Why is this PHP script not sending the e-mail? - php

Question

Note: E-Mail address removed for privacy purposes.
Whenever the form executes this script, it returns the success JSON array at the end, however, the e-mail is never received at the e-mail address specified.
<?php
if(empty($_POST['fullname']) || empty($_POST['phonenumber']) || empty($_POST['emailaddress']))
{
$response = array('status' => 0, 'txt' => 'Please verify all required fields are complete.');
echo json_encode($response);
die();
}
if(!(preg_match("/^[\.A-z0-9_\-\+]+[#][A-z0-9_\-]+([.][A-z0-9_\-]+)+[A-z]{1,4}$/", $_POST['emailaddress'])))
{
$response = array('status' => 0, 'txt' => 'Please Provide a Valid E-Mail Address.');
echo json_encode($response);
die();
}
$name = mysql_real_escape_string($_POST['fullname']);
$phonenumber = mysql_real_escape_string($_POST['phonenumber']);
$email = mysql_real_escape_string($_POST['emailaddress']);
$comments = mysql_real_escape_string($_POST['comments']);
$emailbody = 'Name: ' . $name . '
Phone Number: ' . $phonenumber . '
E-Mail Address: ' . $email . '
Comments: ' . $comments . ' ';
mail("example#example.com","New Consultation Request",$emailbody,"From: noreply#example.com");
$response = array('status' => 1, 'txt' => 'consultation-request-successful');
echo json_encode($response);
?>

Answer 1

You've never bothered connecting to the database, so mysql_real_escape_string() is going to be turning a boolean FALSE for failure - it REQUIRES an active connection to the DB to do its work.
That means your $name, $phonenumber, $email, $comments are all going to be boolean FALSE, and translated into an empty string when you build your mail text.
As well, using mysql escaping for a simple email is beyond utterly pointless. Email is not vulnerable to SQL injection attacks.