Parsing xml with simplexml_load - php

Question

I am trying to parse an xml but I get a problem while I am trying to fetch image url.
My xml is:
<entry>
<title>The Title</title>
<id>http://example.com/post/367327.html</id>
<summary>Some extra text</summary>
<link rel="enclosure" href="http://example.com/photos/f_0px_30px/image687.jpg" type="image/jpeg" length="" />
</entry>
So far I am using the code below to fetch the other data:
$url = "http://msdssite.com/feeds/xml/myxml.xml";
$xml = simplexml_load_file($url);
foreach($xml->entry as $PRODUCT)
{
$my_title = trim($PRODUCT->title);
$url = trim($PRODUCT->id);
$myimg = $PRODUCT->link;
}
How can I parse the href from this: <link rel="enclosure" href="http://example.com/photos/f_0px_30px/image687.jpg" type="image/jpeg" length="" />

Answer 1

Since it seems that your entries can contain several link tags, you need to check that the type attribute has the value image/jpeg to be sure to obtain a link to an image:
ini_set("display_errors", "On");
$feedURL = 'http://OLDpost.gr/feeds/xml/category-takhs-xatzhs.xml';
$feed = simplexml_load_file($feedURL);
$results = array();
foreach($feed->entry as $entry) {
$result = array('title' => (string)$entry->title,
'url' => (string)$entry->id);
$links = $entry->link;
foreach ($links as $link) {
$linkAttr = $link->attributes();
if (isset($linkAttr['type']) && $linkAttr['type']=='image/jpeg') {
$result['img'] = (string)$linkAttr['href'];
break;
}
}
$results[] = $result;
}
print_r($results);
Note that using simplexml like that (the foreach loop to find the good link tag) isn't very handy. It's better to use an XPath query:
foreach($feed->entry as $entry) {
$entry->registerXPathNamespace('e', 'http://www.w3.org/2005/Atom');
$results[] = array(
'title' => (string)$entry->title,
'url' => (string)$entry->id,
'img' => (string)$entry->xpath('e:link[#type="image/jpeg"]/#href')[0][0]
);
}

Answer 2

If that's the exact XML, actually there is no need for a foreach. Try this:
$xml = simplexml_load_file($url);
$my_title = (string) $xml->title;
$myimg = (string) $xml->link->attributes()['href']; // 5.4 or above
echo $myimg; // http://example.com/photos/f_0px_30px/image687.jpg

Answer 3

Try:
foreach($xml->entry as $PRODUCT)
{
$my_title = trim($PRODUCT->title[0]);
$url = trim($PRODUCT->id[0]);
$myimg = $PRODUCT->link[0];
}