i'm trying to do a system to check if the member attended to the meeting.
I will check it using his ID, so, i a form to input his ID(it will be read by a bar code reader that the id will be the bar code, everything will be in a card), but if the member forget his card, should have another way to find his ID, so i'm using a modal open a form, so can find his name and pass his ID to the form.
On the modal, i'm using ajax to get dinamically his name (and his id on a checkbox), it works properly, but i cant take the checkbox value and pass it into the ID FORM.
Thats my code.
<form method="post" enctype="multipart/form-data" id="attendedForm" name="formPresenca">
<fieldset>
<label>
<span>ID</span>
<input type="text" name="id" id="alvo" />
</label>
<input type="hidden" name="acao" value="enviar" />
Seach Manually </fieldset>
</form>
JS:
$(function(){
$("a#popup").click(function(){
$.modal('<form method="post" enctype="multipart/form-data"><fieldset><label><span>Name</span><input type="text" name="Name" id="id" /></label></fieldset><div id="recebe_dados"></div></form>', {
overlayId: 'contact-overlay'
});
$("#id").on('keyup', function(){
var nome = $(this).val();
$.post("../scripts/get-name.php",
{name:name},
function(value){
$("#get_data").html(value);
});
//Dont shows me anything on the console.
$("#Checkbox").click(function(){
console.log($('#Checkbox:checked').val());
});
});
});
});
Get-value.php
$get = $_POST['nome'];
$mysql = mysql_query("SELECT id, name FROM members WHERE name LIKE '%$get%'");
while($res = mysql_fetch_array($mysql)){
echo '<input type="checkbox" name="id" value="'.$res['id'].'" id="Checkbox">'.$res['nome'];
}
I'm using Simple modal.
Since your while loop could possibly create duplicate IDs -- invalid HTML -- use the following instead:
$(document).on("click", ".Checkbox", function(){
console.log( this.value );
});
And:
echo '<input type="checkbox" name="id" value="'.$res['id'].'" class="Checkbox">'.$res['nome'];
And, this should be outside the keyup callback but inside DOM ready.
Related
I've been building a mail form that is supposed to pass the information into a php document that handles sanitization and mailing, but I didn't want it to refresh so i decided to use JQuery and AJAX. I'm fairly new to JQuery and haven't used any AJAX before so I am a bit of a rookie when it comes to this...
Even though I have the .submit(function(e){e.preventDefault();}); it still submits the ordinary way and gives an error when it can't find film_mail in the PHP. Which means that it isn't stopping the submit and isn't passing the code to the PHP.
I've tested with alerts and the JQuery works in to the if() but after that some thing goes wrong.
Here is the code that causes the issue (some of the classes and ids are in swedish but that shouldn't cause an error...)
HTML
<div id="film" class="hidden" >
<form id="film_form" action="formular-send.php" method="post">
<input id="film_mail" type="text" name="mail" placeholder="Mail adress">
<input id="film_nr" type="number" name="nr" min="1">
<input id="film_antal" type="number" name="antal" min="1">
<input id="film_namn" type="text" name="namn" placeholder="Namn">
<input id="film_adress" type="text" name="adress" placeholder="Adress">
<input id="film_ort" type="text" name="ort" placeholder="Ort">
<input id="film_postnr" type="text" name="postnr" placeholder="Postnummer">
<textarea id="film_medelande" name="medelande" placeholder="Medelande"></textarea>
<button id="film_submit" type="submit" name="submit">Skicka</button>
<div class="error-mesage" ></div>
</form>
</div>
JQuery
$(document).ready(() => {
var emne = $('#emneid').val();
if (emne == 'film') {
$('#film_form').submit(function(e) {
e.preventDefault();
var mail = $('#film_mail').val();
var nr = $('#film_nr').val();
var antal = $('#film_antal').val();
var namn = $('#film_namn').val();
var adress = $('#film_adress').val();
var ort = $('#film_ort').val();
var postnr = $('#film_postnr').val();
var medelande = $('#film_medelande').val();
var submit = $('#film_submit').val();
$.post('formular-send.php', {
film_mail: mail,
film_nr: nr,
film_antal: antal,
film_namn: namn,
film_adress: adress,
film_ort: ort,
film_postnr: postnr,
film_medelande: medelande,
film_submit: submit,
emne: emne
});
// I heard that .load() had been removed in 3.0 so i tried to use $.post() because I thougt that might work but it sadly didn't...
