I am trying to call ajax but it always goes in error part. Please help and tell me where I am wrong. I have also tried writing the final value in a text file and it was perfect but don't know why it is not working. I have also checked the URL it is also correct.
PHP Code:
public function checkLockBeforeSend()
{
$mail_key = $_POST['mail_key'];
$this->load->model('dl_master/email_compose');
$result = $this->model_dl_master_email_compose->checkLock($mail_key);
if($result['isopen'] == 1 && $result['openedby'] != $_SESSION['user_id'])
{
$this->load->model('dl_common/commonutil');
$userResult = $this->model_dl_common_commonutil->getUserById($result['openedby']);
$userName = $userResult['firstname'] . " " . $userResult['lastname'];
$html = $userName;
}
else
{
$html = "Empty";
}
/* Just to check what value is coming */
$fp = fopen("C:\\test.txt","w");
fwrite($fp,$html);
fclose($fp);
echo $html;
}
Ajax function:
function checkLockBeforeSend(mail_key)
{
var ajaxUrl = "index.php?route=dl_master/email_compose/checkLockBeforeSend&token=" + token;
$.ajax ({
url:ajaxUrl,
type:'post',
dataType: 'html',
data:{'mail_key':mail_key},
success:function (result)
{
alert(result);
if(result.trim() != "Empty")
{
finalResult = confirm(result);
}
},
error: function ()
{
alert("An error occurred.");
}
});
}
Please help me.
Please try data:{mail_key:mail_key}, instead of data:{'mail_key':mail_key},.
Related
I have this ajax function for login.
Edit: I just noticed that this server runs php7 while other server where the login does work uses php5. What has changed in php that this script doesn't work anymore?
Edit 2: Looks like the server request method isn't post but changed to get, why?
Solution: needed to remove the .php from url: "./ajaxcall/login.php", because I use pretty url htaccess.😅
var InName = $('#InName').val();
var InPass = $('#InPass').val();
alert(InName);
$.ajax({
type: "POST",
url: "./ajaxcall/login.php",
dataType: "json",
data: {InName:InName, InPass:InPass},
error: function (request, error) {
console.log(arguments);
alert("Inlog Can't do because: " + error);
},
success : function(data){
if (data.code == "200"){
$("#InErEr").html(data.msg);
//window.location.reload(true);
} else {
$("#InErEr").html(data.msg);
$('.lds-dual-ring').animate({opacity: 0}, 300);
}
}
});
On the alert(InName); I get the correct value of the username. But when I check in my php file $_POST['InName'] it is empty.
Part of php file
include('../config.php');
if(empty($_POST['InName'])) {
$Ierror = 'Username is required.';
}
if($_POST['InPass'] == '') {
$Ierror = 'Password is required.';
}
$username = $_POST['InName'];
$passwordL = $_POST['InPass'];
// count user in between //
if($Inlognumber_of_rows == 0) {
$Ierror = 'Username not found.';
} else {
// password check //
if(password_verify($salty_pass, $hashed_password)) {
} else {
$Ierror = 'Password incorrect.';
}
}
if ($Ierror == '') {
// do login //
} else {
$showerror = '<span style="color:#F00;">'.$Ierror.$username.$passwordL.$_POST['InName'].$_POST['InPass'].'</span>';
echo json_encode(['code'=>404, 'msg'=>$showerror]);
exit;
}
In the return message, $showerror I only get, Username not found, without the posted values. So the login is not working because of empty values? User is also present in the database of course. I also don't get the empty $_POST errors. So to cap up, in javascript I get the correct value for InName but not in php.
You are close but your error catch is not correct ... try this (Jquery):
var InName = 'something';
var InPass = 'morething';
$.post("./ajaxcall/login.php", {
InName: InName,
InPass: InPass
}, function(data, status) {
console.log(data, status);
}).done(function() {
alert("second success");
})
.fail(function() {
alert("error");
})
.always(function() {
alert("finished");
});
on your php file just do print_r($_POST); and you will receive this in your console...:
Array
(
[InName] => something
[InPass] => morething
)
success
Basically you were trying to print the error where you should have consoled log the request.responeText...
A good trick to know if posts arrived to the php even if the console.log won't show is doing this in the php file:
<?php
print_r($_POST) ;
$newfile = fopen('newfile.txt','a');
fwrite($newfile,json_encode($_POST));
fclose($newfile);
This will print and also store on a local file the post data....
Solution: needed to remove the .php from url: "./ajaxcall/login.php", because I use pretty url htaccess.😅
I am trying to get values from form with serialize function and I correctly post and save to database but after this step my codes don't work . Someone help please ?
