I am passing single base64 string as of now,but Now I need to pass multiple base64 string and sent through PHP script to the server.
as of now my code send only single data
$imagebase64 //it contains base64 array like -['data:image/jpeg;base64,/9j/4A','data:image/jpeg;base64,/9j/4A']
$("#downloadAll").click(function () {
$.ajax({
type: "POST",
url: "imageUpload.php",
data: {
// Sending single as of now
base64Img: "data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD…1jSchh2MkeFK5Anv7fbTv5SKFqOFdOvm764mRVLQgtO8RoP/Z",
},
contentType: "application/octet-stream",
error: function (err) {
console.log("There was an error. Try again please!", err);
},
success: function (msg) {
console.log(msg);
},
});
});
PHP Script
$base64string = $_POST['data'];
$uploadpath = 'image-cropper';
$parts = explode(";base64,", $base64string);
$imageparts = explode("image/", #$parts[0]);
$imagetype = $imageparts[1];
$imagebase64 = base64_decode($parts[1]);
$file = $uploadpath . uniqid() . '.jpeg';
file_put_contents($file, $imagebase64);
After Updated Code as suggested-
Notice: Undefined index: data in /var/www/html/image-cropper/imageUpload.php on line 1
and empty array() posted to upload.php
Ajax call:
$("#downloadAll").click(function () {
var imagebase64 = "<?= $imagebase64 ?>";
$.ajax({
type: "POST",
url: "imageUpload.php",
data: { imagesBase64: JSON.stringify(imagesBase64) },
contentType: "application/json; charset=utf-8",
error: function (err) {
console.log("There was an error. Try again please!", err);
},
success: function (msg) {
console.log(msg);
},
});
});
PHP:
$base64string = $_POST['data'];
$uploadpath = 'image-cropper';
$parts = explode(";base64,", $base64string);
$imageparts = explode("image/", #$parts[0]);
$imagetype = $imageparts[1];
$imagebase64 = base64_decode($parts[1]);
$file = $uploadpath . uniqid() . '.jpeg';
file_put_contents($file, $imagebase64);
As I understand by your first code - your array has base64 data which is already in strings so no need to convert it again.
$("#downloadAll").click(function () {
$.ajax({
type: "POST",
url: "imageUpload.php",
data: { data: imagesBase64 },
cache: false,
error: function (err, data) {
console.log("There was an error. Try again please!" + data, err);
},
success: function (data) {
console.log(data);
},
});
});
As I saw your PHP script has a lot of issues, it was made only to handle a single item, you need to iterate over the array too.
$data = ($_POST['data']);
foreach($data as $base64_string ){
$filename_path = md5(time().uniqid()).".jpeg"; //use png or jpg if required
$base64_string = str_replace('data:image/jpeg;base64,', '', $base64_string);
$base64_string = str_replace(' ', '+', $base64_string);
$decoded = base64_decode($base64_string);
//defining path
file_put_contents("image-cropper".$filename_path,$decoded);
}
Need to save some big data to file on server
"/php/test.php":
<?php if(!empty($_POST['data'])){
$data = $_POST['data'];
$fname = mktime() . ".txt";
$file = fopen("upload/" .$fname, 'w');
fwrite($file, $data);
fclose($file);
}
?>
jquery:
var data = 'foo bar';
$.ajax({
url: 'php/test.php',
type: 'POST',
data: { data: data },
success: function(result) {
alert('the data was successfully sent to the server');
}
});
result:
405 (HTTP method POST is not supported by this URL)
what's the problem?
I am trying to upload an image through ajax and needs to get the image URL as response.
code below..