// but I kept the .load() incase it'd be useful
/*$('#film_form').load('formular-send.php', {
film_mail: mail,
film_nr: nr,
film_antal: antal,
film_namn: namn,
film_adress: adress,
film_ort: ort,
film_postnr: postnr,
film_medelande: medelande,
film_submit: submit,
emne: emne
});*/
});
} else {
}
})
PHP
<?php
$filmmail = $_POST['film_mail'];
?>
If there is anything else that is needed i'd be happy to post it to.
I think $('#emneid').val() returns something different than 'film' and your listener is never attached.
Can you please double check the returned value of $('#emneid').val();
In addition of other comments, I think you need to add the correct name for you button or your PHP form will not work.
<?php
$filmmail = $_POST['film_mail']; //for the moment your need to put $_POST['mail'] because your button is named mail instead of film_mail
?>
Please also take care in production / later use, don't use directly $_POST or your code will be vulnerable from some SQL injection and so on. Take a look at htmlspecialchars function.
Edit :
I think you can just use HTML form and php to post your data, without posting it via JS/Jquery. If you want to have some data validation before sending it, you can just call an event before submit like described in this post : (Validate form before submit jquery)
I think you maybe have a problem with your selector to trigger the function, I don't know the submit function but maybe try with on('submit') or at least it will work with on('click').
$(document).on('click', '#film_submit button[type=submit]', function(e) {
var isValid = $(e.target).parents('form').isValid();
if(!isValid) {
e.preventDefault(); //prevent the default action
}
});
<button> does not have attribute type, but <input> has, try change <button> to <input>
UPD
Where is the tag with id of #emneid?
Try this. Please replace your HTML with my HTML code.
<div id="film" class="hidden" >
<form id="film_form" action="formular-send.php" method="post">
<input id="film_mail" type="text" name="film_mail" placeholder="Mail adress">
<input id="film_nr" type="number" name="film_nr" min="1">
<input id="film_antal" type="number" name="film_antal" min="1">
<input id="film_namn" type="text" name="film_namn" placeholder="Namn">
<input id="film_adress" type="text" name="film_adress" placeholder="Adress">
<input id="film_ort" type="text" name="ort" placeholder="Ort">
<input id="film_postnr" type="text" name="film_ort" placeholder="Postnummer">
<textarea id="film_medelande" name="film_medelande" placeholder="Medelande"></textarea>
<button id="film_submit" type="submit" name="submit">Skicka</button>
<div class="error-mesage" ></div>
</form>
</div>
Can I submit value of <select> in php form without having submit button?
In my html/php code I am using two form or we can say two <select> as you can see in coding. In the second <select>(sub category) I want to use value of first <select>(main category) so that it can show me sub category of main <select>. but I am getting confused, how to do this on a single page without using js.
See my code:
<body>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="post">
main course name <select name ="bcate" ><option value=''>choose</option><?php $auth->cmaster_array(); ?></select>
</form>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="post">
sub course name <select name ="sbcate" ><option value=''>select sub course</option><?php $auth->clmaster_array($frsbct); ?></select>
section name <input type="text" name="cname" required/>
remarks <input type="text" name="remarks" required/>
<input type="submit" name="section_master" value="Submit">
</form>
</body>
The thing you've asked that , You need value of first select input for second input values.
You can do this only by using jQuery without submitting form.
write change event of first select input box.
then send data to your server by jQuery ajax.
and then fill the second input box received from ajax
Code :
// To get value of select box
$('#select_box_id').change(function()
{
var select_box_one_value = $(this).val();
});
$.ajax
({
type: "POST",
url: HOST + "/path/to_your_controller_function",
data: 'data_of_select_box='+select_box_one_value,
cache: false,
success: function(msg)
{
}
});
using this , your controller will get the value of select box value and then return data from there , and you will receive that data in msg variable.
You can submit the form using javascript.