$(document).ready(function() {
$("#kform").submit(function() {
var data = $(this).serialize();
$.ajax({
type: "POST",
url: "yenikayit2.php",
data: data,
dataType: "json",
success: function(data) {
if (data.tip === "dosya") {
alert("tralalala d");
}
if (data.tip === "tercume") {
alert("tralalala t");
}
if (data.tip === "hata") {
alert("tralalala hata");
}
}
});
});
PHP Code
<?php
if($musteri_ekle) { //mysql control function
$musteri_id=mysqli_insert_id($baglanti);
$_SESSION[ 'musteri_id']=$musteri_id;
if ($secilen=="dosya" )
{ echo json_encode(array( "tip"=>"dosya")); }
else if ($secilen == "tercume")
{ echo json_encode(array("tip"=>"tercume")); } }
else { echo json_encode(array("tip"=>"hata")); } ?>
Modify yenikayit2.php to avoid PHP fatal error and notices. You can either use error_reporting(null);
or edit the code as below
if (isset($musteri_ekle)) { // to avoid undefined variable error
$musteri_id = mysqli_insert_id($baglanti);
$_SESSION['musteri_id'] = $musteri_id;
if ($secilen == "dosya") {
echo json_encode(array("tip" => "dosya"));
} else if ($secilen == "tercume") {
echo json_encode(array("tip" => "tercume"));
}
} else {
echo json_encode(array("tip" => "hata"));
}
Well, i realized that i forgot put this fields on form action="" and method=""
after this i changed my jquery code :
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
$("#kayit").click(function(event) { var data=$("#kform").serialize(); }
And this works correctly
I've struggeled alot with this .
I wanna send an ID in the CI model and get the returned value via CI controller
My view is
<script type="text/javascript">
function showsome(){
var rs = $("#s_t_item option:selected").val();
var controller = 'items';
var base_url = '<?php echo site_url(); ?>';
$.ajax({
url : base_url+ '/' + controller+ '/get_unit_item',
type:'POST',
contentType: 'json',
data: {item_id: rs},
success: function(output_string){
//$('#result_area').val(output_string);
alert(output_string);
}
});
}
</script>
My Controller method is
public function get_unit_item()
{
$received = $this->input->post('item_id');
$query = $this->units_model->get_unit_item($received);
$output_string = '';
if(!is_null($query)) {
$output_string .= "{$query}";
} else {
$output_string = 'There are no unit found';
}
echo json_encode($output_string);
}
And my model function responsible
public function get_unit_item($where){
$this->db->where('item_id',$where);
$result = $this->db->get($this->tablename);
if($result->num_rows() >0 ){
$j = $result->row();
return $j->unit_item_info ;
}
}
Html codes
<?php $id = 'id="s_t_product" onChange="showsome();"';
echo form_dropdown('product_id[]', $products, $prod,$id); ?>
I tried to use the id only but failed to fire so passing a function onchange seems to pick the item and fire
Using firebug I can see that the post request sends item_id=2 but the response length is 0 and with php result code 302
POST
RESPONSE
How can I achive this?(The model is loaded on the contructor)
Do slighly change your controller and model:
// Model
public function get_unit_item($where){
$this->db->where('item_id',$where);
$result = $this->db->get($this->tablename);
if($result->num_rows() > 0 ) {
$j = $result->row();
return $j->unit_item_info ;
}
else return false;
}
// Controller
public function get_unit_item()
{
$received = $this->input->post('item_id');
$return = array('status'=>false);
if( $query = $this->units_model->get_unit_item($received) ) {
$return['status'] = true;
// Add more data to $return array if you want to send to ajax
}
$this->output->set_content_type("application/json")
->set_output(json_encode($return));
}
Check returned values in JavaScript:
$.ajax({
url : base_url+ '/' + controller+ '/get_unit_item',
type:'POST',
dataType: 'json',
data: {item_id: rs},
success: function( response ){
if( response.status === true ) {
alert('Everything Working Fine!');
console.log( response );
}
else alert('Something went wrong in query!');
}
});
After trying various approaches I have finally found what really is the problem and i think this might be the problem for all with the 302 found error. In this project (server) there're two systems within the same root and each has got its own codeigniter files. As seen above i was using
var controller = 'items';
var base_url = '<?php echo site_url(); ?>';
url : base_url+ '/' + controller+ '/get_unit_item',
as the value for url but i tried to put the full url from the base and it worked so now it is
url: '<?php echo base_url(); ?>index.php/en/items/get_unit_item',
. I think for any one with the redirect issue the first thing to check is this
I'm new to jQuery, and have not been able to debug this ajax call in Firebug:
This is my ajax call:
var styndx = $('#studylist option:selected').val();
var studyname = $('#edit_field').val();
$.post("saveStudyName.php", {'type': 'update', 'studyname':studyname, 'styndx':styndx},
function(resultmsg) {
$('#edit_field').val('');
$('#savebtn').attr('disabled',true);
refresh_studynames();
});
And this is the function refresh_studynames:
function refresh_studynames()
{
$.ajax({
url: 'getStudyNames.php',
data: "",
dataType: 'json',
error: function() {
alert('Refresh of study names failed.');
},
success: function(data)
{
$data.each(data, function(val, sname) {
$('#studylist').append( $('<option></option>').val(val).html(sname) )
});
}
});
}
Finally, this is the php script getStudyNames.php ($dbname,$dbconnect, $hostname are all populated, and $dbconnect works; the backend database is Postgres, and pg_fetch_all is a Postgres function in PHP that returns result as an array):
$dbconnect = pg_pconnect("host=".$hostname." user=".$dbuser." dbname=".$dbname);
if (!$dbconnect) {
showerror(0,"Failed to connect to database",'saveStudyName',30,"username=".$dbuser.", dbname=".$dbname);
exit;
}
$sql = "SELECT ST.studyindex,ST.studyabrv AS studyname
FROM ibg_studies ST
ORDER BY studyname";
$fetchresult = pg_exec($dbconnect, $sql);
if ($fetchresult) {
$array = pg_fetch_all($fetchresult);
echo json_encode($array);
} else {
$msg = "Failure! SQL="+$sql;
echo $msg;
}
Any help much appreciated....
