PHP/MySQL query not working with no error - php

I have written that seems to not be working, but MySQL does not return any error. It is supposed to get data from database1.table to update database2.table.column
<?php
$dbh1 = mysql_connect('localhost', 'tendesig_zink', 'password') or die("Unable to connect to MySQL");
$dbh2 = mysql_connect('localhost', 'tendesig_zink', 'password', true) or die("Unable to connect to MySQL");
mysql_select_db('tendesig_zink_dev', $dbh1);
mysql_select_db('tendesig_zink_production', $dbh2);
$query = " UPDATE
tendesig_zink_dev.euid0_hikashop_product,
tendeig_zink_production.euid0_hikashop_product
SET
tendesig_zink_dev.euid0_hikashop_product.product_quantity = tendesig_zink_production.euid0_hikashop_product.product_quantity
WHERE
tendesig_zink_dev.euid0_hikashop_product.product_id = tendesig_zink_production.euid0_hikashop_product.product_id";
if (mysql_query($query, $dbh1 ))
{
echo "Record inserted";
}
else
{
echo "Error inserting record: " . mysql_error();
}
?>

The manual page for mysql_error() mentions this about the optional parameter you're omitting:
link_identifier
The MySQL connection. If the link identifier is not
specified, the last link opened by mysql_connect() is assumed. If no
such link is found, it will try to create one as if mysql_connect()
was called with no arguments. If no connection is found or
established, an E_WARNING level error is generated.
So it's reading errors from $dbh2, which is the last connection you've opened. However, you never run any query on $dbh2:
mysql_query($query, $dbh1 )
Thus you get no errors because you are reading errors from the wrong connection.
The solution is to be explicit:
mysql_error($dbh1)
As about what you're trying to accomplish, while you can open as many connections as you want, those connections won't merge as you seem to expect: they're independent sessions to all effects.
All your tables are on the same server and you connect with the same users, there's absolutely no need to even use two connections anyway.

You can't just issue a cross-database update statement from PHP like that!
You will need to execute a query to read data from the source db (execute that on the source database connection: $dbh2 in your example) and then separately write and execute a query to insert/update the target database (execute the insert/update query on the target database connection: $dbh1 in your example).
Essentially, you'll end up with a loop that reads data from the source, and executes the update query on each iteration, for each value you're reading from the source.

I appreciate everyone's help/banter, here is what finally worked for me.
<?php
$dba = mysqli_connect('localhost', 'tendesig_zink', 'pswd', 'tendesig_zink_production') or die("Unable to connect to MySQL");
$query = " UPDATE
tendesig_zink_dev.euid0_hikashop_product, tendesig_zink_production.euid0_hikashop_product
SET
tendesig_zink_dev.euid0_hikashop_product.product_quantity = tendesig_zink_production.euid0_hikashop_product.product_quantity
WHERE
tendesig_zink_dev.euid0_hikashop_product.product_id = tendesig_zink_production.euid0_hikashop_product.product_id";
if (mysqli_query($dba, $query))
{
echo "Records inserted";
}
else
{
echo "Error inserting records: " . mysqli_error($dba);
}
?>

Related

moving my sql database localhost to live server

i want to move my sql database and i have exported and imported mysql.sql file from localhost to live server and now i m not getting the files and content from that database. what i do ? i did make sure connection to database if fine and successful
here's my page http://shooop23.byethost7.com
<?php
$db = mysqli_connect('','','','');
if(mysqli_connect_errno()){
echo'Database Connection Failed with following errors: '. mysqli_connect_errno();
die();
}
?>
Once you have successfully established a connection to MySQL, you need to perform a query specifying what you want to retrieve and then subsequently retrieve it.
The following example uses mysqli_fetch_row
You should explore the documentation to learn the basics.
$db = mysqli_connect('localhost', 'my_user', 'my_password', 'my_db');
if(mysqli_connect_errno()){
echo'Database connection failed with the following error: '.mysqli_connect_errno();
exit;
}
if ($result = mysqli_query($db, "SELECT MyCol1,MyCol2 FROM MyTable")) {
while ($row = mysqli_fetch_row($result)) {
echo"{$row[0]} - {$row[1]}<br>");
}
mysqli_free_result($result);
}
mysqli_close($db);
$db = mysqli_connect('localhost', 'my_user', 'my_password', 'my_db');
$sql="SELECT * FROM login";
here i connected and stored my database and set a sql command (which is now a string) into these two veriables.
if(mysqli_connect_errno()){
echo'Database connection failed with the following error: '.mysqli_connect_errno();
exit;
}
this is to check if the database is correctly connected, if not then it will show some errors.
$result = mysqli_query($db,$sql);
here i put the database and the sql command to run my query.
while($row = mysqli_fetch_array($result)){
echo $row['username'];
}
here finally outputting the usernames(username is one of the column in my table in this case) which matched with that query
i will suggest This Sql site to get a better understanding on sql queries and try to improve the secuirty because this is the basic point where hackers try to inject their attact most offenly.
Note : If your table's in the database are empty then it will not able to fetch anything

