When I use CI to send email with attachment there is no error but send with no attachment and contents.If it send without attachment email send with contents.
$this->load->library('email');
$this->email->to('$tomail');
$this->email->cc('$cmail');
$this->email->from('noreply#******8');
$this->email->subject('Gift Voucher');
$this->email->set_mailtype('html');
$data['content'] = 'Please find the attachment.<br> Reach us on : *****';
$data['footer'] = '© ' . date("Y") . '********/ All rights reserved';
$msg = $this->load->view('includes/mail_template', $data, TRUE);
$path = base_url('assets/uploads/giftpurchase/giftvoucher_'.$payid);
$this->email->attach($path);
$this->email->message($msg);
$this->email->send();
base_url() is provide you HTTP path, you should use there Directory path for mail attachment
Change
$path = base_url('assets/uploads/giftpurchase/giftvoucher_'.$payid);
// http://www.sitename.com/assets/uploads/giftpurchase/giftvoucher_.....
to
$path = {HERE_ROOT_PATH} 'assets/uploads/giftpurchase/giftvoucher_'.$payid;
// /var/www/html/assets/uploads/giftpurchase/giftvoucher_.....
PS : getcwd() function is provide current working directory, you can use to get working dir path
$path = getcwd(). 'assets/uploads/giftpurchase/giftvoucher_'.$payid;
If You want to attach file from Your server You need to use path to file from Your filesystem, not from Your web-root
There're 2 useful constants in CodeIgniter:
FCPATH -> path to front controller (index.php at top level (above /system/))
APPPATH -> path to /application/ folder
$path = FCPATH.'assets/uploads/giftpurchase/giftvoucher_'.$payid;
Related
I have a method which is responsible for downloading a file.
$attachment = KnowledgeDatabaseAttachments::where('id', $id)->first();
if ($attachment) {
$filesPath = storage_path('app/knowledge_database_attachments');
return response()->download($filesPath . '/' . $attachment->physical_name);
}
After download, when I try to open it (this is an error message from my OS):
Could not load image '88ebb9c0-11af-11e8-b056-b1568dc848cb.jpg'.
Error interpreting JPEG image file (Not a JPEG file: starts with 0x0a 0xff)
File is saved like so:
$filesPath = storage_path('app/knowledge_database_attachments');
$physicalName = Uuid::generate() . '.' . $file->getClientOriginalExtension();
$file->move($filesPath, $physicalName);
KnowledgeDatabaseAttachments::create([
'knowledge_database_id' => $page->id,
'name' => $file->getClientOriginalName(),
'physical_name' => $physicalName
]);
File exist in that directory, and the downloaded file has correct size and name.
Funny part is that I can also create a newsletter which will include this file. When I create newsletter file is copied:
$extension = explode('.', $attachment->physical_name)[1];
$newPhysicalName = Uuid::generate() . '.' . $extension;
File::copy($attachment->getPathAttribute(), $storagePath . DIRECTORY_SEPARATOR . $newPhysicalName);
SendMailAttachments::create([
'mail_id' => $mail->id,
'filename' => $attachment->name,
'physical_name' => $newPhysicalName,
]);
And then, in the newsletter edit view I can as well download this file, with this (identical as above) method:
$attachment = SendMailAttachments::where('mail_id', $mailId)->where('filename', $attachmentName)->first();
if ($attachment) {
$filesPath = storage_path('app/sendmail_attachments');
return response()->download($filesPath . '/' . $attachment->physical_name);
}
And it works - file is correctly downloaded and I can open it.
Why I cant open file downloaded with first method?
I use Laravel 5.1 and Ubuntu 16.04 (if that matters).
EDIT
When I run file command on a downloaded file the result is data. When I run it on file in storage, the result is correct JPEG image data.
Try to add headers with response
View docs
$headers = array('Content-Type' => ' image/jpeg');
$filesPath = storage_path('app/knowledge_database_attachments');
return response()->download($filesPath,$attachment->physical_name,$headers);
Note: Symfony HttpFoundation, which manages file downloads, requires the file being downloaded to have an ASCII file name.
The problem is that I have something being output before the image stream.
Temporary solution:
$response = response()->download($filesPath . '/' . $attachment->physical_name);
ob_end_clean();
return $response;
Permanent solution:
Find whats being output and remove it.