You can use this code to submit the form
document.getElementById("[ur form id should be here]").submit();
You can use following code
<form id="jsform" action="whatever you want">
// input fields
</form>
<script type="text/javascript">
document.getElementById('jsform').submit();
</script>
I have a table that lists my students.. and the License Number Column will either shown the license number or if there is no number in the DB it will show a textbox..
Upon submit (note: no submit button, to keep it need i just press return)
The results from the PHP script will be shown via Ajax.
My complete code is here.
http://pastebin.com/9k0EKXA9
Here is the code within the license number cell on each row:
<td><?php // check if license number exists.
if($row['license_no'] == '')
{
//show form.
?>
<form method="POST" id="license_no_update"">
<input type="text" name="license_no" value="License Number" />
<input type="hidden" value="<?php echo $row['student_id']; ?>" name="student_id" />
</form>
<div id="output"></div>
<?php
}else{
//show license no.
echo $row['license_no'];
}
?></td>
Here Is the JQUERY
<script type="text/javascript">
$(document).ready(function() {
$("#license_no_update").submit(function() {
var license_no_update = $(this).serialize();
$.post('license_update.php', license_no_update, function(data) {
// We not pop the output inside the #output DIV.
$("#output").html(data);
});
return false;
});
});
</script>
The problem i am having, even after searching google many times..
I know i have to have a new form & element id for each row of the table.
but even when i do have those, i do not know how to get JQUERY to find that unique number..
currently with the code attached if i submit on the first row of the table, the correct results are displayed, if i submit on any other row nothing is displayed..
I hope that all makes sense.
Regards
Aaron
Use .find() to find the value of the hidden input within the clicked form. Notice the use of $(this) which is the form itself, and then you can narrow down the input by it's name, since you know the name.
However, it is unclear what you want to do with the id so I left that up to you.
$("#license_no_update").submit(function() {
var studentID = $(this).find("input[name='student_id']").val();
var license_no_update = $(this).serialize();
$.post('license_update.php', license_no_update, function(data) {
// We not pop the output inside the #output DIV.
$("#output-" + studentID).html(data);
});
return false;
});
Update:
Here is one way of creating unique ID's for each output:
if($row['license_no'] == '')
{
//show form.
?>
<form method="POST" id="license_no_update"">
<input type="text" name="license_no" value="License Number" />
<input type="hidden" value="<?php echo $row['student_id']; ?>" name="student_id" />
</form>
<div id="output-<?php echo $row['student_id']; ?>"></div>
<?php
}else{
//show license no.
echo $row['license_no'];
}
Is it possible?
I want a user to post an array full of 1-5 pieces of data.
At first there would be only one text field on show, but on clicking a 'plus' icon next to it, it would create another text field below it for more user input.
I would also want to have a delete icon next to text boxes 2-5, to remove them if necessary.
My JQuery knowledge is limited, and I can work out how to append text boxes to a list, but not to keep track of them/delete them. Ideally I would also want to pass them as an array to php, so I can easily loop through them.
<input type="text" size="15" maxlength="15" name="1"><img src="add.png" onclick="add();">
<!-- Below is hidden by default, and each one shows on click of the add image -->
<input type="text" size="15" maxlength="15" name="2"><img src="delete.png" onclick="delete(2);">
<input type="text" size="15" maxlength="15" name="3"><img src="delete.png" onclick="delete(3);">
<input type="text" size="15" maxlength="15" name="4"><img src="delete.png" onclick="delete(4);">
<input type="text" size="15" maxlength="15" name="5"><img src="delete.png" onclick="delete(5);">
jQuery clone() is very handy for this. A small example how it could be done (working example on jsfiddle)
<ul>
<li><input type="text" name="textbox[]" /></li>
</ul>
<input type="button" id="addTextbox" value="Add textbox" />
<script type="text/javascript">
$(function(){
$('#addTextbox').click(function(){
var li = $('ul li:first').clone().appendTo($('ul'));
// empty the value if something is already filled in the cloned copy
li.children('input').val('');
li.append($('<button />').click(function(){
li.remove();
// don't need to check how many there are, since it will be less than 5.
