I have a query in a repository like :
$rsm = new ResultSetMapping;
$rsm->addEntityResult('\My\ProjectBundle\Entity\News', 't');
$rsm->addFieldResult('t', 'id', 'id');
$rsm->addMetaResult('t', 'account_id', 'account_id');
$qb = $this->_em->createNativeQuery(
'SELECT t.*
FROM news as t
LEFT JOIN
LEFT JOIN
WHERE
CONDITIONS CONDITIONS
',
$rsm
);
return $qb->getResult();
I simplified the above query which is used to retrieve the news that meet specific conditions.
I need to add a count() function to this query.
I have an other ManyToOne entity-relationship between Comment and News.
How to modify the query to get the comments number a given news has ?
I'm trying to add a left join to comment and add Count() in the select but I always get errors. How could I resolve this problem ?
Raw SQL with Doctrine is easier like this :
$em = $this->getDoctrine()->getManager()->getConnection();
$query = "
SELECT t.*
FROM news as t
LEFT JOIN
LEFT JOIN
WHERE
CONDITIONS CONDITIONS
";
$stmt = $em->prepare($query);
$stmt->execute();
$result = $stmt->fetchAll();
Related
I have a two tables in my database instructors and courses . I want to join them and for this reason wrote this code
$this->db->join('instructors', 'instructors.id = courses.instructor_id', 'left');
$query = $this->db->get_where('courses', array('courses_slug' => $slug));
return $query->row_array();
This code means:
SELECT * FROM `courses` LEFT JOIN `instructors` ON `instructors`.`id` = `courses`.`instructor_id` WHERE `courses_slug` = 'abituriyent-hazirligi'
But when I write this code to check:
$data['courses'] = $this->popular_courses_model->get_popular_courses($slug);
echo $data['courses']['id'];
die();
It writes the instructors id, not id of the course. Where can be the problem? Thanks in advance.
You are joining two table with columns of the same name ('id'). You need to be specific in your select for the columns and rename ('AS') if necessary.
select courses.id as course_id, instructor.id as instructor_id, ...
When using joins you should explicitly call out what columns you want returned like:
$select = "c.id, c.name, c.instructor_id, i.name instructor_name";
return $this->db->select($select)
//equivalent to "instructors as i"
->join('instructors i', 'i.id = c.instructor_id', 'left')
->where('c.courses_slug', $slug)
//equivalent to "courses as c"
->get('courses c')->row_array();
I have a query builder with the following select:
$starterRepository = $this->getDoctrine()
->getManager()
->getRepository('CatalogBundle:Starter');
$query = $starterRepository->createQueryBuilder('s')
->where('s.active = 1')
->orderBy('s.voltage, s.power, s.serial');
It selects the table "starters", but inside Starter.php I have an association "references" like this:
/**
* #var ArrayCollection
*
* #ORM\ManyToMany(targetEntity="StarterReference", inversedBy="starters")
* #ORM\JoinTable(name="starters_references")
*/
protected $references;
So inside my query results I have both "starters" and "starters_references" tables. 1 starter has many starter references. Now the problem is that I need to select not all of the starter references, but only the ones which has some value in column named "ref_usage".
So I need to write where clause in my query, I am trying this:
->where('reference.ref_usage = 1')
But this way I get only one "starter" item with all the references it has included. And I need all the starter items, but with only the references with ref_usage 1.
Any ideas?
Here is the full files and functions I am using.
