Laravel: InsertgetId and display results - php

I would like to insert some records into my DB table and using the insertgetid feature, return those results to my blade view.
Controller
$grids[] = array();
foreach($c as $key) {
$grids[] = DB::table('infile')->insertGetId(
array( 'href' => $key,
'creator_id' => $id,
'random' => substr(str_shuffle("aBcEeFgHiJkLmNoPqRstUvWxYz0123456789"),0, 9))
);
}
$name[] = array();
foreach($grids as $id){
$name = DB::table('infile')->where('id', '=', $id)->first();
}
return View::make('Home')->withName($name);
Blade View
#if(isset($name) && $name != '')
{{dd($name)}}
#endif
I'm getting this error
ErrorException
preg_replace(): Parameter mismatch, pattern is a string while replacement is an array

You can use whereIn to make exact query. between should work, but it's error prone, since there might be another row inserted in the meantime:
$ids = [];
foreach (..)
{
$ids[] = DB::table('infile')->insertGetId(...);
}
$data = DB::table('infile')->whereIn('id', $ids)->get();

I ended up using a different approach
I found the max id before I performed the insert and then found the max id after the insert and then used a wherebetween to grab the data.
$max = DB::table('infile')->max('id');
foreach($c as $key) {
DB::table('infile')->insertGetId(
array(
'href' => $key,
'creator_id' => $id,
'random' => substr(str_shuffle("aBcEeFgHiJkLmNoPqRstUvWxYz0123456789"),0, 9)
)
);
}
$max2 = DB::table('infile')->max('id');
$data = DB::table('infile')->whereBetween('id', array($max, $max2))->get();

$id = DB::table('user')->insertGetId(['name'=>"test"]);

Related

How to get data from database that result as an array in model codeigniter

I want to make a query that results like this in codeigniter MODEL:
$caldata = array (
15 => 'yes',
17 => 'no'
);
Is that possible to do?
Take NOTE: The 15,17 and yes,no are in the same database table.
There is no core helper function to achieve what you want in CI. But you can create your own helper function:
function pluck($arr = [], $val = '', $key = '')
{
// val - label for value in array
// key - label for key in array
$result = [];
foreach ($arr as $value) {
if(!empty($key)){
$result[$value[$key]] = $value[$val];
}else{
$result[] = $value[$val];
}
}
return $result;
}
you can use result_array() function so you can have something like:
$query = $this->db->select('id,answer')->from('users')->get();
$result = $query->result_array();
print_r($result);
After that you have your array and you can make the $key => $value relation of the fields
After a long search i found an answer. Sample way to do this:
$query = $this->db->select('start_date, class')->from('event')->like('start_date', "$year-$month", 'after')->get();
$datavariable = $query->result();
$caldata = array();
foreach($datavariable as $row){
$caldata[substr($row->start_date,8,2)] = $row->class;
}

Getting multiple fields from database to an array

I wrote an api call in my Symfony project that returns all fields from my entity with the query defined below..
Now, I need to define just three fields like 'id', 'name', 'value' and to pull values from that fields that are currently stored in a database.
public function getChartData() {
$myResults = $this->getMyRepository()
->createQueryBuilder('s')
->groupBy('s.totalCollected')
->orderBy('s.id', 'ASC')
->getQuery()
->getArrayResult();
$result = array("data" => array());
foreach ($myResults as $myResult => $label) {
$result['data'][$schoolResult] = $label["id"];
$result['data'][$schoolResult] = $label["name"];
$result['data'][$schoolResult] = $label["totalCollected"];
}
}
The problem is it return just totalCollected field.
One of errors are Call to a member function getId() on array and so on, and I can't figure out a way to pull data from db...
I cannot see in your code where $schoolResult come from but lets guess it string key of some sort.
Notice you trying to set 3 value on the same key so only the last one remains.
Look at:
$a = array();
$a["key"] = 4;
$a["key"] = 6;
It is simple to see that $a["key"] will contains 6 and not 4 or both.
When you do:
foreach ($myResults as $myResult => $label) {
$result['data'][$schoolResult] = $label["id"];
$result['data'][$schoolResult] = $label["name"];
$result['data'][$schoolResult] = $label["totalCollected"];
}
You override the data in $result['data'][$schoolResult] therefor only try totalCollected is there as the last one to set.
In order to fix that you can use:
foreach ($myResults as $myResult => $label) {
$result['data'][$schoolResult]["id] = $label["id"];
$result['data'][$schoolResult]["name"] = $label["name"];
$result['data'][$schoolResult]["totalCollected"] = $label["totalCollected"];
}
Hope that helps!

