Hello I am using strtotime function to subtract time but I am not able to getting such true value of it.
$time = strtotime('00:00:00');
$time1 = strtotime('23:00:00');
$t = $time - $time1;
echo "diff".$t1 = date('H:i:s',$t);
But am getting $t = 2:00:00 Instead of i get 1:00:00
Any one have idea whats gone wrong ?
try to add strtotime() on changing format
date('H:i:s',strtotime($t));
$time = strtotime('00:10:00');
$time1 = strtotime('23:00:00');
$t = $time - $time1;
$hours = floor(($t - (($t/ 86400)* 86400)) / 3600);
$minutes = floor(($t - (($t/ 86400) * 86400) - ($hours * 3600))/60);
echo "".$hours.':'.$minutes;
its give you right diff. time for same days .
Related
I have two times: a starting time and the duration. I want to subtract the duration from the starting time. The time I read from an mysql db and is already formatted. My code:
$start= $row["start"]; //output is for e.g. 08:00:00
$dur = $row["duration"]; //output is for e.g. 01:00:00
$sub = $start - $dur;
// I want the output to be 07:00:00
// the result now is 7 and I got an error (non well formed numeric value)
Can someone help me?
Alternatively you can achieved like this
$date = "1970-01-01";
$start = $date." ".$row["start"];
$dur = $date ." ".$row["duration"];
$date1=date_create($start);
$date2=date_create($dur);
$diff=date_diff($date1,$date2);
echo $diff->format("%H:%I:%S");
$start= "08:00:00";
$dur = "01:00:00";
$diff = differenceInHours($start, $dur);
echo convertTime($diff);
function differenceInHours($startdate,$enddate){
$starttimestamp = strtotime($startdate);
$endtimestamp = strtotime($enddate);
$difference = abs($endtimestamp - $starttimestamp)/3600;
return $difference;
}
function convertTime($dec)
{
// start by converting to seconds
$seconds = ($dec * 3600);
// we're given hours, so let's get those the easy way
$hours = floor($dec);
// since we've "calculated" hours, let's remove them from the seconds variable
$seconds -= $hours * 3600;
// calculate minutes left
$minutes = floor($seconds / 60);
// remove those from seconds as well
$seconds -= $minutes * 60;
// return the time formatted HH:MM:SS
return lz($hours).":".lz($minutes).":".lz($seconds);
}
// lz = leading zero
function lz($num)
{
return (strlen($num) < 2) ? "0{$num}" : $num;
}
You should always save date in your database in the appropriate format. And not as a "already formated" value. Except in very specific case.
Anyway, to solve your problem you can do soemthing like this
$start = new DateTime('08:00:00');
$duration = new DateTime('01:00:00');
$interval = date_diff($start, $duration);
echo $interval->format('%H:%I:%S'); //ouput will be 07:00:00
I'm trying to get the difference between two date-times and return it as a minute. Date & Time are taken in date("Y-m-d H:i:s") format. But it seem i can't get it right. I did it
$time=date("Y-m-d H:i:s");
$time=date("2014-01-13 08:18:25");
$interval = $time->diff($login_time);
$elapsed = $interval->format(%i minutes);
echo $elapsed;
And This is showing a massage
"Call to a member function diff() on a non-object"
As I am not good enough with date formatting. So Please help me.
What is the way to go about this?
Try this:
$date1 = new DateTime('2013-01-13 04:10:58');
$datediff = $date1->diff(new DateTime('2013-09-11 10:25:00'));
echo $datediff->i;
For more details see this link : http://www.php.net/manual/en/book.datetime.php
Get difference is minutes between two dates:
$now = new DateTime;
$before = new DateTime('2014-01-10 08:18:25');
$diff = $now->diff($before);
$elapsed = $diff->days * 24 * 60 + $diff->h * 60 + $diff->i;
demo
Use the below code for getting time in all expected parameter.
$time1=date("Y-m-d H:i:s");
$time2=date("2014-01-13 08:18:25");
$seconds = strtotime($time1) - strtotime($start);
$year = floor(($seconds)/(60*60*24*365)); $months = floor($seconds /
86400 / 30 ); $week = floor($seconds / 604800); $days =
floor($seconds / 86400); $hours = floor(($seconds - ($days * 86400))
/ 3600); $minutes = floor(($seconds - ($days * 86400) - ($hours *
3600))/60); $seconds = floor(($seconds - ($days * 86400) - ($hours *
3600) - ($minutes*60)));
I'm addditioning time value of a schedule.
When The value go over 24:00 I'm begining to have a problem..
Here is a simple example of what i'm trying to do.
$now = strtotime("TODAY");
$time_1 = strtotime('08:00:00') - $now;
$total = $time_1 * 5;
$total = $total + $now;
echo date('H:i', $total);
The echo value is 16:00:00
But it should be 40:00:00
24:00:00 + 16:00:00 = 40:00:00
So I understand that this is 1 day and 16 hours.
How can I echo 40:00:00
Below is your example code working the way you want.
As others have mentioned, you have to do the math yourself for cases like this.