Found this here: https://laracasts.com/discuss/channels/laravel/image-is-being-thrown-as-a-white-blank-image?page=1
I asked a similar question previously, but didn't know how to quite ask before. Below I created a new directory based on the username I grabbed from a signup form. I just need the inclusion of the template file copied over to the new directory that was just made. The outcome I'm getting is an inclusion of the file in the directory that's up one level. The new directory is created with the username but doesn't contain the template file in its directory. I spent hours on this so I wouldn't have to bother you guys again. What am I doing wrong?
$folder = DIRECTORY_SEPARATOR; // adds the forward slash
$name = $user->username; // included from a login script I purchased
$thisdir = "../associate"; // desired directory
$folderPath = $thisdir . $folder . $name;
$file = copy('../associate/joshua/career.php', $folderPath.'.php'); // copy this file into new directory
if(!file_exists($folderPath)){
mkdir($folderPath);
chmod($folderPath,0777);
}
file_put_contents(realpath($folderPath) .'/'. $folderPath, $file);
});
If I understand you well, you want to copy career.php template from /associates/ folder to /associates/username/ folder
$rootfolder = $_SERVER['DOCUMENT_ROOT'];
$name = $user->username;
$thisdir = "/associate/";
$folderPath = $rootfolder.$thisdir.$name."/"; // desired directory
if(!is_dir($folderPath)){
mkdir($folderPath, 0777, true);
}
$currentfile = $rootfolder.$thisdir.'joshua/career.php';
$destination = $folderPath.'career.php';
copy($currentfile, $destination); // copy this file into new directory
I have created a directory in Wordpress uploads folder for end user to bulk upload photos via ftp. Images are numbered 1.jpg, 2.jpg... etc. I've generated the image urls successfully, but now I want to test for empty urls - i.e. if "8.jpg" doesn't exist, show a placeholder image from the theme's images folder instead.
I'm trying to use file_exists(), but this returns false every time and always displays the placeholder image. Any suggestions would be appreciated.
<?php while ( have_posts() ) : the_post();
// create url to image in wordpress 'uploads/catalogue_images/$sale' folder
$upload_dir = wp_upload_dir();
$sub_dir = $wp_query->queried_object;
$image = get_field('file_number');
$image_url = $upload_dir['baseurl'] . "/catalogue_images/" . $sub_dir->name . "/" . $image . ".JPG"; ?>
<?php if(file_exists($image_url)){
echo '<img src="' . $image_url . '" alt="" />';
} else {
//placeholder
echo '<img src="' . get_bloginfo("template_url") . '/images/photo_unavailable.jpg" alt="" />';
} ?>
<?php endwhile; ?>
The PHP file_exists function mainly expects an internal server path to the file to be tested. This is made obvious with the example.
Fortunately, we see that wp_upload_dir() gives us several useful values:
'path' - base directory and sub directory or full path to upload directory.
'url' - base url and sub directory or absolute URL to upload directory.
'subdir' - sub directory if uploads use year/month folders option is on.
'basedir' - path without subdir.
'baseurl' - URL path without subdir.
'error' - set to false.
I've bolded what we want to use. Using these two values, you have to generate two variables, one for the external URL and one for the internal file path:
$image_relative_path = "/catalogue_images/" . $sub_dir->name . "/" . $image . ".JPG";
$image_path = $upload_dir['basedir'] . $image_relative_path;
$image_url = $upload_dir['baseurl'] . $image_relative_path;
Then use file_exists($image_path) instead of file_exists($image_url).
Note
As with the PHP notes on PHP >= 5.0.0, you can indeed use file_exists with some URLs, however the http:// protocol is not supported for the stat() function (which is what file_exists uses.)
You have to use an internal path for checking if a file exists.
So use $upload_dir['path'] instead $upload_dir['baseurl']
[path] - base directory and sub directory or full path to upload
directory.
http://codex.wordpress.org/Function_Reference/wp_upload_dir
I am uploading a file using Codeigniter's File Uploading Library and trying to insert the URL into the database. Codeigniter only supplies the server_path when using $this->upload->data(), which isn't usable for displaying the image to users.
I could normally just do something like base_url('uploads) . '/' . $data['file_name'] but I am storing the images in a folder for each post.
For example, I am getting C:/xampp/htdocs/site/uploads/32/image.jpg as the full_path, how can I convert this to http://mysite.com/uploads/32/image.jpg
The only thing that comes to mind is using a regular expression, but I feel like there has to be PHP function or Codeigniter function to help with this?
How can I convert the server path into the correct URL?
