PHP - Get directory contents and info and output array - php

Question

I'm working on the following but have become stumped as to how to get this to output.
I have the following which scans the directory contents, then gets the info and saves it as an array:
//SCAN THE DIRECTORY
$directories = scandir($dir);
$directinfo = array();
foreach($directories as $directory){
if ($directory === '.' or $directory === '..') continue;
if(!stat($dir.'/'.$directory)){
} else {
$filestat = stat($dir.'/'.$directory);
$directinfo[] = array(
'name' => $directory,
'modtime' => $filestat['mtime'],
'size' => $filestat['size']
);
}
}
When trying to output it however, I'm just getting single letters with a lot of breaks. Im obviously missing something here with the output loop.
foreach($directinfo as $dirInfo){
foreach($dirInfo as $drInfo){
for ($x=0; $x<=2; $x++) {
<span>"".$drInfo[$x]."<br/></span>";
}
}
}
Help is greatly appreciated. :)

Answer 1

You have already did everything just remove your for loop.
and try to do the following-
foreach($directinfo as $dirInfo){
foreach($dirInfo as $key=>$drInfo){
echo "<span>".$key."=>".$drInfo."<br/></span>";
}
}

Answer 2

I think your dealing with a 2d array, but treating it like a 3d array.
what does
foreach($directinfo as $dirInfo){
foreach($dirInfo as $drInfo){
var_dump($drInfo);
}
}
give you?

Answer 3

You're building a single array, dirInfo.
Php foreach takes the array first;
foreach($dirInfo as $info) {
echo "<span>" . $info['name'] . "</span>";
}

Answer 4

Try this function. It will return you list of all files with path.
// to list the directory structure with all sub folders and files
function getFilesList($dir)
{
$result = array();
$root = scandir($dir);
foreach($root as $value) {
if($value === '.' || $value === '..') {
continue;
}
if(is_file("$dir$value")) {
$result[] = "$dir$value";
continue;
}
if(is_dir("$dir$value")) {
$result[] = "$dir$value/";
}
foreach(getFilesList("$dir$value/") as $value)
{
$result[] = $value;
}
}
return $result;
}