PHP post jQueryUI menu selection - php

Question

I have a jQuery UI menu inside a form and I would like to be able to pass the tag attribute as value for my POST in PHP.
Does anybody know how I can do that? I only know how to get that value via JavaScript.
Example:
<form id="cities" name="cities">
<ul id="menu" style="position:absolute;">
<li>Lodon</li>
<li>Madrid</li>
<li>Lyon</li>
<li>Paris</li>
</ul>
... other input fields...
... a submit button
</form>
I want to POST/GET the tag to the next PHP page.
<?php
// How can I get the tag or just the menu selection value (Lyon, Paris, etc)
and save it to a variable in PHP?
// I'm more interested in the tag
?>
Thanks in advance for your help,
Cristina

Answer 1

DEMO
JS code:
$(function() {
$( "#menu" ).menu({
select:function(event, ui){
console.log(ui.item);
alert("Selected tag = "+$(ui.item).find('a').attr('tag'));
$('#tag').val($(ui.item).find('a').attr('tag'));
}
});
});
HTML:
<form id="cities" name="cities">
<ul id="menu" >
<li>Lodon</li>
<li>Madrid</li>
<li>Lyon</li>
<li>Paris</li>
</ul>
<br style="clear:both;">
Selected menu tag (hidden field):
<input type="text" id="tag" name="tag">
</form>