Sort 2-d array using arsort - php

Question

Here is my array prob with two values value (int) and tag (string).
At the end of loop I want to sort array by value and want to print top 5 values with their tag.
foreach($POS as $p)
{
//echo "POS :".$p."<br/>";
while ($row1 = #mysqli_fetch_array($selectTag))
{
//Calculate total pos for given tag
//echo "Tag : ".$row1['tag']."<br/>";
$selectPOS1 = mysqli_query($con,"SELECT * from koove_posts where tag = '".$row1['tag']."'");
while ($row2 = #mysqli_fetch_array($selectPOS1))
{
//echo $row2['pos']."<br/>";
$totalPOSs.=$row2['pos'].",";
}
$totalPOS_count = str_word_count($totalPOSs);
//calculate how many times particular 'pos' appears for given tag
$pos_Count = substr_count($totalPOSs, $p);
//Calculate the probability for each part of speach
$prob[] = (object) array(
"value" => ($pos_Count + 1)/ ($totalPOS_count + $distinct_pos_Count),
"tag" => $row1['tag'],
);
}
}
arsort($prob);
$prob = array_slice($prob, 0, 5);
foreach ($prob as $array)
{
echo "Tag :". $array->tag." Probablity :".$array->value."<br/>";
}
I tried this, but it prints first 5 tags from list.

Answer 1

You should use uasort function this way:
<?php
$prob = [];
$prob[] = (object) array('value' => 1, 'tag' => 2);
$prob[] = (object) array('value' => 2, 'tag' => 4);
$prob[] = (object) array('value' => 3, 'tag' => 6);
$prob[] = (object) array('value' => 4, 'tag' => 8);
$prob[] = (object) array('value' => 5, 'tag' => 10);
$prob[] = (object) array('value' => 6, 'tag' => 12);
var_dump($prob);
uasort ($prob, function($a, $b) {
if ($a->value == $b->value) {
return 0;
}
return ($a->value < $b->value) ? 1 : -1;
});
var_dump($prob);