In a current project I have hit a wall because I need to compare two dates and find the difference between the dates (in hours), this would be easy if the server was >= 5.3, can someone help me?
I have the difference in timestamp
$diff = abs(strtotime($date1)-strtotime($date2)
but I don't know what to do next...
Thank you.
In your code $diff is the difference in seconds. You can convert the seconds to hours like this:
$hours = floor($diff / (60 * 60));
Edit: To get minutes and seconds:
$minutes = floor(($diff - $hours * 60 * 60) / 60);
$seconds = floor($diff - $hours * 60 * 60 - $minutes * 60);
Try this
echo round((strtotime($date1) - strtotime($date2))/(60*60));
In your code $diff is in seconds.
There are 3600 seconds in an hour, so:
$date1 = "2014-07-15";
$date2 = "2014-07-17";
$diff_seconds = abs(strtotime($date1)-strtotime($date2));
$diff_hours = $diff_seconds/3600;
echo $diff_seconds.' '.$diff_hours;
Related
Hi I have a two variable in 24 hour time format and want to compute the number of hours worked. But I get negative and wrong value
I'm using PHP and here's my code
$endtime = date( 'g:i A', strtotime( $itInfo['endTime'] ) );
$startTime = date( 'g:i A', strtotime( $itInfo['startTime'] ) );
$timeDiff = (strtotime($endtime) - strtotime($startTime))/60/60;
$total = strtotime($endtime) - strtotime($startTime);
$hours = floor($total / 60 / 60);
$minutes = round(($total - ($hours * 60 * 60)) / 60);
echo "FROM ".$itInfo['startTime']." TO ".$itInfo['endTime']." (".$hours.'.'.$minutes."hours)";`
Here's the output FROM 22:00 TO 03:00 (-19.0hours) which is wrong the output should be 5 Hours.
Try this:
$timeDiff = strtotime($itInfo['endTime']) - strtotime($itInfo['startTime']);
echo substr('00'.($timeDiff / 3600 % 24),-2)
.':'. substr('00'.($timeDiff / 60 % 60),-2)
.':'. substr('00'.($timeDiff % 60),-2);
As others have stated, best to work with timestamps. But with your current code, you should be able to add this right before the echo:
if ($itInfo['startTime'] > $itInfo['endTime']) {
$hours = 24 - $hours;
}
This would be: 24 - 19 = 5.
Also, be sure to take add abs() in your $total variable as well:
$total = abs(strtotime($endtime) - strtotime($startTime));
I'm trying to get the difference between two date-times and return it as a minute. Date & Time are taken in date("Y-m-d H:i:s") format. But it seem i can't get it right. I did it
$time=date("Y-m-d H:i:s");
$time=date("2014-01-13 08:18:25");
$interval = $time->diff($login_time);
$elapsed = $interval->format(%i minutes);
echo $elapsed;
And This is showing a massage
"Call to a member function diff() on a non-object"
As I am not good enough with date formatting. So Please help me.
What is the way to go about this?
Try this:
$date1 = new DateTime('2013-01-13 04:10:58');
$datediff = $date1->diff(new DateTime('2013-09-11 10:25:00'));
echo $datediff->i;
For more details see this link : http://www.php.net/manual/en/book.datetime.php
Get difference is minutes between two dates:
$now = new DateTime;
$before = new DateTime('2014-01-10 08:18:25');
$diff = $now->diff($before);
$elapsed = $diff->days * 24 * 60 + $diff->h * 60 + $diff->i;
demo
Use the below code for getting time in all expected parameter.
$time1=date("Y-m-d H:i:s");
$time2=date("2014-01-13 08:18:25");
$seconds = strtotime($time1) - strtotime($start);
$year = floor(($seconds)/(60*60*24*365)); $months = floor($seconds /
86400 / 30 ); $week = floor($seconds / 604800); $days =
floor($seconds / 86400); $hours = floor(($seconds - ($days * 86400))
/ 3600); $minutes = floor(($seconds - ($days * 86400) - ($hours *
3600))/60); $seconds = floor(($seconds - ($days * 86400) - ($hours *
3600) - ($minutes*60)));
So far I've got this script that counts down the days and hours, but how can I make it also do minutes and seconds?
