rfind($find, $val));
}
return $found;
}

need to search for values in each string of an array to construct another array

I have this array:
Array
(
[count] => 12
[6] => CN=G_Information_Services,CN=Users,DC=hccc,DC=campus
[7] => CN=WEBadmin,CN=Users,DC=hccc,DC=campus
[9] => CN=G_ISDept,CN=Users,DC=hccc,DC=campus
[10] => CN=STAFF,CN=Users,DC=hccc,DC=campus
)
and I want to create an array of values that consist of the value between the first CN= and , of each array value below.
I probably will have to loop thru the array above, do a regex search for the first occurrence of cn and the value that follows it
I am not sure what I am doing wrong.
I need the final result to be an array that resembles this:
array('G_Information_Services', 'WEBadmin', 'G_ISDept', 'STAFF');
Use preg_match on each of the array values to get only the first corresponding CN value.
$found = array();
foreach ($arr AS $values) {
if (preg_match('/CN=([^,]+),/',$values,$matches))
$found[] = $matches[1];
}
Output
Array
(
[0] => G_Information_Services
[1] => WEBadmin
[2] => G_ISDept
[3] => STAFF
)
Try this (not the most efficient way but it should work):
foreach ($array as $key => $value)
{
if (is_numeric($key))
{
$array[$key] = explode(',', $array[$key]);
$array[$key] = $array[$key][0];
$array[$key] = substr($array[$key], 3);
}
}
This gets the first value of CN= of each element of the array, it also ignores any DC= values.
$arr = array(
'count' => 12,
6 => 'CN=G_Information_Services,CN=Users,DC=hccc,DC=campus',
7 => 'CN=WEBadmin,CN=Users,DC=hccc,DC=campus',
9 => 'CN=G_ISDept,CN=Users,DC=hccc,DC=campus',
10 => 'CN=STAFF,CN=Users,DC=hccc,DC=campus'
);
$newArr = array();
foreach($arr as $key => $value)
{
if($key != 'count')
{
$temp = explode(',', $value);
foreach($temp as $item)
{
if(strpos($item, 'CN=') === 0)
{
$item = substr($item, 3 );
$newArr[] = $item;
break 1;
}
}
}
}
print_r($newArr);

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