im making an notification system, and i can't get them outputted.
I have following code:
public function getNotification() {
$sth = $this->dbh->prepare("SELECT n.to_uid as `notif_to_uid`, n.status as `notif_status`, n.time as `notif_time`, u.id as `user_id`, u.name as `user_name` FROM notifications n INNER JOIN users u ON u.id = n.to_uid WHERE u.id = :uid n.type = 'friendrequest'");
$sth->execute(array(
':uid' => $_SESSION['uid']
)
);
if($notifications = $sth->fetchAll(PDO::FETCH_OBJ)) {
foreach($notifications as $notification) {
echo 'New notification ect. ect.';
}
}
}
My tables looks like this:
CREATE TABLE `notifications` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`from_uid` int(11) NOT NULL,
`to_uid` int(11) NOT NULL,
`type` enum('friendrequest','gameinvite','update') NOT NULL,
`status` enum('unseen','seen') NOT NULL,
`time` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
PRIMARY KEY (`id`)
);
CREATE TABLE `users` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`email` varchar(255) NOT NULL,
`password` varchar(155) NOT NULL,
`firstname` varchar(255) NOT NULL,
`lastname` varchar(255) NOT NULL,
`gender` varchar(255) NOT NULL,
`points` varchar(255) DEFAULT '0',
PRIMARY KEY (`id`)
);
Right now it isnt outputting anything, and the connection to the db does work.
Try to display query errors by
$execute = $sth->execute(array(
':uid' => $_SESSION['uid']
)
);
if(!$execute){
print_r($sth->errorInfo());
}
I see you have lost "AND" or "OR" here
WHERE u.id = :uid n.type = 'friendrequest'
Related
I am trying to add the direction, left and right member to direct but the problem now here is that I am only able to fetch one data (left_mem) instead of both left_mem and right_mem.
$query = $MySQLi_CON->query("select * from users where enroller_id='".$enroller_id_n."' ");
$direct = array();
if($query){
while ($row = $query->fetch_array()) {
$enroller_id3 = $row['enroller_id'];
$direct[] = $row['direction'];
}
}
if ($direct == "left_mem")
{
echo "success";
}
else {
echo "fail";
}
This is my database
CREATE TABLE `users` (
`user_id` int(11) NOT NULL,
`user_name` varchar(25) NOT NULL,
`user_email` varchar(255) NOT NULL,
`user_pass` varchar(255) NOT NULL,
`enroller_id` varchar(25) NOT NULL,
`enrolled_id` varchar(25) NOT NULL,
`direction` varchar(25) NOT NULL DEFAULT 'avail'
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
INSERT INTO `users` (`user_id`, `user_name`, `user_email`, `user_pass`, `enroller_id`, `enrolled_id`, `direction`);
ALTER TABLE `users`
ADD UNIQUE KEY `user_id` (`user_id`);
ALTER TABLE `users`
MODIFY `user_id` int(11) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=1;
Use in_array to see if both values exist:
if (in_array('left_mem',$direct) && in_array('right_mem',$direct) )
first, sorry for my English ...
what i want is to select from two SQL tables and then make them in a specific order , like in forums ...
i have two table, topic and users, i want to select from both of them a putt author info next to his topic
here is the SQL of Topic and users
CREATE TABLE IF NOT EXISTS `topics` (
`id` int(11) NOT NULL,
`id2` int(11) NOT NULL,
`title` varchar(256) NOT NULL,
`message` longtext NOT NULL,
`author_id` int(11) NOT NULL,
`timestamp` int(11) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
CREATE TABLE IF NOT EXISTS `users` (
`id` bigint(20) NOT NULL,
`username` varchar(255) NOT NULL,
`password` varchar(255) NOT NULL,
`email` varchar(255) NOT NULL,
`avatar` varchar(255) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
and the php code might look like this
<?php
$sql = mysql_query(' MySQL query ... ');
while($row = mysql_fetch_array($sql)) {
echo '<p>'.$row['username']'<br>';
echo $row['message'].'<br></p>';
}
?>
is there any way to do it ??
As I understood, what you are looking for is the correct SQL statement to execute. The following simple solution will.