<?php
$now = strtotime("TODAY");
$time_1 = strtotime('08:00:00') - $now;
$total = $time_1 * 5;
$secs = $total%60;
$mins = floor($total/60);
$hours = floor($mins/60);
$mins = $mins%60;
printf("%02d:%02d:%02d", $hours, $mins, $secs);
You can't. date() is intended to produce VALID date/time strings. 40 is not something that would appear in a normal time string. You'll have to use math to generate that time string on your own:
$seconds = $total;
$hours = $seconds % 3600;
$seconds -= ($seconds * 3600);
$minutes = $seconds % 60;
$seconds -= ($seconds * 60);
$string = "$hours:$minutes:$seconds";
The date function is for dates and times, not durations. Since the time is never "40:00", it will never return that string.
You can look into using the DateTimeInterface to get what you want, but it might be simpler just to do the math yourself.
$seconds = $total;
$minutes = (int)($seconds/60);
$seconds = $seconds % 60;
$hours = (int)($minutes / 60);
$minutes = $minutes % 60;
$str = "$hours:$minutes:$seconds";
$time1 = "01:00";
$time2 = "04:55";
list($hours1, $minutes1) = explode(':', $time1);
$startTimestamp = mktime($hours1, $minutes1);
list($hours2, $minutes2) = explode(':', $time2);
$endTimestamp = mktime($hours2, $minutes2);
$seconds = $endTimestamp - $startTimestamp;
$minutes = ($seconds / 60) % 60;
$hours = round($seconds / (60 * 60));
echo $hours.':'.$minutes;
exit;
Outputs 4:55, should be 3:55 ?
Whats wrong here? If it is 01:00 and 02:00, it works fine, but not with the above?
Use floor instead of round...
Or just cast to integer.
$hours = (int) ($seconds / (60 * 60));
Too many calculations when PHP can do it for you with also reducing possibility of error
$time1 = Datetime::createFromFormat("h:i", "01:00");
$time2 = Datetime::createFromFormat("h:i", "04:55");
$diff = $time1->diff($time2);
var_dump($diff->format("%h %i"));
Output
string '3:55' (length=4)
You can also save yourself some time by using strtotime:
$time1 = strtotime("01:00");
$time2 = strtotime("04:55");
$seconds = $time2-$time1;
$minutes = ($seconds / 60) % 60;
$hours = floor($seconds / (60 * 60));
echo $hours.':'.$minutes;
As mentioned, using floor will produce the result you need:
Result
3:55
I have two dates, formated like "Y-m-d H:i:s". I need to compare these two dates and figure out the hour difference.
You can convert them to timestamps and go from there:
$hourdiff = round((strtotime($time1) - strtotime($time2))/3600, 1);
Dividing by 3600 because there are 3600 seconds in one hour and using round() to avoid having a lot of decimal places.
You can use DateTime class also -
$d1= new DateTime("06-08-2015 01:33:26pm"); // first date
$d2= new DateTime("06-07-2015 10:33:26am"); // second date
$interval= $d1->diff($d2); // get difference between two dates
echo ($interval->days * 24) + $interval->h; // convert days to hours and add hours from difference
As an addition to accepted answer I would like to remind that \DateTime::diff is available!
$f = 'Y-m-d H:i:s';
$d1 = \DateTime::createFromFormat($date1, $f);
$d2 = \DateTime::createFromFormat($date2, $f);
/**
* #var \DateInterval $diff
*/
$diff = $d2->diff($d1);
$hours = $diff->h + ($diff->days * 24); // + ($diff->m > 30 ? 1 : 0) to be more precise
\DateInterval documentation.
$seconds = strtotime($date2) - strtotime($date1);
$hours = $seconds / 60 / 60;
You can try this :
$time1 = new DateTime('06:56:58');
$time2 = new DateTime('15:35:00');
$time_diff = $time1->diff($time2);
echo $time_diff->h.' hours';
echo $time_diff->i.' minutes';
echo $time_diff->s.' seconds';
Output:
8 hours 38 minutes 2 seconds
The problem is that using these values the result is 167 and it should be 168:
$date1 = "2014-03-07 05:49:23";
$date2 = "2014-03-14 05:49:23";
$seconds = strtotime($date2) - strtotime($date1);
$hours = $seconds / 60 / 60;
$date1 = date_create('2016-12-12 09:00:00');
$date2 = date_create('2016-12-12 11:00:00');
$diff = date_diff($date1,$date2);
$hour = $diff->h;
This is because of day time saving.
Daylight Saving Time (United States) 2014 began at 2:00 AM on
Sunday, March 9.
You lose one hour during the period from $date1 = "2014-03-07 05:49:23" to
$date2 = "2014-03-14 05:49:23";
You can try this:
$dayinpass = "2016-09-23 20:09:12";
$today = time();
$dayinpass= strtotime($dayinpass);
echo round(abs($today-$dayinpass)/60/60);
You can use strtotime() to parse your strings and do the difference between the two of them.
Resources :
php.net - strtotime()