Get column value (name) from a Foreign Key reference in PHP - php

Question

I've got two databases fruit and fruit-prices (for arguement's sake).
In fruit there are two columns id | name
Fruit table
id | name
1 | Apple
2 | Banana
In fruit_prices there are three columns id | fruit_id | price where fruit_id is a FOREIGN KEY reference.
id | fruit_id | price
1 | 1 | £2.00
2 | 2 | £3.00
Now I have a PHP function that will print out a table row and cells with the information from the database but currently if I am printing two fruits out my table looks like this.
Name | Price
1 | £2.00
2 | £3.00
PHP Code:
$query = mysqli_query($conn, "SELECT * FROM fruits ");
while($row = mysqli_fetch_assoc($query)) {
$name = $row['fruit_id']; //for comma separation
$price = $row['price'];
echo "<tr>";
echo "<td>" .$name. "</td>" .
"<td>" .$price. "</td>";
echo "</tr>";
}
Is there an elegant way I can retrieve the name of the fruit (i.e. 1 = Apple, 2 = Banana). Rather than using the unique ID of each fruit.
So then my table will look like this
Name | Price
Apple | £2.00
...
I hope this makes sense? I'm new to RD concepts. This is a very simple example and does not reflect my entire project so I'm just wondering if this is achievable?

Answer 1

This can be done by joining both the tables.Change your sql query with below one.I think it will solve your problem.
"SELECT fruit.name,fruit_prices.price FROM fruit,fruit_prices WHERE fruit_prices.fruit_id = fruit.id";

Answer 2

You would want to use a join and specify the columns you would like to select.
SELECT f.name, fp.price FROM fruit as f
JOIN fruit-prices as fp ON f.id=fp.fruit_id;

Answer 3

It is achievable using JOIN:
SELECT * FROM fruits a JOIN fruits-prices b ON b.fruit_id = a.id
For more friendly column names you can add column aliases and use them further.

Answer 4

You say they are in two databases, but I think it might just be two tables. If so:
select * from fruit f
left outer join fruit-prices fp
on f.id = fp.fruit_id
The left outer join ensures that if a fruit doesn't have a price it will be returned will null as the price. If you don't want that replace it with an inner join.

Answer 5

Use of JOIN does what you need.
"SELECT `p`.`price`, `f`.`name` FROM `fruit_prices` `p`
JOIN `fruits` `f` ON `f`.`id` = `p`.`fruit_id`"
Be wary - use of SELECT * here will lead to an error, as both tables have an id field, and the query will break.

Answer 6

You need a join between the tables,
SELECT f.name, fp.price
FROM fruit f
INNER JOIN fruit_price fp ON f.id = fp.fruit_id

Answer 7

Well, you need to take a look to SQL Joins
query = mysqli_query($conn, "SELECT FRUIT.name,FRUIT_PRICES.price FROM fruits INNER JOIN FRUIT_PRICES ON FRUIT.id = FRUIT_PRICES.fruit.id");
while($row = mysqli_fetch_assoc($query)) {
$name = $row['name']; //for comma separation
$price = $row['price'];
echo "<tr>";
echo "<td>" .$name. "</td>" .
"<td>" .$price. "</td>";
echo "</tr>";
}
What I wrote means : "Select FRUIT.Name,FRUIT_PRICES.price in FRUIT AND FRUIT_PRICES, considering that FRUITS.id is related to FRUIT_PRICES.id_fruit"

Answer 8

Suggestion : You can have a single table viz fruits with 3 columns id, fruit_name, price.
for your table structure :
SELECT fruits.id, name, price
FROM fruits, fruit-prices
WHERE fruit_id=fruits.id;