The line
$('#studylist').append( $('<option></option>').val(val).html(sname) );
looks wrong.
I'm not too sure but you could try :
var $studylist = $('#studylist').empty();
$data.each(data, function(i, record) {
$studylist.append( $('<option/>').html(record.sname) );
});
I am sure this is probably something simple that i am not doing. Running livevalidation.js jquery plugin (livevalidation.com). It provides for custom function callbacks. I am trying to check for username availability. The server side is working fine and I am getting the proper responses back in my data var...
Here is my JS:
Validate.Username = function(value, paramsObj) {
var paramsObj = paramsObj || {};
var message = paramsObj.failureMessage || "Username is not available";
var isSuccess = true;
$.post("<?php echo fURL::getDomain(); ?>/ajax/username",
function(data) {
if (data.status === 'notavailable')
{
Validation.fail('oops, not available.');
}
});
};
I am calling it using:
var username = new LiveValidation('username', { validMessage: curr_username + "is available!" });
username.add( Validate.Presence, { failureMessage: "Choose a username" });
username.add( Validate.Username, { failureMessage: "Username is not available." } );
The problem I am getting is:
Uncaught ReferenceError: Validation is not defined
If I put the Validation.fail() outside of my .post() function it works fine. So am pretty sure it is because it's not able to be referenced inside the .post() function.
I've tried using a callback function
if (data.status === 'notavailable')
{
status_not_available();
}
I get the same error.
I realize this is something probably extremely simple, but any help would be appreciated. Thank you in advance.
i am having the same issue.
Ive found the following, http://forum.jquery.com/topic/ajax-return-value-on-success-or-error-with-livevalidation but have not been able to get it working.
BUT YES! At this very moment i made som (crappy) javascript addon that made it behave, i think :)
This is what i use.
function check_avail(name, id, postUrl)
{
var dataVal = name+'='+$(id).val();
var isaccepted = ''
$(id).next('div').remove();
$(id).after("Undersøger om "+name+" er ledigt");
$.ajax({
url: postUrl,
cache: false,
type: 'post',
dataType: 'json',
data: dataVal,
async: false,
success: function(data) {
if( data.success == 'true' )
{
$('#'+name+'-availability').remove();
//return false;
isaccepted = false;
}
if( data.success == 'false' )
{
$('#'+name+'-availability').remove();
// name.destroy();
isaccepted = true;
}
}
});
if (isaccepted == false) {
return false;
} else{
return true
};
}
And
f1.add( Validate.Custom, { against: function() {
return check_avail( 'brugernavn', '#ft001', 'usernamecheck.asp' );
}, failureMessage: 'Brugernavnet er optaget' } );
Hope it helps you :)
The json query you can read about on the link in the begining :)
(I am not at all skilled at javascript, and the "isaccepted" solution could problalby be made a lot better)
try to change it from Validation.fail to Validate.fail
try wrapping it in another function and try putting your validateStatus(status) function both inside and outside your Validate.Username function. example below is inside
Validate.Username = function(value, paramsObj) {
var paramsObj = paramsObj || {};
var message = paramsObj.failureMessage || "Username is not available";
var isSuccess = true;
$.post("<?php echo fURL::getDomain(); ?>/ajax/username",
function(data) {
validateStatus(data.status);
});
function validateStatus(status){
if (status === 'notavailable'){
Validate.fail("not available");
}
}
};