You can use $_SERVER['HTTP_HOST']; to get the url. Using the ID for your post, you can construct your path like so:
$url = "http://" . $_SERVER['HTTP_HOST'] . "/" . $id . "/" . basename($data['file_name']);
the basename() function returns everything after the last / in your path.
you only need to save the filename to the database and just use the post id and filename:
$url = "http://mysite.com/uploads/" . $postID . "/" . $fileName;
to get the file name use: How to get file name from full path with PHP?
<?php
$path = "C:/xampp/htdocs/site/uploads/32/image.jpg";
$file = basename($path); // $file is set to "image.jpg"
$file = basename($path, ".jpg"); // $file is set to "image"
?>
In CodeIgniter you should use $config['base_url']
You can use the ENVIRONMENT to setup different base_url, for example:
switch(ENVIRONMENT)
{
case 'development':
$config['base_url'] = 'http://localhost/';
break;
case 'testing':
$config['base_url'] = 'http://testing.server.com/';
break;
default:
$config['base_url'] = 'http://liveserver.com/';
}
See config.php
Now simply replace your local path with the base_url, str_replace should do the job (documentation here)
$newpath = str_replace("C:/xampp/htdocs/site/", $config['base_url'], $localpath);
Also, if you're interested in getting parts of the path, you could use explode (documented here) with / to create an array with every "section" of your path
$pathElements = explode('/', $localpath);
In this case, $pathElements[0] is C:, $pathElements[1] is xampp, etc...
Uploadify is a jQuery plugin that allows the easy integration of a multiple (or single) file uploads on your website. It requires Flash and any backend development language. An array of options allow for full customization for advanced users, but basic implementation is so easy that even coding novices can do it.
I wanted to ask if It is possible to sends out a link of a file that has just been uploaded wioth the e-mail notification of Uploadify.
Here is the code for uploadify.php :
<?php
if (!empty($_FILES)) {
$tempFile = $_FILES['Filedata']['tmp_name'];
$targetPath = $_SERVER['DOCUMENT_ROOT'] . $_REQUEST['folder'] . '/';
$targetFile = str_replace('//','/',$targetPath) . $_FILES['Filedata']['name'];
// $fileTypes = str_replace('*.','',$_REQUEST['fileext']);
// $fileTypes = str_replace(';','|',$fileTypes);
// $typesArray = split('\|',$fileTypes);
// $fileParts = pathinfo($_FILES['Filedata']['name']);
// if (in_array($fileParts['extension'],$typesArray)) {
// Uncomment the following line if you want to make the directory if it doesn't exist
// mkdir(str_replace('//','/',$targetPath), 0755, true);
move_uploaded_file($tempFile,$targetFile);
echo "1";
// } else {
// echo 'Invalid file type.';
// }
}
//define the receiver of the email
$to = 'admin#admin.com';
//define the subject of the email
$subject = 'Test email';
//define the message to be sent. Each line should be separated with \n
$message = "Hello World!\n\nThis is my first mail.";
//define the headers we want passed. Note that they are separated with \r\n
$headers = "From: webmaster#example.com\r\nReply-To: webmaster#example.com";
//send the email
$mail_sent = #mail( $to, $subject, $message, $headers );
//if the message is sent successfully print "Mail sent". Otherwise print "Mail failed"
echo $mail_sent ? "Mail sent" : "Mail failed";
?>
Your script is vulnerable to filename collisions. You're the uploaded using the original name provided by the user. If the same filename is used more than once, you'll overwrite previous versions with the new one.
As well, you're blindly using a form value to specify a location to store the upload. What happens if someone specifies "../../../../../../../../../etc" for the folder and "passwd" for the filename? Or on a Windows server "../../../../../../../../windows/system32" and "ntoskrnl.exe"? If the webserver's misconfigured as to what user ID it's running on, you've just opened the machine to a complete remote compromise. But even if they don't want to compromise the system, they'll be able to trash any file within your site's document root with ease.
Having said that, if you want to embed a link to directly download the file, you'll have to build an HTML-formatted email, or hope the mail client can auto-linkify text that looks like URLs. Building HTML mails for use with the mail() function is a serious pain. I use PHPMailer for my projects. It works nicely and allows you to build any kind of email you'd like.
Something like:
<?PHP
$fileURL = 'http://' . $_SERVER['HTTP_HOST'] . $_REQUEST['folder'] . '/' . $_FILES['Filedata']['name'];
// ...
$message = "You can download the file from: {$fileURL}";
// ...
$mail_sent = #mail( $to, $subject, $message, $headers );
//...