PHP Regex preg_match won't work [closed] - php

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if (preg_match("/<response>(.*)<\/response>/iUms", '<response>CONNECTED_OK</response>', $mathces))
{
var_dump($matches);
}
I tried this, but at first i had a downloaded page with cURL with the subject I now have hard coded in. I have tried lots of other things but it always return $matches with null.


Try this:
if (preg_match("/<response>(.*)<\/response>/iUms", '<response>CONNECTED_OK</response>', $matches)) { var_dump($matches); }
You had $mathces instead of $matches

Related

Why can't I identify the false? [closed]

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Closed 4 years ago.
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I'm trying to fail on purpose... According to the documentation get_term_by will return false when nothing is found.
I issue:
$exiting_term = get_term_by('slug', sanitize_title("something"), 'non-existing-one');
Then I...
var_dump($existing_term);
The output from which is:
bool(false)
However, my code will not to into this block. Why is that?
if ($existing_term === false) {
/// NEVER GETS HERE.
}

You have a typo.
var_dump('exiting_term' == 'existing_term');
--> bool(false)

php preg_replace working only if there's ending space in string [closed]

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Closed 7 years ago.
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I have this pattern:
preg_replace_callback('##abc\((.*?)\)(.*?)#end.#is', ..
My template string:
$test = "#abc('test')<h1>test</h1>#end"; // not working
$test2 = "#abc('test')<h1>test</h1>#end "; // working
Why it doesn't work if there's no space after #end?

As #Rizier123 pointed out, this is the correct regex:
preg_replace_callback('##abc\((.*?)\)(.*?)#end#is', ..

What is the "returnto" in this piece of code [closed]

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header("Location: {$TBDEV['baseurl']}/login.php?returnto=" . urlencode($_SERVER["REQUEST_URI"]));
Is it a variable? PHP reserved word? something to do with HTML?

It's a $_GET parameter. When you submit the code, the page receiving it will be able to use $_GET['returnto'] to return you to the page you're currently on.
Take some time to learn about $_GET

Php help find where is syntax error [closed]

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foreach($db->fetch_array("SELECT id_categories FROM csn_categories_join_kartes where id_kartes===".$card['id']."") as $kat){
echo (kat['id_categories']);
}
table cols and values are all matched, something is wrong in this part of code
I tried adding $ before kat and using only one "=", sill doesnt work
NEW LINK
http://pastebin.com/RPK7vEaJ

this
where id_kartes===".$card['id']."
would be
where id_kartes=".$card['id']."
and missing $
echo $kat['id_categories'];
so full code :-
foreach($db->fetch_array("SELECT id_categories FROM csn_categories_join_kartes where id_kartes='".$card['id']."'") as $kat){
echo $kat['id_categories'];
}
best practice if you store your query result in a variable and loop over this variable.

foreach($db->fetch_array("SELECT id_categories FROM csn_categories_join_kartes where id_kartes=".$card['id']."") as $kat)

Regular Expression For indenfity google search pages [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 9 years ago.
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I would like to get the regular expression to identify whether a url is a google search home page or search results page .

You can use something like this :
(https?:\/\/www\.google\.(?:(?:com)|(?:co\.in)).*#q=.+)
For Google search result url.
Since in Google the searched word will be there , after q=
DEMO
Explanation:

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