$(".filupldt").on('change',function(){
var file_data=$(this).prop("files")[0];
var form_data=new FormData();
form_data.append("file",file_data);
form_data.append("type",$(this).prev().prev().val());
form_data.append("primerkey",$(this).prev().val());
var element = this;
$.ajax({
type:'POST',
mimeType: 'multipart/form-data',
url:'includes/dealerimg.settings.php?operation=savedealerimgeqtype',
dataType:'json',
async:false,
processData: false,
cache: false,
contentType: false,
data:form_data,
success:function(response){
console.log(response);
//$(element).parent().prev().prev().attr('src',response);
},
});
});
PHP Ajax function
$createthumb = new createthumb();
$todburl = $this->url;
$ajaxtype = $_POST['type'];
$uploads_dir = "../assets/equipmenttype/";
$uniid = uniqid();
$now =date('Y-m-d H:i:s');
$pkid = $_POST['primerkey'];
$ext =pathinfo($_FILES['file']['name'], PATHINFO_EXTENSION);
$filename = $pkid."_".$DealerID."_dealerupdate";
$thumbnamer = $pkid."_".$DealerID."_thumb_dealerupdate_".$uniid.".".$ext;
$tmpname = $_FILES['file']['tmp_name'];
$imagename = $_FILES['file']['name'];
$loc_thumb = $uploads_dir.$thumbnamer;
$createthumb->create_thumb_with_ratio($tmpname,300,300,$loc_thumb); //CREATING THUMB
$createthumb->upload_original(1,$filename,$imagename,$tmpname,$uploads_dir);//for upload original
$thumnametodb = $thumbnamer;
$orinametodb = $filename."_".$imagename;
$data = ['dddd'=>$todburl."assets/equipmenttype/".$thumbnamer];
header('Content-Type: application/json');
echo json_encode($data);
This function working perfectly and creating thumb in my required folder.
But this is an ajax page and I want to show the image name as response.
In this case the ajax response is like below attached image.
How can i solve this issue ?
Thanks
You said that you want to show the image name as response :
Then just
echo $_FILES['file']['name'];
then in your script you get the image name as response with :
success:function(response){
console.log('Image Name = '+response);
}
Your current response is JSON representation (json_encode($data)) & not the image's name.
Probably some output is braking the response data. To be sure that nothing prints on the response page try putting ob_start() and ob_end_clean()
ob_start();
//...
// your code here
//...
$data['dddd'] = $todburl."assets/equipmenttype/".$thumbnamer;
ob_end_clean();
echo json_encode($data);
I'm trying to capture audiorecorder (https://github.com/cwilso/AudioRecorder) and send the blob through Ajax a php file, which will receive the blob content and create the file(the wave file in this case).
Ajax call:
audioRecorder.exportWAV(function(blob) {
var url = (window.URL || window.webkitURL).createObjectURL(blob);
console.log(url);
var filename = <?php echo $filename;?>;
$.ajaxFileUpload({
url : "lib/vocal_render.php",
secureuri :false,
dataType : blob.type,
data: blob,
success: function(data, status) {
if(data.status != 'error')
alert("boa!");
}
});
});
and my php file (vocal_render.php):
<?php
if(!empty($_POST)){
$data = implode($_POST); //transforms the char array with the blob url to a string
$fname = "11" . ".wav";
$file = fopen("../ext/wav/testes/" .$fname, 'w');
fwrite($file, $data);
fclose($file);
}?>
P.S:I'm newbie with blobs and ajax.
Thanks in advance.
Try uploading the file as form data
audioRecorder.exportWAV(function(blob) {
var url = (window.URL || window.webkitURL).createObjectURL(blob);
console.log(url);
var filename = <?php echo $filename;?>;
var data = new FormData();
data.append('file', blob);
$.ajax({
url : "lib/vocal_render.php",
type: 'POST',
data: data,
contentType: false,
processData: false,
success: function(data) {
alert("boa!");
},
error: function() {
alert("not so boa!");
}
});
});
.
<?php
if(isset($_FILES['file']) and !$_FILES['file']['error']){
$fname = "11" . ".wav";
move_uploaded_file($_FILES['file']['tmp_name'], "../ext/wav/testes/" . $fname);
}
?>
According to the documentation, by using XMLHttpRequest.send() you can use the Blob object directly.
var blob = new Blob(chunks, { 'type' : 'audio/webm' });
var xhr = new XMLHttpRequest();
xhr.open('POST', '/speech', true);
xhr.onload = function(e) {
console.log('Sent');
};
xhr.send(blob);
I've tried this and it works like a charm.
I'm working on a generative art project where I would like to allow users to save the resulting images from an algorithm. The general idea is:
Create an image on an HTML5 Canvas using a generative algorithm
When the image is completed, allow users to save the canvas as an image file to the server
Allow the user to either download the image or add it to a gallery of pieces of produced using the algorithm.
