Mysql update table column from one database to another - php

Question

I am working on a script that updates from:
tendesig_zink_production | euid0_hikashop_product | product_quantity
to:
tendesig_zink_dev | euid0_hikashop_product | product_quantity
I have to do this because our inventory numbers are stored on the production instance. so before pushing a new version from our dev instance i have to update the dev's inventories from production prior to the push. I am a lot rusty with my mySQL, this is what i have so far I need to know what the proper query would be though.
<?php
$host1="localhost"; // destination
$base1="tendesig_zink_dev";
$user1="tendesig_zink";
$password1="1,&#GZAWiB5z";
$host2="localhost"; //source
$base2="tendesig_zink_production";
$user2="tendesig_zink";
$password2="1,&#GZAWiB5z";
$conection1 = #mysql_connect($host1, $user1, $password1)
or die("Error reaching destination<br>".mysql_error()." nr eroare: ".mysql_errno());
print "Succesfuly connected 1! <br>";
$Db1 = #mysql_select_db($base1, $conection1)
or die("Error reaching destination database:<br>" . mysql_error(). "<br>" . mysql_errno());
print "Database1 reached!<br>";
$conection2 = #mysql_connect($host2, $user2, $password2)
or die("Error reaching source<br>".mysql_error()." nr eroare: ".mysql_errno());
print "Succesfuly connected 2!<br>";
$Db2 = #mysql_select_db($base2, $conection2)
or die("Error reaching source database:<br>" . mysql_error(). "<br>" . mysql_errno());
print "Database2 reached!!<br>";
$query = 'create table destination_table select * from second_database.source_table';
//echo "<br>".$query."<br>";
$result2 = mysql_query($query2, $conection1) or die('Query failed: ' . mysql_error().'||'.mysql_errno());
mysql_close($conection1);
mysql_close($conection2);
?>

Answer 1

Your query is wrong. You want to do something like this:
CREATE TABLE destination_database.destination_table LIKE source_database.source_table
Then run this:
INSERT INTO destination_database.destination_table
SELECT * FROM source_database.source_table
In (untested) PHP code:
$create_query = 'CREATE TABLE destination_database.destination_table LIKE source_database.source_table';
$result = mysql_query($create_query, $conection1) or die('Query failed: ' . mysql_error().'||'.mysql_errno());
$insert_query = 'INSERT INTO destination_database.destination_table SELECT * FROM source_database.source_table';
$result = mysql_query($insert_query , $conection1) or die('Query failed: ' . mysql_error().'||'.mysql_errno());