a button for getting data from sql - php

Question

i have create two table in my databases, 1.loginacc (stay login information(LoginID , Password and Permission)2.borrow (have book that the login borrowed,userid)
below is the code: and i have get all the user id,beside every user that i get from database loginacc ,it has a button called 'get information'.when i click it,it will have order of" select * from borrow where userid = (the loginid that shown out )
<?php
$con = mysql_connect("127.0.0.1","root","password");
mysql_select_db("babytradeapps");
$sql = "Select LoginID , Password , Permission
from loginacc where Permission = 1 ";
$results = mysql_query($sql,$con);
echo "<tr><th>Admin</th></tr>";
echo "<table border=5 cellpadding=10>";
echo "<tr><th></th><th>ac</th><th>pw</th><th>per</th><th></th></tr>";
while($row = mysql_fetch_array($results)) {
echo "<tr><td><form action='searchtable.php' method='get'><button type='button' name='button2' value='button2'>get information</button></td>
<td><input type=text id='row0' name='row0' value='$row[0]' /></td><td><input type=text id='row1' name='row1' value='$row[1]' /></td>
<td><input type=text id='row2' name='row2' value='$row[2]' /></td><td><input type='submit' name='button' value='change' /></td></tr>";
}
echo "</table>";

Answer 1

Why don't you use anchor (link) to send the loginID rather than using button , it will be simple . As far as i've understood your problem , you can do it as below .
echo "<table border=5 cellpadding=10>";
echo "<tr><th></th><th>ac</th><th>pw</th><th>per</th><th></th></tr>";
while($row = mysql_fetch_array($results)) {
echo "<tr><td>
<a href='searchtable.php?lid=$row[0]'>get information</a></td>
<td><input type=text id='row0' name='row0' value='$row[0]' /></td><td><input type=text id='row1' name='row1' value='$row[1]' /></td>
<td><input type=text id='row2' name='row2' value='$row[2]' /></td><td><input type='submit' name='button' value='change' /></td></tr>";
}
echo "</table>";
Now in the next page i.e. searchtable.php, just get that id using GET method and execute the query . This should be somehow like ,
<?php
$loginId = $_GET['lid'];
$con = mysql_connect("127.0.0.1","root","password");
mysql_select_db("babytradeapps");
$sql = "Select * from borrow where userid = $loginId";
$results = mysql_query($sql,$con);
$final_result = mysql_fetch_array($results);
print_r($final_result);
// Manipulate view with the result
?>