Hide column if column is empty i.e. array element is empty - php

Question

I have an array such:
$prices = array();
Along with a MySQL query and fetch:
$query = "SELECT $columns FROM Prices WHERE `key` LIKE '$rows' LIKE '$AirportPU' AND rate LIKE '$rate'";
if($results = $db->query($query))
{
if($results->num_rows)
{
while($row = $results->fetch_object())
{
$prices[] = $row;
}
$results->free();
}
I've printed out the table using the following code: (I have removed some table columns)
<?php
if(!count($prices)) {
echo '<p>No results found for your current search. Use the inputs to the left to change the filters.</p>';
} else {
?>
<table>
<thead>
<tr>
<th>Location</th>
<th>City</th>
</tr>
</thead>
<tbody>
<?php
foreach ($prices as $p) {
?>
<tr>
<td> <?php echo $p->Location; ?> </td>
<td> £<?php echo $p->City; ?> </td>
</tr>
<?php
}
?>
</tbody>
</table>
<?php } ?>
I can return data from the MySQL query, and print this to the table. However, sometimes not all the columns need be printed as they have no values. I would like to hide these columns.
I have tried checking the array using:
print (isset($prices["City"])) ? "Exists</br>" : "Doesn't Exist</br>" ;
But that always returns "Doesn't Exist"
if (array_key_exists("City",$prices))
{
echo "Element exists!";
}
else
{
echo "Element does not exist!";
}
That also returns false.

Answer 1

You need to check it inside the foreach loop which you are executing.
print (isset($p->City)) ? "Exists</br>" : "Doesn't Exist</br>" ;

Answer 2

Check with
if(empty($price['City'] || $price['City'] == "")){
//Hide column
}