Error message: Database Query failed

For some reason, the following code inside the query works in my MySQL command console, yet when I try to run it as a Query in PHP, something keeps going wrong and I'm not sure what. Here is the code I've done so far.
//2. Perform database query
$query = "SELECT skills.element_id, content_model_reference.element_id, element_name FROM skills, content_model_reference WHERE (skills.element_id = content_model_reference.element_id)";
$result = mysql_query($query);
//Tests if there was a query error
if(!$result){
die("Database query failed.");
}
Is there something preventing the code that worked in MySQL (The line with SELECT) from working, or is my syntax somehow wrong?
EDIT: So it's saying I didn't select a database. Yet I thought I had. Here is the code above it:
//1. Create a database connection
$dbhost = "host"; //Host: Can be either an IP address, or a domain (like google.com).
$dbuser = "user";//User: The user that is connecting to the database.
$dbpass = "pass";//Password: This is the password that the user is using.
$dbname = "db";//Name: This is the name of the database.
$connection = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname);//The value, 'handle,' is the connection.
//Test if connection occurred. Die ends the program/php, and in this case, also prints a message
if(mysqli_connect_errno()){
die("Database connection failed: ".
mysqli_connect_error().
" (". mysqli_connect_errno() . ")"
);
}
Like I said, the error message I am getting is pertaining only to the query, the server is fine with my database connection.
You're using mysqli_* for the connection, but you're using mysql_* for the QUERY... don't think you can do that, has to be one or the other (MYSQLI_ preffered). Also the query should be:
$result = mysqli_query($connection,$query);

My php script is not using given username/pass/host rather using root#localhost (password: NO)

Got a problem! Though I found almost similar threads but none helped :(
I've written a php script to fetch the number of registered users from my MySQL database. The script is working great in my localhost; it is using the given username,pass and host name which are "root", "root", and "localhost" respectively, but the script is not using the given username/pass/host rather using root#localhost (password: NO) in Live server.
In the Live server I created a MySQL user, set an different password, and hostname there is of course not localhost. I updated the script with my newly created mysql users data. BUT, whenever I run the script, I see that the script is still using "root", "root", and "localhost"!!
take a look at the script:
//database connection
$conn = mysql_connect( "mysql.examplehost.com", "myusername", "mypass" );
$db = mysql_select_db ("regdb",$conn); //Oops, actually it was written this way in the script. I misstyped it previously. now edited as it is in the script.
//Query to fetch data
$query = mysql_query("SELECT * FROM regd ");
while ($row = mysql_fetch_array($query)):
$total_regd = $row['total_regd'];
endwhile;
echo $total_regd;
-- Some says to change the default username and pass in the config.ini.php file located in phpMyAdmin directory. Would this help?? I didn't try this because either my hosting provider didn't give me privilege to access that directory (because I am using free hosting for testing scripts) or I simply didn't find it :(
Please help....
Foreword: The MySQL extension is marked as deprecated, better use mysqli or PDO
Though you store the connection resource in $conn you're not using it in your call to mysql_query() and you're not checking the return value of mysql_connect(), i.e. if the connection fails for some reason mysql_query() "is free" to establish a new default connection.
<?php
//database connection
$conn = mysql_connect( "mysql.examplehost.com", "myusername", "mypass" );
if ( !$conn ) {
die(mysql_error()); // or a more sophisticated error handling....
}
$db = mysql_select_db ("regdb", $conn);
if ( !$db ) {
die(mysql_error($conn)); // or a more sophisticated error handling....
}
//Query to fetch data
$query = mysql_query("SELECT * FROM regd ", $conn);
if (!$query) {
die(mysql_error($conn)); // or a more sophisticated error handling....
}
while ( false!=($row=mysql_fetch_array($query)) ):
$total_regd = $row['total_regd'];
endwhile;
echo $total_regd;
edit: It looks like you're processing only one row.
Either move the echo line into the while-loop or (if you really only want one record) better say so in the sql statement and get rid of the loop, e.g.
// Query to fetch data
// make it "easier" for the MySQL server by limiting the result set to one record
$query = mysql_query("SELECT * FROM regd LIMIT 1", $conn);
if (!$query) {
die(mysql_error($conn)); // or a more sophisticated error handling....
}
// fetch data and output
$row=mysql_fetch_array($query);
if ( !$row ) {
echo 'no record found';
}
else {
echo htmlspecialchars($row['total_regd']);
}
First of all:
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Not connected : ' . mysql_error());
}
// make foo the current db
$db_selected = mysql_select_db('foo', $link);
if (!$db_selected) {
die ('Can\'t use foo : ' . mysql_error());
}
What is your mysql_error()? :)