$remaining = strtotime($ActiveListing['ListingExpires']) - time();
$days_remaining = floor($remaining / 86400);
$hours_remaining = floor(($remaining % 86400) / 3600);
I thought of a solution with date():
$remaining = strtotime($ActiveListing['ListingExpires']) - time();
list($months, $days, $hours, $minutes, $seconds) = explode(" ",date("n j H i s",$remaining));
$months--;$days--;
echo "$months months - $days days - $hours hours - $minutes minutes - $seconds seconds left";
$remaining = strtotime($ActiveListing['ListingExpires']) - time();
$days_remaining = floor($remaining/60/60/24);
$hours_remaining = floor(($remaining-($days_remaining*60*60*24))/60/60);
$minutes_remaining = floor(($remaining-($days_remaining*60*60*24)-($hours_remaining*60*60))/60);
$seconds_remaining = floor(($remaining-($days_remaining*60*60*24)-($hours_remaining*60*60))-($minutes_remaining*60));
$edate = '2027-07-06 07:01:53';
$datestr = $edate;//Your date
$date=strtotime($datestr);//Converted to a PHP date (a second count)
//Calculate difference
$diff=$date-time();//time returns current time in seconds
$days=floor($diff/(60*60*24));//seconds/minute*minutes/hour*hours/day)
$hours=round(($diff-$days*60*60*24)/(60*60));
I have a cron job that runs at midnight which resets all user limits for that day. I want to display something along the lines of Your limits reset in 1 hour 14 minutes to my users. Basically a countdown until midnight (server time).
At the moment I'm using this to find midnight:
strtotime('tomorrow 00:00:00');
which returns a timestamp for when midnight rolls over, but I have no idea how to display a user friendly countdown. Is there a PHP library for this or is this pretty easy without a library?
Simply this gives you left-minutes;
$x = time();
$y = strtotime('tomorrow 00:00:00');
$result = floor(($y - $x) / 60);
But you need to filter $result;
if ($result < 60) {
printf("Your limits rest in %d minutes", $result % 60);
} else if ($result >= 60) {
printf("Your limits rest in %d hours %d minutes", floor($result / 60), $result % 60);
}
Since you're looking for a rough estimate, you could leave out the seconds.
$seconds = strtotime('tomorrow 00:00:00') - now();
$hours = $seconds % 3600;
$seconds = $seconds - $hours * 3600;
$minutes = $seconds % 60;
$seconds = $seconds - $minutes *60;
echo "Your limit will reset in $hours hours, $minutes minutes, $seconds seconds.";
It is quite easy, just a little mathematics along with finding the difference in seconds between then and now.
// find the difference in seconds between then and now
$seconds = strtotime('tomorrow 00:00:00') - time();
$hours = floor($seconds / 60 / 60); // calculate number of hours
$minutes = floor($seconds / 60) % 60; // and how many minutes is that?
echo "Your limits rest in $hours hours $minutes minutes";
I use this function to set a time date("Y-m-d H:i:s", strtotime("+2 minutes"). Now I want to compare that value with the current time to find the amount of seconds it's left.
For example compare: $next_action = 2011-01-16 18:03:00 and $now = 2011-01-16 18:01:23. To find the amount of seconds.
strtotime can convert mysql timestamps to unix timestamps. so you just convert both of them to UNIX timestamps and subtract one from other, and you'll get the difference in seconds.
$next_action = "2011-01-16 18:03:00";
$now = "2011-01-16 18:01:23";
echo strtotime($next_action)-strtotime($now);
Why did you convert them to "Y-m-d H:i:s" in the first place? Unix timestamps are much easier to work with.
$start_time = date("Y-m-d H:i:s", strtotime("+2 minutes"));
$time_diff = (time() - strtotime($start_time)); // difference in seconds
$seconds = $time_diff % 60;
$minutes = ($time_diff - $seconds) % (60 * 60);
$hours = ($time_diff - ($minutes * 60) - $seconds) / (24 * 60 * 60);
Untested, but it would probably go something like this.