<?php
$sql = mysql_query('SELECT users.username, topics.message FROM `users` INNER JOIN topics ON topics.author_id = users.id');
while($row = mysql_fetch_array($sql)) {
echo '<p>'.$row['username']'<br>';
echo $row['message'].'<br></p>';
}
?>
SELECT * FROM `users` INNER JOIN topics ON topics.author_id = users.id'
I have three tables
User > id, username, name, age, sex, location
User Post > id, user_id, description, image, postime, location
Follow > id, user_id, follow_id, status
In User table I will be having all the user information.
In User Post table I will be having all the post related information.
I want to display my own post and also post of the users I am following
The query I had written for this situation is
SELECT
u.username,
u.name,
u.profile_pic,
up.*
FROM user u, user_post up
WHERE (up.user_id = $user_id OR up.user_id IN
(SELECT user_id
FROM follow WHERE follow_id=$user_id)), $user_id)
AND description='' group by id order by postime desc
I feel the query is wrong, can anyone help me
CREATE TABLE IF NOT EXISTS `user` (
`id` int(10) NOT NULL AUTO_INCREMENT,
`name` varchar(50) NOT NULL,
`username` varchar(30) NOT NULL,
`password` varchar(1000) NOT NULL,
`email` varchar(100) NOT NULL,
`age` varchar(100) NOT NULL,
`gender` varchar(100) NOT NULL,
`city` varchar(100) NOT NULL,
`state` varchar(100) NOT NULL,
`country` varchar(100) NOT NULL,
`profile_pic` varchar(100) NOT NULL,
`deviceToken` char(64) DEFAULT NULL,
PRIMARY KEY (`id`)
)
CREATE TABLE IF NOT EXISTS `user_post` (
`id` int(10) NOT NULL AUTO_INCREMENT,
`description` varchar(100) NOT NULL,
`image` varchar(100) NOT NULL,
`location` varchar(100) NOT NULL,
`postime` timestamp NULL DEFAULT CURRENT_TIMESTAMP,
`user_id` int(20) NOT NULL,
PRIMARY KEY (`id`)
)
CREATE TABLE IF NOT EXISTS `follow` (
`id` int(100) NOT NULL AUTO_INCREMENT,
`user_id` int(100) NOT NULL,
`follow_id` int(100) NOT NULL,
`date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`status` varchar(20) NOT NULL DEFAULT 'Pending',
PRIMARY KEY (`id`)
)
This is the same answer I posted yesterday:
SELECT u.username,u.name,u.profile_pic, up.*
FROM user u JOIN user_post up
ON up.user_id = u.id
WHERE
(up.user_id = $user_id
OR
up.user_id IN (
SELECT user_id
FROM follow
WHERE follow_id=$user_id
)
)
AND description=''
ORDER BY postime DESC
As you didn't tell about the relations between user and follower it might enough to switch follow_idand user_id:
SELECT u.username,u.name,u.profile_pic, up.*
FROM user u JOIN user_post up
ON up.user_id = u.id
WHERE
(up.user_id = $user_id
OR
up.user_id IN (
SELECT follow_id
FROM follow
WHERE user_id=$user_id
)
)
AND description=''
ORDER BY postime DESC
With this code I'm getting news from the database and order it by column "views":
<?php
$getnewsinfo = mysql_query("SELECT * FROM news ORDER BY views DESC LIMIT 5");
while($newsinforow = mysql_fetch_array($getnewsinfo))
{
$newsid = $newsinforow['id'];
$title = $newsinforow['title'];
$author = $newsinforow['author'];
$date = date('d.m.Y', $newsinforow['date']);
$picture = $newsinforow['picture'];
$picture_desc = $newsinforow['picture_desc'];
$category = $newsinforow['category'];
$text = $newsinforow['text'];
?>
Now I want to order the news by views and by the number of comments, but I have no idea how.
Here is my database structure :
CREATE TABLE IF NOT EXISTS `news` (
`id` int(11) NOT NULL auto_increment,
`views` int(11) NOT NULL default '0',
`title` varchar(255) NOT NULL,
`author` varchar(255) NOT NULL,
`date` varchar(255) NOT NULL,
`picture` varchar(255) NOT NULL,
`picture_desc` varchar(255) NOT NULL,
`category` varchar(255) NOT NULL,
`text` text NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=6 ;
CREATE TABLE IF NOT EXISTS `news_comments` (
`id` int(11) NOT NULL auto_increment,
`news_id` int(11) NOT NULL,
`name` varchar(255) NOT NULL,
`email` varchar(255) NOT NULL,
`website` varchar(255) NOT NULL,
`text` text NOT NULL,
`date` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=16 ;
I also want to ask you... do you have any comments on the code and database structure ?