$('#addTextbox').attr('disabled',false);
}).text('Remove'));
// disable button if its the 5th that was added
if ($('ul').children().length==5){
$(this).attr('disabled',true);
}
});
});
</script>
For the server-side part, you could then do a foreach() loop through the $_POST['textbox']
As long as you give each text box a name like "my_input[]", then when the form is submitted, PHP can get the answer(s) as an array.
$_REQUEST['my_input']; would be an array of the values stored in each text box.
Source: Add and Remove items with jQuery
Add
Remove
<p><input type="text" value="1" /></p>
<script type="text/javascript">
$(function() { // when document has loaded
var i = $('input').size() + 1; // check how many input exists on the document and add 1 for the add command to work
$('a#add').click(function() { // when you click the add link
$('<p><input type="text" value="' + i + '" /></p>').appendTo('body'); // append (add) a new input to the document.
// if you have the input inside a form, change body to form in the appendTo
i++; //after the click i will be i = 3 if you click again i will be i = 4
});
$('a#remove').click(function() { // similar to the previous, when you click remove link
if(i > 1) { // if you have at least 1 input on the form
$('input:last').remove(); //remove the last input
i--; //deduct 1 from i so if i = 3, after i--, i will be i = 2
}
});
$('a.reset').click(function() {
while(i > 2) { // while you have more than 1 input on the page
$('input:last').remove(); // remove inputs
i--;
}
});
});
</script>
You will need to create DOM elements dynamically. See how it is done for example in this question. Notice that
document.createElement
is faster then using jquery's syntax like
$('<div></div>')
Using that technick, you could create inputs like
<input name="id1"/>
<input name="id2"/>
<input name="id3"/>
<input name="id4"/>
<input name="id5"/>
On submitting your form you'll get all them in your query string like
...id1=someval1&id2=someval2&...
Having that, you could process this query as you want on server side.
<form method="POST" id="myform">
<input />
Add textbox
<input type="submit" value="Submit" />
</form>
<script type="text/javascript">
$(document).ready(function(){
$('#add_textbox').click(function(){
var form=$(this).closest('form');
var count=form.find('input').length();
form.append('<div class="removable_textbox"><input />delete</div>');
$('.delete_input').click(function(){
$(this).find('.removable_textbox').remove();
return false;
});
return false;
});
$('#myform').submit(function(){
var i=1;
$(this).find('input').each(function(){
$(this).attr('name','input-'+i);
i++;
})
});
});
</script>
<?php
if(isset($_POST['input-1'])){
$input_array=$_POST;
}
?>
something like this?
I wrote a litte jQuery plugin called textbox. You can find it here: http://jsfiddle.net/mkuklis/pQyYy/2/
You can initialize it on the form element like this:
$('#form').textbox({
maxNum: 5,
values: ["test1"],
name: "textbox",
onSubmit: function(data) {
// do something with form data
}
});
the settings are optional and they indicate:
maxNum - the max number of elements rendered on the screen
values - an array of initial values (you can use this to pass initial values which for example could come from server)
name - the name of the input text field
onSubmit - onSubmit callback executed when save button is clicked. The passed data parameter holds serialized form data.
The plugin is not perfect but it could be a good start.
I have the scriptaculous autocompleter working. It pops up the data and I can select it, but it does not transfer the ID number in the form I'm using. I just cannot get the ID number. I can show the ID number on the screen using the following command:
alert (li.id);
I have used the following but no luck:
document.getElementById('inv_id').value=li.id;
and
$("#inv_id").val(li.id);
How do I pass that ID number to a value in the form? Here is the form code...
<form action="page2.php" method="post" name="Add_Form">
<input type="hidden" name="inv_id" value="0">
<input type="text" id="autocomplete" name="autocomplete_parameter"/>
<div id="autocomplete_choices" class="autocomplete"></div>
</form>
<script type="text/javascript">
new Ajax.Autocompleter("autocomplete", "autocomplete_choices", "ajax_inv.php", {
afterUpdateElement : getSelectedId
});
function getSelectedId(text, li) {
alert (li.id);
document.getElementById('inv_id').value=li.id;
or
$("#inv_id").val(li.id);
}
</script>
Where is the inv_id field? Make it a hidden input if you don't have it existing already, then document.getElementById('inv_id').value=li.id; should work