I have a drop down that's numbered 1-30. So if I select '2', my radio buttons will appear like this:
<input type="radio" id="yes-sdf-1" name="field[1][sdfradio]" value="Yes" />
<input type="radio" id="no-sdf-1" name="field[1][sdfradio]" value="No" />
<input type="radio" id="yes-sdf-2" name="field[2][sdfradio]" value="Yes" />
<input type="radio" id="no-sdf-2" name="field[2][sdfradio]" value="No" />
How do I get the individual values of the radio buttons because I want to set conditions that will only affect those with the same name.
Here is an example to give you an idea.
Try this:
$('input:radio').click(function(){
alert($(this).attr('name'));
});
This will return the name of the radio button.
JSFiddle
Related
I have 3 radio buttons in my form. 2 of them have static values and the 3rd one has a radio button that should have the same value as the number entered in the textbox. I am able to fetch the first 2 radio buttons values by using $_POST method on next page but for the 3rd radio button, the value is null. Please help me get the textbox value for the 3rd radio button. The code is :
<input type="radio" name="radio" value="500000" checked="checked" />Purchase More than 5 Lakhs
<input type="radio" name="radio" value="2000000" />Purchase More than 20 Lakhs
<input type="radio" name="radio" value="" />Purchase More than : <input type="text" name="radio" />
If you want to solve this using PHP, try this approach:
<input type="radio" name="radio" value="500000" checked="checked" />Purchase More than 5 Lakhs
<input type="radio" name="radio" value="2000000" />Purchase More than 20 Lakhs
<input type="radio" name="radio" value="0" />Purchase More than : <input type="text" name="user_entered" />
In your PHP file:
$result = $_POST['radio']?$_POST['radio']:$_POST['user_entered'];
This means: if radio is set, use radio value; else use the user_entered value.
Of course, you should further check if user_entered contains a valid value, depending on your requirements.
Your inputs should have different names. Call your type="text" input something different from radio and then you should be able to do $_POST["newName"]
Unfortunately I haven't been able to find exactly what I'm looking for online to resolve this.
At any rate, I have three radio buttons and I need to push the selection of a single button selected from the list into MySQL.
Currently using the below as my radio buttons & submit:
<input class="radiobutton" type="radio" name="1" id="1">1</div>
<input class="radiobutton" type="radio" name="2" id="2">2</div>
<input class="radiobutton" type="radio" name="3" id="3">3</div>
<input type="submit" name="submit" value="Update">`
Can someone help me with the syntax to grab the selected radio button and insert it into MySQL?
An example of the syntax would be
UPDATE tblwhatever.setting SET value='$x' where setting='Y';
Consider the following:
<input class="radiobutton" type="radio" name="radio" id="1" value="1" onclick="document.getElementById('2').checked = false;"/>
<input class="radiobutton" type="radio" name="radio" id="2" value="2" onclick="document.getElementById('1').checked = false;"/>
Note that i gave them the same name attribute. When the form is submitted we will retrieve $_POST['radio'] and the value will determine which radio button was selected. The onclick attribute will uncheck the other radio button if selected.. eg: if radio id="1" is being checked uncheck id="2"
<form method='POST' >
<input class="radiobutton" type="radio"
name="radio" id="1" value='1' checked>
<input class="radiobutton" type="radio"
name="radio" id="2" value='2'>
<input class="radiobutton" type="radio"
name="radio" id="3" value='3'>
<input type="submit" name="submit"
value="Update">`
</form>
in php code should be like this :
<?
$radio = $_POST['radio'];
$query = mysql_query('update "your table" set column1=$radio WHERE some_column=some_value);
?>
I am developing a PHP website which will generate several approval requests.
My approval page has only one form and one save button, and I want to use 2 radio buttons for each request.
Here is a link to how I imagine it to look like: link
On the PHP side I have no problem with generating the form and assigning different names to the radio buttons. My problem is what names I should give to the radio buttons in order for me to be able to associate them to a specific member on the PHP side? Or do I need to set values for the radio buttons?
How would I accomplish this?
If you have an even better solution to handle such a case I am open to that as well.
Thanks
Every User will have a unique user_id,
As you are displaying radiobuttongroup for each other user in the page, and want to access then in php,
The base way to name them in a array with indices as their user_id
<input type="radio" value="1" name="acceptance['uid1']"/>Approve<br />
<input type="radio" value="0" name="acceptance[uid1]"/>Deny
<input type="radio" value="1" name="acceptance['uid2']"/>Approve<br />
<input type="radio" value="0" name="acceptance[uid2]"/>Deny
<input type="radio" value="1" name="acceptance['uid3']"/>Approve<br />
<input type="radio" value="0" name="acceptance[uid3]"/>Deny
in php
foreach($_POST['acceptence'] as $uid=>$acpt)
{
..Do whatever
}
I hope this would help..If something else is needed plz comment..
