Form not posting data - php

JSfiddle: http://jsfiddle.net/NqaZ2/4/
I have two forms on a page, One posts fine but the other does not post anything:
<form id="comment-oa" action="" method="post">
<input type="hidden" name="key" value="coa" />
<input type="hidden" name="action" value="" />
<input type="hidden" name="value" value="" />
</form>
Its being submitted through jquery:
$('a[data-role="fc-delete"]').click(function(){
var id = $(this).parent().parent().parent().parent().attr('id'),
spl = id.split("-");
$('#comment-oa input[name="action"]').attr('value', "delete");
$('#comment-oa input[name="value"]').attr('value', spl[0]);
$('#comment-oa').submit();
});
and I'm simply just doing print_r($_POST) at the moment, but it just comes up with Array ( ).
I've checked whether jQuery puts values in and it does (firefox inspector pic):
EDIT:
The other form:
<form action="" method="post">
<textarea name="comment"></textarea>
<input type="hidden" name="reply-id" value="" />
<input type="submit" value="Post comment" />
<input type="button" value="cancel" style="display: none;" />
</form>

Update:
$('a[data-role="fc-delete"]').click(function(){
var id = $(this).parent().parent().parent().parent().attr('id'),
spl = id.split("-");
$('#comment-oa input[name="action"]').attr('value', "delete");
$('#comment-oa input[name="value"]').attr('value', spl[0]);
$('#comment-oa').submit();
});
to
$('a[data-role="fc-delete"]').click(function(e){
e.preventDefault();
var id = $(this).parent().parent().parent().parent().attr('id'),
spl = id.split("-");
$('#comment-oa input[name="action"]').attr('value', "delete");
$('#comment-oa input[name="value"]').attr('value', spl[0]);
$('#comment-oa').submit();
});
Your using a link without preventing it form well - linking.

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When submitted it will be http://example.com/?zip=ZIPCODE
What I am looking to do it add an additional piece so it will be http://example.com/?zip=234&country=usa
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Try:
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Does a jquery event overwrite the submit action?

I have one form with a few submit buttons. I want to submit the form via POST to itself to process the filled out form fields... does the jquery override the submit?
$('#myButton').click('myAction') <!-- not actual code, just for the idea -->
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you can use something like this:
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<input type="text" name="other" value="">
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js:
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sample jsfiddle

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html form - how to call different php pages based on the button selected

Problem: How to make an HTML Form call different php pages from the action based on what button is pushed?
The code below is the solution I have now, but I figure there must be a better way to do this then creating multiple forms on the page?
<html>
<body>
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<input type="hidden" name="entry_id" value="">
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document.sample.submit();
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you might choose the page to go from a dispatcher, it's an extensible and robust solution:
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<form action="dispatcher.php" method="POST">
<input type="radio" name="myOption" value="register" />
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</form>
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// validate possible actions
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Form with two button submit with different value

<form action="here.php" method="POST">
<input type="text" name="text">
<div id="one">
<input type="hidden" name="aaa" value="one">
<input type="submit" value="Send">
</div>
<div id="two">
<input type="hidden" name="aaa" value="two">
<input type="submit" value="Send">
</div>
</form>
Now if i click on Send of div ONE or div TWO i have always in $_POST['aaa'] = 'two';
Is possible make one form with two submit with different values?
If i click on div one submit i would like reveice $_POST['aaa'] = 'one' and if i click on div two submit i would like receive $_POST['aaa'] = 'two'.
How can i make it?
I can use for this PHP and jQuery.
EDIT:
I dont want create two form - i dont want showing two many times <input type="text" name="text">
EDIT: maybe i can instead button submit ? but how?
It seems that what you actually want to do is have a value in each of the buttons, see this, for example:
<form action="demo_form.asp" method="get">
Choose your favorite subject:
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</form>
You'd need two different forms:
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<form ...>
<input type="hidden" name="aaa" value="one">
<input type="submit" value="Send">
</form>
</div>
<div id="two">
<form ...>
<input ...>
<input ...>
</form>
</div>
Standard practice is that when two fields have the exact same name, to use only the LAST value encountered in the form and submit that.
PHP does have a special-case notation (name="aaa[]") to allow submitting multiple values with the same name, but that wouldn't help you here, as that'd submit ALL of the aaa values, not just the one closest to the submit button.
HTML form:
<form ...>
<input type="text" name="textfield">
<div id="one">
<input type="hidden" name="one_data" value="aaa" />
<input type="submit" name="submit_one" value="Submit" />
</div>
<div id="two">
<input type="hidden" name="two_data" value="bbb" />
<input type="submit" name="submit_two" value="Submit" />
</div>
</form>
server-side:
if (isset($_POST['submit_two'])) {
$data = $_POST['two_data'];
} else if (isset($_POST['submit_one'])) {
$data = $_POST['one_data'];
} else {
die("Invalid submission");
}
Instead of showing two submit button, you can show a radio list with two options and one submit button.
Try this:
in html-
<input id="PreviousButton" value="Previous" type="submit" />
<input id="NextButton" value="Next" type="submit" />
<input id="Button" name="btnSubmit" type="hidden" />
in jOuery-
$("#PreviousButton").click(function () {
$("#Button").val("Previous");
});
$("#NextButton").click(function () {
$("#Button").val("Next");
});
then you can see in the form results - what "Button" contains.

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