How to change a php array

Simple question to which I don't have an answer.
How can I change my array from this:
[{"sku":"6"},{"buyers":"7"},{"base":"8"}]
to this:
[{"sku":"6","buyers":"7","base":"8"}]
I have three queries for three different database tables:
$sku = DB::table('mapiranje')->select(DB::raw('count(*) as sku'))
->where('mate_fk', '=', NULL)
->get();
$kupac = DB::table('mapkupci')->select(DB::raw('count(*) as buyers'))
->where('kupci_fk', '=', NULL)
->get();
$base = DB::table('dist_base')->select(DB::raw('count(*) as base'))
->where('base_fk', '=', NULL)
->get();
now each returns:
[{"sku":"6"}]
[{"buyers":"6"}]
[{"base":"6"}]
I have used merge_array to make a single array, but I get:
[{"sku":"6"},{"buyers":"7"},{"base":"8"}]
what I want is:
[{"sku":"6","buyers":"7", "base":"8"}]
Refactor your code according to right Laravel way:
$result = [
'sku' => DB::table('mapiranje')->whereNull('mate_fk')->count(),
'buyers' => DB::table('mapkupci')->whereNull('kupci_fk')->count(),
'base' => DB::table('dist_base')->whereNull('base_fk')->count()
];
$result = [];
foreach($input as $oneInputRow) {
$result[$oneInputRow[0]] = $oneInputRow[1];
}
$target = array();
$start = array(array("sku"=>"6"), "buyers"=>"7"), "base"=>"8"));
foreach($start as $sub){
foreach($sub as $key => $val){
$target[$key] = $val;
}
}
Not shure if laravel provides any special syntax, but just with php I'd do it as above.
Basicly you loop over the start-array. In that you loop over every array to get the key/val combination and put that into the target-array.
For the second loop there would be other ways if you only have one entry in every secondary array.
Please try below code
$dd = '[{"sku":"6"},{"buyers":"7"},{"base":"8"}]';
$data = json_decode($dd,true);
$result = array();
foreach($data as $key=>$value){
foreach($value as $key1=>$value1){
$result[$key1] = $value1;
}
}
echo json_encode($result); //this will print your required format result

Get node from php array by one of the fields

I have an array with structure generated like this:
$groups = array();
while ($group = mysql_fetch_array($groups_result)) {
$groups[] = array( 'id' => $group['id'], 'name' => $group['name']);
}
How can I later in the code get the name of the group by its id? For example, I would like a function like:
function get_name_by_id($id, $array);
But I'm looking for some solution which is already implemented in PHP. I know it would be easier to make arrays with array[5] = array('name' => "foo") etc where 5 in this case is id, but in my code there is a lot of arrays already created like i mentioned above and I cannot easily switch it.
$groups = array();
while ($group = mysql_fetch_assoc($groups_result)) {
$groups[$group['id']] = array( 'name' => $group['name']);
}
$name = $groups['beer']['name'];
also please not using fetch_assoc is more efficient than fetch array
function get_name_by_id($id, $data) {
foreach($data as $d) {
if ($d['id'] == $id) {
return $d['name'];
}
}
// return something else, id was not found
}

php foreach supplied argument not valid

I am getting results from a mysql table and putting each cell into an array as follows:
$sqlArray = mysql_query("SELECT id,firstName FROM members WHERE id='$id'");
while ($arrayRow = mysql_fetch_array($sqlArray)) {
$friendArray[] = array(
'id' => $arrayRow['id'],
'firstName' => $arrayRow['firstName'],
);
}
Then I do a search for a specific friend. For example if I want to search for a friend name Osman, i would type and o and it will return to me all the results that start with the letter o. Here is my code for that:
function array_multi_search($array, $index, $pattern, $invert = FALSE) {
$output = array();
if (is_array($array)) {
foreach($array as $i => $arr) {
// The index must exist and match the pattern
if (isset($arr[$index]) && (bool) $invert !== (bool) preg_match($pattern, $arr[$index])) {
$output[$i] = $arr;
}
}
}
return $output;
}
$filtered = array_multi_search($friendArray, 'firstName', '/^o/i');
and then it will print out all the results. My problem is that it returned an error saying "Invalid argument supplied to foreach()" and that is why I added the if(is_array)) condition. It is working fine if I leave this code in the index.php page, but I moved it to a subfolder named phpScripts and it doesn't work there. Any Help?
$output is not returning any value because apparently $friendArray is not an array. But I verified that it is by using print_r($friendArray) and it returns all the member's id and firstName.
P.S. I use JavaScript to the the call using AJAX.
If your array structure is such:
$friendArray[] = array(
'id' => $arrayRow['id'],
'firstName' => $arrayRow['firstName'],
);
This means your array is indexed and two levels.
So the correct way to walk through it is:
foreach($array as $cur_element) {
$id = $cur_element['id'];
$firstName = $cur_element['firstName'];
}
Change this:
foreach($array as $i => $arr) {
To this:
foreach((array)$array as $i => $arr) {
Are you sure that $array is not empty?

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