Here you are:
<input type="radio" value="approve" name="acceptance"/>Approve<br />
<input type="radio" value="deny" name="acceptance"/>Deny
With radio buttons, they should named the same and have different values for grouping them.
UPDATED
To me, I will add row id to each radio group buttons. For example
<input type="radio" value="19" name="acceptance1"/>Approve<br />
<input type="radio" value="0" name="acceptance1"/>Deny
...
<input type="radio" value="21" name="acceptance2"/>Approve<br />
<input type="radio" value="0" name="acceptance2"/>Deny
...
<input type="radio" value="23" name="acceptance5"/>Approve<br />
<input type="radio" value="0" name="acceptance5"/>Deny
Assuming we have 5 rows per page and each approve radio button holds id of a records in database.
<?php
$approve = array();
for($i=1;$i<=5;$i++)
$approve[] = $_POST['acceptance'.$i];
?>
Then you will get what row has approve selection (i.e value !=0). Hope this helps
I try to implement the follwing code:
<?php
$yesno1="";
$yesno2="";
$option1="";
$option2="";
$option3="";
if(isset($_POST['submit'])){
$yesno1=$_POST['yesno1'];
$yesno2=$_POST['yesno2'];
$option1=$_POST['option1'];
$option2=$_POST['option2'];
$option3=$_POST['option3'];
}
?>
<form method="POST" name="contact_form"
action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>">
<input type="radio" name="yesno1" value="yes" style="outline:0;"/>Yes
<input type="radio" name="yesno1" value="no" style="outline:0;"/>No
<input type="radio" name="yesno2" value="yes" style="outline:0;"/>Yes
<input type="radio" name="yesno2" value="no" style="outline:0;"/>No
<input type="checkbox" name="option1" value="Milk"> Milk<br>
<input type="checkbox" name="option2" value="Butter" checked> Butter<br>
<input type="checkbox" name="option3" value="Cheese"> Cheese<br>
<input type="submit" value="Submit" name='submit'>
</form>
Once I click submit button, normally the value I seleted in radio and marked in the checkbox are gone, so how can I keep the value even after the click the submit button or refrsh the page using php, javascript is fine as well, would be better if any one can help me with it on both php and javascript since I am not very good on both of them, thanks for kind help:)
An example below
<input type="checkbox" name="option1" value="Milk" <?php echo ($_POST['option1'] == 'Milk' ? 'checked' : '') ?>> Milk<br>
From MDN:
The input (<input>) element is used to create interactive controls for
web-based forms.
Attributes
type
[...]
radio: A radio button. You must use the value attribute to define the
value submitted by this item. Use the checked attribute to indicate
whether this item is selected by default. Radio buttons that have the
same value for the name attribute are in the same "radio button
group"; only one radio button in a group can be selected at one time.
This is a basic HTML question. Learn to walk before you run ;-)
Is it possible to conditionally add hidden input fields into a form?
eg I have a php form that is adding values to a table and if the appleID = 1 or 2 then I want 1 added to the fruits column of my table and if appleID =3 I want 1 added to the sweets column of my table. I thought I might be able to do something like the below but it is adding all hidden values no matter what I select. Or should I approach this a different way?
<input type="radio" value="1" name="appleID" />
<input type="hidden" value="1" name="fruits" />
<input type="hidden" value="0" name="sweets" />
<input type="radio" value="2" name="appleID" />
<input type="hidden" value="1" name="fruits" />
<input type="hidden" value="0" name="sweets" />
<input type="radio" value="3" name="appleID" />
<input type="hidden" value="0" name="fruits" />
<input type="hidden" value="1" name="sweets" />
Thanks I haven't done much with php so I will need to explore that option further. Thanks for the feedback.
I was also looking at something like the below. But PHP sounds likes the better option.
change field value when select radio buttons
You can either use all values in the radio buttons (1,1,0 - 2,1,0 - 3,0,1) and split them after receiving them in your PHP script or add/delete the hidden fields via JavaScript.
Split Example:
HTML:
<input type="radio" value="1,1,0" name="appleID" />
<input type="radio" value="2,1,0" name="appleID" />
<input type="radio" value="3,0,1" name="appleID" />
PHP:
if (!empty($_POST['appleID']))
{
list($appleID, $fruits, $sweets) = explode(",", $_POST['appleID']);
}
It is better to put that logic into the PHP script instead of using Javascript - because you have to do the validation anyway.