Try this sql
SELECT n.*,count(nc.id) as cnt FROM news as n, news_comments as nc where n.id = nc.news_id group by nc.news_id ORDER BY views DESC,cnt DESC LIMIT 5
I am developing a cooking recipe-website and i want to create a recipe finder based on the used incredients.
My current finder only works with 3 ingredients right.
The Finder should return the right recipe(s) based on the used incredients (should work with 1-n*)
My Tables:
CREATE TABLE IF NOT EXISTS `INGREDIENTS` (
`ingredients_id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(45) NOT NULL,
PRIMARY KEY (`ingredients_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=17 ;
CREATE TABLE IF NOT EXISTS `INGREDIENTS_POS` (
`ingredients_pos_id` int(11) NOT NULL AUTO_INCREMENT,
`ingredients_id` int(11) NOT NULL,
`ingredients_unit` varchar(20) NOT NULL,
PRIMARY KEY (`ingredients_pos_id`),
KEY `ingredients_detail_fk` (`ingredients_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=17 ;
CREATE TABLE IF NOT EXISTS `RECIPES` (
`recipes_id` int(11) NOT NULL AUTO_INCREMENT,
`title` varchar(50) COLLATE utf8_bin NOT NULL,
`text` varchar(2000) COLLATE utf8_bin NOT NULL,
`count_persons` int(11) NOT NULL,
`duration` int(11) NOT NULL,
`user_id` int(11) NOT NULL,
`date` datetime NOT NULL,
`accepted` int(11) NOT NULL DEFAULT '0',
PRIMARY KEY (`recipes_id`),
KEY `recipes_user_fk` (`user_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_bin AUTO_INCREMENT=88 ;
CREATE TABLE IF NOT EXISTS `RECIPES_POS` (
`recipes_pos_id` int(11) NOT NULL AUTO_INCREMENT,
`recipes_id` int(11) NOT NULL,
`ingredients_id` int(11) NOT NULL,
`ingredients_value` int(11) NOT NULL,
PRIMARY KEY (`recipes_pos_id`),
KEY `recipe_pos_rec_id` (`recipes_id`),
KEY `recipes_pos_ingredient_fk` (`ingredients_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=58 ;
My buggy Solution (doesn't support count from 1-n):
<?php
include 'db_connect.php';
$q = urldecode(mysql_real_escape_string($_GET['q']));
$parameter = explode ('$',$q);
$var = 0;
//print_r($parameter);
foreach($parameter as $ing)
{
//echo $ing;
$sql = "SELECT ingredients_id FROM INGREDIENTS WHERE name='".$ing."'";
$result = mysql_query($sql,$db) or exit('{"Data":null,"Message":null,"Code":500}');
$row = mysql_fetch_array($result);
$arr_id[$var] = $row['ingredients_id'];
$var++;
}
//print_r($arr_id);
$sql = "SELECT r.recipes_id FROM RECIPES r, RECIPES_POS rp WHERE r.recipes_id = rp.recipes_id ";
foreach($arr_id as $id)
{
$sql .= "AND rp.ingredients_id =".$id . " ";
}
//echo $sql;
$result = mysql_query($sql,$db) or exit('{"Data":null,"Message":null,"Code":500}');
mysql_close($db);
$rec;
while($row = mysql_fetch_array($result))
{
//echo "test";
$_GET['id'] = $row['recipes_id'];
$rec= include('get_recipe_byID.php');
}
//print_r(mysql_fetch_array($result));
if (count($arr_id) == 0)
{
echo '{"Data":null,"Message":null,"Code":404}';
die();
}
?>
I need a better solution for that chase.
Maybe SQL itself will help me to find the right recipes
thx
That query helped me a lot:
select r.recipes_id
from RECIPES r
inner join RECIPES_POS rp on r.recipes_id = rp.recipes_id
where rp.ingredients_id in (4, 6)
group by r.recipes_id
having count(distinct rp.ingredients_id) = 2