Controller function:
http://pastebin.com/0tTEcQbn
Entity "Starter.php":
http://pastebin.com/BFLpKtec
Entity "StarterReference.php":
http://pastebin.com/Kr9pEMEW
EDIT:
This is the query I get if I use:
->where('reference.ref_usage = 1')
SELECT COUNT(*) AS dctrn_count FROM (SELECT DISTINCT id0 FROM (SELECT s0_.id AS id0, s0_.serial AS serial1, s0_.voltage AS voltage2, s0_.power AS power3, s0_.rotation AS rotation4, s0_.teeth AS teeth5, s0_.module AS module6, s0_.b_terminal AS b_terminal7, s0_.comment AS comment8, s0_.commenten AS commenten9, s0_.commentru AS commentru10, s0_.commentpl AS commentpl11, s0_.commentde AS commentde12, s0_.commentes AS commentes13, s0_.type AS type14, s0_.adaptation AS adaptation15, s0_.alternative_product_1 AS alternative_product_116, s0_.alternative_product_2 AS alternative_product_217, s0_.alternative_product_3 AS alternative_product_318, s0_.alternative_product_4 AS alternative_product_419, s0_.active AS active20 FROM starters s0_ INNER JOIN starters_references s2_ ON s0_.id = s2_.starter_id INNER JOIN starter_reference s1_ ON s1_.id = s2_.starterreference_id WHERE s0_.active = 1 AND s1_.ref_usage = 1 ORDER BY s0_.voltage ASC, s0_.power ASC, s0_.serial ASC) dctrn_result) dctrn_table
As you can see it adds ref_usage = 1 to where clause. But the problem is that I don't need it here, I only need to check ref_usage when I inner join my references.
You should join the references in your query and then add the where clause.
$query = $starterRepository->createQueryBuilder('s')
->join('s.references', 'reference')
->where('s.active = 1')
->andwhere('reference.ref_usage = 1')
->orderBy('s.voltage, s.power, s.serial');
I am trying to link 4 tables and also add a custom field calculated by counting the ids of some related tables using laravel.
I have this in SQL which does what I want, but I think it can be made more efficient:
DB::select('SELECT
posts.*,
users.id AS users_id, users.email,users.username,
GROUP_CONCAT(tags.tag ORDER BY posts_tags.id) AS tags,
COUNT(DISTINCT comments.id) AS NumComments,
COUNT(DISTINCT vote.id) AS NumVotes
FROM
posts
LEFT JOIN comments ON comments.posts_id = posts.id
LEFT JOIN users ON users.id = posts.author_id
LEFT JOIN vote ON vote.posts_id = posts.id
LEFT JOIN posts_tags ON posts_tags.posts_id = posts.id
LEFT JOIN tags ON tags.id = posts_tags.tags_id
GROUP BY
posts.id,
posts.post_title');
I tried to implement it using eloquent by doing this:
$trending=Posts::with(array('comments' => function($query)
{
$query->select(DB::raw('COUNT(DISTINCT comments.id) AS NumComments'));
},'user','vote','tags'))->get();
However the NumComments value is not showing up in the query results.
Any clue how else to go about it?
You can't do that using with, because it executes separate query.
What you need is simple join. Just translate the query you have to something like:
Posts::join('comments as c', 'posts.id', '=', 'c.id')
->selectRaw('posts.*, count(distinct c.id) as numComments')
->groupBy('posts.id', 'posts.post_title')
->with('user', 'vote', 'tags')
->get();
then each post in the collection will have count attribute:
$post->numComments;
However you can make it easier with relations like below:
Though first solution is better in terms of performance (might not be noticeable unless you have big data)
// helper relation
public function commentsCount()
{
return $this->hasOne('Comment')->selectRaw('posts_id, count(*) as aggregate')->groupBy('posts_id');
}
// accessor for convenience
public function getCommentsCountAttribute()
{
// if relation not loaded already, let's load it now
if ( ! array_key_exists('commentsCount', $this->relations)) $this->load('commentsCount');
return $this->getRelation('commentsCount')->aggregate;
}
This will allow you to do this:
$posts = Posts::with('commentsCount', 'tags', ....)->get();
// then each post:
$post->commentsCount;
And for many to many relations:
public function tagsCount()
{
return $this->belongsToMany('Tag')->selectRaw('count(tags.id) as aggregate')->groupBy('pivot_posts_id');
}
public function getTagsCountAttribute()
{
if ( ! array_key_exists('tagsCount', $this->relations)) $this->load('tagsCount');
$related = $this->getRelation('tagsCount')->first();
return ($related) ? $related->aggregate : 0;
}
More examples like this can be found here http://softonsofa.com/tweaking-eloquent-relations-how-to-get-hasmany-relation-count-efficiently/
as of laravel 5.3 you can do this
withCount('comments','tags');
and call it like this
$post->comments_count;
laravel 5.3 added withCount
I try to get this mysql query to work with Yii model but i can't.
