Get multiple rows from foreach - php

Question

So on my project I have posts. And basically they include the post time and post content. Now here's my issue, I can only figure out how to retrieve one row instead of post content and post time. Here's my code
$posts = array();
while($row = $stmt->fetch(PDO::FETCH_ASSOC)){
$posts[] = $row['post_content'];
}
And how I'm returning
<?php
foreach($posts as $post) {
$post;
?>
<div class="content">
<div class="post">
<h1 class="message">
<?php
echo $post;
?>
</h1>
<p class="time">4 minutes ago</p>
</div>
</div>
<?php
}
?>
I've tried
$posts = array();
$time = array();
while($row = $stmt->fetch(PDO::FETCH_ASSOC)){
$posts[] = $row['post_content'];
$time[] = $row['post_time'];
}
But that doesn't work. I've ran out of ideas. Any help would be great. Also if there is a cleaner way to do this, it would be nice knowing how. Thanks

Answer 1

You can use nested arrays:
$posts = array();
while($row = $stmt->fetch(PDO::FETCH_ASSOC)){
$posts[] = array(
'post_content' => $row['post_content'],
'time' => $row['post_time']
);
}
Then your echo needs to reference $post['post_content'] and $post['time'].

Answer 2

Your're using $post = value, this will overwrite your value each time, try:
array_push($posts, $row['post_content']);
inside of your while loop

Answer 3

You could simply generate your HTML within the while loop. Otherwise, you might like to populate your posts array directly with PDOStatement::fetchAll -
$posts = $stmt->fetchAll();
and use it as you have been, e.g -
<?php foreach($posts as $post): ?>
<article>
<h1> <?php echo $post['title']; ?> </h1>
<p> <?php echo $post['content']; ?> </p>
</article>
<?php endforeach; ?>