However, I’m stuck on the second step. After some help from Google, I found this blog post, which seemed to be exactly what I wanted:
Which led to the JavaScript code:
function saveImage() {
var canvasData = canvas.toDataURL("image/png");
var ajax = new XMLHttpRequest();
ajax.open("POST", "testSave.php", false);
ajax.onreadystatechange = function() {
console.log(ajax.responseText);
}
ajax.setRequestHeader("Content-Type", "application/upload");
ajax.send("imgData=" + canvasData);
}
and corresponding PHP (testSave.php):
<?php
if (isset($GLOBALS["HTTP_RAW_POST_DATA"])) {
$imageData = $GLOBALS['HTTP_RAW_POST_DATA'];
$filteredData = substr($imageData, strpos($imageData, ",") + 1);
$unencodedData = base64_decode($filteredData);
$fp = fopen('/path/to/file.png', 'wb');
fwrite($fp, $unencodedData);
fclose($fp);
}
?>
But this doesn’t seem to do anything at all.
More Googling turns up this blog post which is based off of the previous tutorial. Not very different, but perhaps worth a try:
$data = $_POST['imgData'];
$file = "/path/to/file.png";
$uri = substr($data,strpos($data, ",") + 1);
file_put_contents($file, base64_decode($uri));
echo $file;
This one creates a file (yay) but it’s corrupted and doesn’t seem to contain anything. It also appears to be empty (file size of 0).
Is there anything really obvious that I’m doing wrong? The path where I’m storing my file is writable, so that isn’t an issue, but nothing seems to be happening and I’m not really sure how to debug this.
Edit
Following Salvidor Dali’s link I changed the AJAX request to be:
function saveImage() {
var canvasData = canvas.toDataURL("image/png");
var xmlHttpReq = false;
if (window.XMLHttpRequest) {
ajax = new XMLHttpRequest();
}
else if (window.ActiveXObject) {
ajax = new ActiveXObject("Microsoft.XMLHTTP");
}
ajax.open("POST", "testSave.php", false);
ajax.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
ajax.onreadystatechange = function() {
console.log(ajax.responseText);
}
ajax.send("imgData=" + canvasData);
}
And now the image file is created and isn’t empty! It seems as if the content type matters and that changing it to x-www-form-urlencoded allowed the image data to be sent.
The console returns the (rather large) string of base64 code and the datafile is ~140 kB. However, I still can’t open it and it seems to not be formatted as an image.
Here is an example of how to achieve what you need:
Draw something (taken from canvas tutorial)
<canvas id="myCanvas" width="578" height="200"></canvas>
<script>
var canvas = document.getElementById('myCanvas');
var context = canvas.getContext('2d');
// begin custom shape
context.beginPath();
context.moveTo(170, 80);
context.bezierCurveTo(130, 100, 130, 150, 230, 150);
context.bezierCurveTo(250, 180, 320, 180, 340, 150);
context.bezierCurveTo(420, 150, 420, 120, 390, 100);
context.bezierCurveTo(430, 40, 370, 30, 340, 50);
context.bezierCurveTo(320, 5, 250, 20, 250, 50);
context.bezierCurveTo(200, 5, 150, 20, 170, 80);
// complete custom shape
context.closePath();
context.lineWidth = 5;
context.fillStyle = '#8ED6FF';
context.fill();
context.strokeStyle = 'blue';
context.stroke();
</script>
Convert canvas image to URL format (base64)
// script
var dataURL = canvas.toDataURL();
Send it to your server via Ajax
$.ajax({
type: "POST",
url: "script.php",
data: {
imgBase64: dataURL
}
}).done(function(o) {
console.log('saved');
// If you want the file to be visible in the browser
// - please modify the callback in javascript. All you
// need is to return the url to the file, you just saved
// and than put the image in your browser.
});
Save base64 on your server as an image (here is how to do this in PHP, the same ideas is in every language. Server side in PHP can be found here):
I played with this two weeks ago, it's very simple. The only problem is that all the tutorials just talk about saving the image locally. This is how I did it:
1) I set up a form so I can use a POST method.
2) When the user is done drawing, he can click the "Save" button.
3) When the button is clicked I take the image data and put it into a hidden field. After that I submit the form.
document.getElementById('my_hidden').value = canvas.toDataURL('image/png');
document.forms["form1"].submit();
4) When the form is submited I have this small php script:
<?php
$upload_dir = somehow_get_upload_dir(); //implement this function yourself
$img = $_POST['my_hidden'];
$img = str_replace('data:image/png;base64,', '', $img);
$img = str_replace(' ', '+', $img);
$data = base64_decode($img);
$file = $upload_dir."image_name.png";
$success = file_put_contents($file, $data);
header('Location: '.$_POST['return_url']);
?>
I think you should convert the image to base64 and then to Blob and send it to the server. When you use base64 images, a lot of lines will be sent to server. With blob, it's only the file.