SELECT COUNT( qhc.countries_id) AS counter, q.question, co.name
FROM questions AS q , countries as co, questions_has_countries AS qhc
WHERE qhc.questions_id = q.id
AND co.id = qhc.countries_id
GROUP BY question
HAVING counter = 2
So far i have this, but somehow thou it seems ok, it doesnt work :
$criteria = new CDbCriteria();
$criteria->select = 'question, COUNT(countries_id) as counter';
$criteria->with = array('countries', 'categories');
$criteria->addInCondition('countries.id' , $_POST['Questions']['countries']);
$criteria->group = 'question';
$criteria->having = ('counter = 1');
$model = Questions::model()->findAll($criteria)
Pls help, I'am pretty new to Yii framework.
Thanks.
Sql from the log :
SELECT `t`.`question` AS `t0_c1`,
COUNT(countries_id) as counter, `t`.`id` AS `t0_c0`, `countries`.`id` AS
`t1_c0`, `countries`.`name` AS `t1_c1`, `categories`.`id` AS `t2_c0`,
`categories`.`name` AS `t2_c1` FROM `questions` `t` LEFT OUTER JOIN
`questions_has_countries` `countries_countries` ON
(`t`.`id`=`countries_countries`.`questions_id`) LEFT OUTER JOIN `countries`
`countries` ON (`countries`.`id`=`countries_countries`.`countries_id`)
LEFT OUTER JOIN `questions_has_categories` `categories_categories` ON
(`t`.`id`=`categories_categories`.`questions_id`) LEFT OUTER JOIN
`categories` `categories` ON
(`categories`.`id`=`categories_categories`.`categories_id`) WHERE
(countries.id=:ycp0) GROUP BY question HAVING (counter = 2). Bound with
:ycp0='1'
You have done most of work. Now you need to call the $criteria into model. Just like this
$rows = MODEL ::model()->findAll($criteria);
Where MODEL is model class of table which you want to apply criteria on.
To learn more about this you can follow this CActiveRecord Class.
Try to set together in CDbCriteria
...
$criteria->together = true;
$model = Question::model()->findAll($criteria);
when you use "as counter", your model must have a property named "counter" or it will not load it into your model.
if you don't have a property named "counter", try using another one of your models property that you are not selecting right now : "as someColumn"
and use condition or addCondition or .. instead of having
cheers
Can I write something like this:
$post = Post::join(['author'])->find($postId);
$authorName = $post->author->name;
To produce only ONE select with inner join (no 2 selects) and without using DB query builder
SELECT
post.*,
author.*
FROM post
INNER JOIN author
ON author.id = post.author_id
WHERE post.id = ?
You can do it in Eloquent using the join method:
$post = Post::join('author', function($join)
{
$join->on('author.id', '=', 'post.author_id');
})
->where('post.id', '=', $postId)
->select('post.*', 'author.*')
->first();
Please note that your results in $post will be an object where their attributes will correspond to the result set, if two columns has the same name it will be merged. This happen when using:
->select('post.*', 'author.*')
To avoid this, you should create alias to those columns in the select clause as shown below:
->select('post.id AS post_id', 'author.id AS author_id')
Try
Post::join('author',function($join){
$join->on('author.id','=','post.author_id');
})->where('post.id','=',$postId)->select('post.*','author.*');