In php I want some calculation part to be done. So I am getting all the values from variable and doing calculation. When doing calculation my formula is something like this
ceil($99.00/100)*2
but here it is showing error as $(dollar currency symbol is there). So can someone kindly tell me what is the good method of doing calculation here?
You need to learn basic PHP. You can't feed a monetary string (99 dollars and zero cents) into math operation. PHP will attempt to use $99 as a variable, and variables cannot be named with numbers.
You're basically doing
ceil (99 dollars concatenated with (zero divided by one hundred)) times two
If you're trying to do actual math with numbers, then
ceil(99/100) * 2
is all you'd need.
So basically you are dividing 99 dollars 0 cents with one hundred and multiplying the result by 2.
Try this:
<?php
$amount = 99.00;
$calculation = ($amount/100)*2;
echo $calculation;
You should append the dollar sign after you have done the calculation. Like this:
echo '$'.$calculation;
Remove the $. PHP can't calculate with anything but pure numbers, so $99.00 obviously won't work for 99 dollars.
Actually, what PHP thinks you are trying to do is have a variable (variable names start with a $). But 99 is not a valid variable name. Then PHP thinks you want to concatenate that variable with the result of 0 / 100 (concatenation is done with ..
Related
I'm using minus php query to calculate and find out two variables difference. Here is the code i'm using to calculate
Example
$v1="13.240";
$v2="0";
echo $v1 - $v2;
When calculation gets completed, the zero at the end of variable gets stripped eg (13.24), which in right scenario should have been 13.240. I do not understand how to fix this issue.
Both are same, but if you need that badly, then you can use number_format() to keep number 3 decimal places,
<?php
$v1="13.240";
$v2="0";
echo number_format($v1 - $v2, 3);
?>
DEMO: https://3v4l.org/FV1Or
I am trying to make this calculation in php but is giving me wrong result. I think that is right.
And if i do 5000.00 - 100.10 it works, but i want the 5,000.00 to work too.
This is my code:
To create the 5,000.00 i have used number_format(5000, 2).
Aswell to the 100.10
$total = $value1 - $value2;
echo $total;
?>
$total = -95.00
I am trying to make this calculation in php but is giving me wrong result. I think that is right.
And if i do 5000.00 - 100.10 it works, but i want the 5,000.00 to work too.
Please Help...
If you want to do arithmetic on number, you can't have the thousands separator (,). What's happening is 5,000.00 is being read as 5 (it stops interpreting it as a number as soon as it hits the comma) and then you're getting 5 - 100.10 which is -95.10 (I'm thinking you left off the .10 in your example.
You'll need to convert first:
$value1 = floatval(str_replace(',', '', $original_value1))
$value2 = floatval(str_replace(',', '', $original_value2))
I'm assuming here that you have them as strings originally. These remove the comma separator.
It sounds like you're confusing rendering in the UI with calculations.
It's perfectly reasonable for a user to see currencies rendered according to their locale rules (e.g. a String "$1,000.00" in USA), but the calculations in the back need to done on a floating point number (e.g. 1000.0).
So you have to be able to convert back and forth between them. You can't make arithmetic operations work on a String. Better to parse the String to a float, do the operations, then convert that back to String for rendering.
Maybe the question is simple, but I can't find the answer.
What I need to do is to round number to 2 places after comma.
Im using this:
round(($data/$count*100), 2)
And when I get number like:
60.36036036036012 and : 37.83783783783808 is OK, because it's: 60.36 and 37.84
But why this:
1.8018018018018036
Is rounded to this:
1.8000000000000003
How to round always to 2 places, after comma?
You should get 1.8 unless you use something like old PHP version with some sort of related bugs. Still, if you want to see 1.80 you need to format output string, otherwise trailing zero will be stripped by default. The most flexible approach would be to use sprintf() formatting, like this:
$val = 1.8000000000000003;
printf("%.02f", round( $val, 2 ));
which would produce
1.80
The key is "%.02f" which means you want to format (f)loating point value, with two digits after dot, padded with 0 when needed (like this case).
See the sprintf() docs for more about available formatting possibilites.
Use PHP NumberFormatter class http://es.php.net/manual/es/class.numberformatter.php
I have the following line of code in javascript:
(Math.random() + "") * 1000000000000000000
which generates numbers like:
350303159372528000
I tried the same thing in PHP with this:
rand()*1000000000000000000
Which returns:
2.272e+21
I need to use PHP as the number generated will be stored as a SESSION variable and will be used by JavaScript later on.
How do I get PHP to force the number to be an int rather than a float?
EDIT PHP seems to struggle with this.
Would it work if I just generated the rand number in PHP saved it to the SESSION and then done the multiplying by 1000000000000000000 in JavaScript?
How would I go about this?
I'd recommend calling
PHP_INT_MAX
To see if your PHP installation can handle an integar that large. I'm guessing it can't which is why it is knocking it down to scientific notation.
I'd suggest converting your result to an int:
intval(rand()*1000000000000000000)
That said, see Kolink and Jeremy1026 answers for precision issues. If you only need an unique identifier, see Truth's answer.
Update: if you're using strings to represent your numbers, don't want or can't use an arbitrary precision library, and don't stricly need perfecly fair random numbers, you could generate smaller numbers and concat them together:
strval(rand()*999999999 + 1) . strval(rand()*1000000000)
(The +1 is to avoid a leading zero in your result; note also that your number will never have a single digit, but every other number is possible)
For a random number with (exactly) 18 digits, you can also use str_pad in the 2nd part, to fill it with leading zeros:
strval(rand(100000000,999999999)) .
str_pad(strval(rand(0,999999999)), 9, "0", STR_PAD_LEFT)
If you need a unique identifier (which is what it looks like you're trying to do), please use PHP's uniqid() function.
floor() / ceil() / round() / (int) / intval() will convert the number to int.
Also, rand() takes two arguments. If ints are supplied - it will return an integer
And printf() should take care of printing in the format you wish (printf('%d', $int) should do the trick)
In the end I solved the issue like this:
<?php
error_reporting(0);
function RandNumber($e){
for($i=0;$i<$e;$i++){
$rand = $rand . rand(0, 9);
}
return $rand;
}
echo RandNumber(18);
// Outputs a 18 digit random number
?>
my script calculates a number X by dividing two other numbers, A by B.
X=A/B
when i use number_format(A,2) on A before calculating X, i get a very odd number. Actual figures:
1,045.00 / 5 = 0.2
but if i don't use number_format on A before the division, i get the correct answer. Is number_format somehow making A into a non-number?
1045 / 5 = 209
number_format should be used only while pretty printing the number. Its return value should not used in calculation as you did.
Example:
If $A = 1045;
then number_format($A,2) will be 1,045.00 now if you treat 1,045.00 as a number it will be 1 as comma and remaining char will be ignored and 1/2 is 0.5 which you are getting.
You want round(A, 2), not number_format() which is for string representations (hence named "format").
The docs show that number_format returns a string. Have you tried casting the result of number_format() to a numeric type before your mathematical manipulation?
I had similar issues. It could be better if we use number format dec_point and thousand_separator parameters. you could use number_format($number, 2, '.', ''); It will help to remove your thousand separator
number_format makes it into a string with commas between thousands, and the comma will be confusing the divisor into thinking that's the decimels based on your locale.