You can use this code bellow:
function dataURLtoBlob(dataURL) {
let array, binary, i, len;
binary = atob(dataURL.split(',')[1]);
array = [];
i = 0;
len = binary.length;
while (i < len) {
array.push(binary.charCodeAt(i));
i++;
}
return new Blob([new Uint8Array(array)], {
type: 'image/png'
});
};
And canvas code here:
const canvas = document.getElementById('canvas');
const file = dataURLtoBlob( canvas.toDataURL() );
After that you can use ajax with Form:
const fd = new FormData;
fd.append('image', file);
$.ajax({
type: 'POST',
url: '/url-to-save',
data: fd,
processData: false,
contentType: false
});
The code in CoffeeScript syntax:
dataURLtoBlob = (dataURL) ->
# Decode the dataURL
binary = atob(dataURL.split(',')[1])
# Create 8-bit unsigned array
array = []
i = 0
while i < binary.length
array.push binary.charCodeAt(i)
i++
# Return our Blob object
new Blob([ new Uint8Array(array) ], type: 'image/png')
And canvas code here:
canvas = document.getElementById('canvas')
file = dataURLtoBlob(canvas.toDataURL())
After that you can use ajax with Form:
fd = new FormData
# Append our Canvas image file to the form data
fd.append 'image', file
$.ajax
type: 'POST'
url: '/url-to-save'
data: fd
processData: false
contentType: false
Send canvas image to PHP:
var photo = canvas.toDataURL('image/jpeg');
$.ajax({
method: 'POST',
url: 'photo_upload.php',
data: {
photo: photo
}
});
Here's PHP script:
photo_upload.php
<?php
$data = $_POST['photo'];
list($type, $data) = explode(';', $data);
list(, $data) = explode(',', $data);
$data = base64_decode($data);
mkdir($_SERVER['DOCUMENT_ROOT'] . "/photos");
file_put_contents($_SERVER['DOCUMENT_ROOT'] . "/photos/".time().'.png', $data);
die;
?>
I've worked on something similar.
Had to convert canvas Base64-encoded image to Uint8Array Blob.
function b64ToUint8Array(b64Image) {
var img = atob(b64Image.split(',')[1]);
var img_buffer = [];
var i = 0;
while (i < img.length) {
img_buffer.push(img.charCodeAt(i));
i++;
}
return new Uint8Array(img_buffer);
}
var b64Image = canvas.toDataURL('image/jpeg');
var u8Image = b64ToUint8Array(b64Image);
var formData = new FormData();
formData.append("image", new Blob([ u8Image ], {type: "image/jpg"}));
var xhr = new XMLHttpRequest();
xhr.open("POST", "/api/upload", true);
xhr.send(formData);
If you want to save data that is derived from a Javascript canvas.toDataURL() function, you have to convert blanks into plusses. If you do not do that, the decoded data is corrupted:
<?php
$encodedData = str_replace(' ','+',$encodedData);
$decocedData = base64_decode($encodedData);
?>
http://php.net/manual/ro/function.base64-decode.php
In addition to Salvador Dali's answer:
on the server side don't forget that the data comes in base64 string format. It's important because in some programming languages you need to explisitely say that this string should be regarded as bytes not simple Unicode string.
Otherwise decoding won't work: the image will be saved but it will be an unreadable file.
I just made an imageCrop and Upload feature with
https://www.npmjs.com/package/react-image-crop
to get the ImagePreview ( the cropped image rendering in a canvas)
https://developer.mozilla.org/en-US/docs/Web/API/HTMLCanvasElement/toBlob
canvas.toBlob(function(blob){...}, 'image/jpeg', 0.95);
I prefer sending data in blob with content type image/jpeg rather than toDataURL ( a huge base64 string`
My implementation for uploading to Azure Blob using SAS URL
axios.post(azure_sas_url, image_in_blob, {
headers: {
'x-ms-blob-type': 'BlockBlob',
'Content-Type': 'image/jpeg'
}
})