mysql_query() error (Invalid Query) in a searcher php [closed] - php

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this is a searcher program php with MySqL this give me a error, and i need a bit help on this...
This is the php Code:
<?php
if ($_POST['buscar'])
{
// Tomamos el valor ingresado
$buscar = $_POST['palabra'];
// Si está vacío, lo informamos, sino realizamos la búsqueda
if(empty($buscar))
{
echo "No se ha ingresado una cadena a buscar";
}else{
//Conexión a la base de datos
$servidor = "localhost"; //Nombre del servidor
$usuario = "root"; //Nombre de usuario en tu servidor
$password = "1234"; //Contraseña del usuario
$base = "db_maquinas"; //Nombre de la BD
$con = mysql_connect($servidor, $usuario, $password) or die("Error al conectarse al servidor");
mysql_select_db($base, $con) or die("Error al conectarse a la base de datos");
$sql= mysql_query("SELECT * FROM repuestos WHERE id LIKE '%$buscar%' AND descripcion LIKE '%$buscar%' ORDER BY id", $con) or die(mysql_error($con));
$result = mysql_query($sql, $con); //<----LINE 32!!!
// Tomamos el total de los resultados
if($result) { $total = mysql_num_rows($result); } else { die('Invalid query' . mysql_error($con)); }
echo "<table border = '1'> \n";
//Mostramos los nombres de las tablas
echo "<tr> \n";
while ($field = mysql_fetch_field($result)){
echo "<td>$field->name</td> \n";
}
echo "</tr> \n";
do {
echo "<tr> \n";
echo "<td>".$row["id"]."</td> \n";
echo "<td>".$row["descripcion"]."</td> \n";
echo "<td>".$row["cantidad"]."</td> \n";
echo "</tr> \n";
} while ($row = mysql_fetch_array($result));
echo "</table> \n";
echo "¡ No se ha encontrado ningún registro !";
}
}
?>
The error is --> Warning: mysql_query() expects parameter 1 to be string, resource given in C:\xampp\htdocs\maquinas2000\paginas\buscarepuestos.php on line 32
Invalid query {Line 32 is -> $result = mysql_query($sql, $con); }
i work with a Localhost xampp ofc, this give me a lot of troubles this code, i need only this and i'll finish 100% the work, so if anyone can give me the answer of this error i'll be very grateful for that, thx!

Answer 1

You have already executed the query. mysql_query return true or false and you are passing this return value again in mysql_query , make changes this :
$sql= "SELECT * FROM repuestos WHERE id LIKE '%$buscar%' AND descripcion LIKE '%$buscar%' ORDER BY id";// remove mysql_query from this line
$result = mysql_query($sql, $con);
Important : mysql_ is depricated use mysqli instead of that