PHP SQL Truncate

I'm having a problem trying to truncate the 'requestID' field from my requests table.
This is my code.
<?php
include 'mysql_connect.php';
USE fypmysqldb;
TRUNCATE TABLE requestID;
echo "Request ID table has been truncated";
?>
I'm using server side scripting so no idea what error is coming back.
Anyone got an idea?
You aren't executing queries, you're just putting SQL code inside PHP which is invalid. This assumes you are using the mysql_*() api (which I kind of suspect after viewing one of your earlier questions), but can be adjusted if you are using MySQLi or PDO.
// Assuming a successful connection was made in this inclusion:
include 'mysql_connect.php';
// Select the database
mysql_select_db('fypmysqldb');
// Execute the query.
$result = mysql_query('TRUNCATE TABLE requestID');
if ($result) {
echo "Request ID table has been truncated";
}
else echo "Something went wrong: " . mysql_error();
Take a look at the function mysql_query which performs the query execution. The code to execute a query should look something like this.
$link = mysql_connect('host', 'username', 'password') or die(mysql_error());
mysql_select_db("fypmysqldb", $link) or die(mysql_error());
mysql_query("TRUNCATE TABLE requestID", $link) or die(mysql_error());
mysql_close($link);

php and mysql help, working with multiple database

I need to work on multiple database, and below is my current code.
Following code seems to be very very slow and having issues with multiple connection while I view the mysql connection list.
So can anyone let me what's wrong with the code and help me to correct the issues and faster performance.
$dbHost="localhost";
$dbUser="user";
$dbPass="pass";
$db_1="database1";
$db_2="database2";
$connect=mysql_connect($dbHost, $dbUser, $dbPass);
if (!$connect)
die("Error Connecting to MYSQL");
mysql_select_db($db_1, $connect)
or die("Error Connecting to Database 1");
$remainingDataCount="25000";
$getData=mysql_query("select * from TABLE where FIELD1='data' && FIELD2>'date' && FIELD3='NO'");
$loop=0;
while ($eachData=mysql_fetch_array($getData)) {
$loop++;
$UNIQUE_ID=$eachData['id'];
$UNIQUE_DATA1=$eachData['FIELD4'];
$DATA2=$eachData['FIELD5'];
$responseMessage="some text here";
$currentTimeStamp=date('Y-m-d H-i-s');
if ($loop>$remainingDataCount) {
break;
} else {
$insertQuery=mysql_query("insert into ".$db_2.".TABLE values('', '$UNIQUE_DATA1', '$DATA2', '$responseMessage', '$currentTimeStamp')");
if ($insertQuery==true) {
$updateQuery=mysql_query("update ".$db_1.".TABLE set FIELD1='YES', FIELD2='$responseMessage', FIELD3='$currentTimeStamp' where FIELD4='$UNIQUE_DATA1'");
if ($updateQuery==false) {
mysql_query("delete from ".$db_2.".TABLE where FIELD1='$UNIQUE_DATA1'");
}
}
}
}
Open up two connections with mysql_connect(), select the correct database on both and then use the optional link identifier parameter with mysql_query() to choose which database to execute your queries on.
mysql_query ( string $query [, resource $link_identifier ] )
Edit: Also, you might want to have a look at Mysqli (ee.php.net/manual/en/book.mysqli.php) so you can use prepared statements which would probably speed up the looped insert dramatically.
SQL statements in a loop is a performance issue number one.
I think that you could use INSERT SELECT instead of loop

Categories