I thought I could find loads of examples on how to do this but nothing I find tells me how to get the values in PHP.
Say I have this code:
$query = "SELECT name, age FROM people WHERE id = 2";
$result = mysql_query($query);
How do I get the data from $result?
Pseudo code:
$name = $result['name'];
$age = $result['age'];
Did you try this?
$query = "SELECT name, age FROM people WHERE id = 2";
$result = mysql_query($query);
$row = mysql_fetch_assoc($result);
echo $row['name'];
echo $row['age'];
You need to get a row from the result first. You can get a number-based array using mysql-fetch-row or an associative array using mysql-fetch-assoc.
$query = "SELECT name, age FROM people WHERE id = 2";
$result = mysql_query($query);
$row = mysql_fetch_assoc($result);
$name = $row['name'];
$age = $row['age'];
To note: the mysql functions are deprecated. You should use mysqli or PDO instead.
Related
$sql = "SELECT temail FROM teacherusers WHERE tfullname='$teachername' limit 1";
$result = mysql_query($sql);
$value = mysql_fetch_object($result);
$teacheremail2 = $value->temail;
echo $teacheremail2;
echo $teacheremail2 returns nothing.
$teachername is valid and i have checked multiple times.
It should be a two-dimensional array , you need
$value[0]->temail
The result of mysql_fetch_object($result) is an object(stdClass).
The explanation of object(stdClass) ican be found at this link
$sql = "SELECT temail FROM teacherusers WHERE tfullname='$teachername' limit 1";
$result = mysql_query($sql);
while ($value = mysql_fetch_object($result))
{
$teacheremail2 = $value->temail;
echo $teacheremail2;
}
First off, you'll want to run the query directly against your database to ensure that the query returns some kind of result.
Secondly, if that works, you'll want to echo $value directly to check that you are getting results back on the webpage.
Then you can check if temail is a field of $value
$sql = "SELECT temail FROM teacherusers WHERE tfullname='$teachername' limit 1";
$result = mysql_query($sql);
while ($value = mysql_fetch_object($result))
{
$teacheremail2 = $value->temail;
echo $teacheremail2;
}
hope this help
I am trying to retrieve the data stored in an unknown number of mySQL database rows and display them using HTML. At the moment I can display data from one row.
Each row has a unique id number, I was planning to iterate through by comparing this number to the variable counter. But it would then leave me with the issue of displaying the results in HTML. At the moment I am just echoing variables that contain data from the rows. However what I want to create is a HTML list that increases in length depending on how many rows are in the table.
Here is my current PHP code for retrieving a row from the database is:
$sql = "SELECT * FROM project_tasks WHERE project_name='$proj_name' AND task_id='$counter'";
$query = mysqli_query($db_conx, $sql);
$row = $query->fetch_assoc();
$task_id = $row["task_id"];
$proj_name = $row["project_name"];
$task_name = $row["task_name"];
$task_importance = $row["task_importance"];
$task_description = $row["task_description"];
$task_deadline = $row["task_deadline"];
$task_members = $row["task_members"];
$task_budget = $row["task_budget"];
At the moment I am just displaying some of the results in HTML using this code:
<div id="inner_container">
<?php echo "$task_id $proj_name $task_name $task_deadline"; ?>
</div>
$sql = "SELECT * FROM project_tasks WHERE project_name='$proj_name' AND task_id='$counter'";
$query = mysqli_query($db_conx, $sql);
while($row = $query->mysqli_fetch_assoc()) {
$task_id = $row["task_id"];
$proj_name = $row["project_name"];
$task_name = $row["task_name"];
$task_importance = $row["task_importance"];
$task_description = $row["task_description"];
$task_deadline = $row["task_deadline"];
$task_members = $row["task_members"];
$task_budget = $row["task_budget"];
echo "$task_id $proj_name $task_name $task_deadline";
}
Since you have built an associative array using fetch_assoc all you need to do is loop through that array. The OO example on http://php.net/manual/en/mysqli-result.fetch-assoc.php should get you what you need. A quick example:
$sql = "SELECT * FROM project_tasks WHERE project_name='$proj_name' AND task_id='$counter'";
$query = mysqli_query($db_conx, $sql);
echo '<div id="inner_container">';
while ($row = $query->fetch_assoc()) {
$proj_name = $row["project_name"];
$task_name = $row["task_name"];
$task_deadline = $row["task_deadline"];
echo "$task_id $proj_name $task_name $task_deadline";
};
/* free result set */
$row->free();
echo '</div>;
I am creating a function that will retrieve an id number from a table with multiple columns, put it in a variable which i want to use to send as a "claims number" in an email to a claimant and also echo on a confirmation screen. Here's what I have so far.
$sql = "SELECT id FROM warranty_claim where lname=$lname";
$result = mysql_query($sql);
$claim_id = $result;
$result = mysql_fetch_array(mysql_query($sql));
$claim_id = $result['id'];
Supposing you are sure that you will receive 1 row.
$sql = "SELECT id FROM warranty_claim where lname=$lname";
$result = mysql_query($sql);
$c = mysql_fetch_assoc($result);
$claim_id = $c['lname'];
NB*: And get ready for a lecture. Someone is going to tell you that mysql is depracated.
Start using MySQLi or PDO (recommended).
Try :
$sql = "SELECT id FROM warranty_claim where lname=$lname";
$result = mysql_query($sql);
$row = mysql_fetch_row($result);
$claim_id = $row[0];
or
$sql = "SELECT id FROM warranty_claim where lname=$lname";
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$claim_id = $row['id'];
}
$row = mysql_fetch_array($result);
$claim_id = $row['id'];
please note that you should also check for errors (e.g. if($result === FALSE)). Also, there are other ways to fetch data - I recommend looking at mysql_fetch_array, mysql_fetch_row, mysql_fetch_assoc and mysql_fetch_object
Also, don't rely on the statement always returning exactly one row - make sure that the result is as expected: mysql_num_rows
Give this a try:
$sql = "SELECT id FROM warranty_claim where lname='".$lname."'";
$result = mysql_query($sql);
$objResult = mysql_fetch_array($result);
$claim_id = $objResult['id'];
I want to echo out one field from my database so I do not want to use a while loop.
The database table is called index and the field that I want to echo is called title.
What is wrong with this code as the output is just blank.
$result = mysql_query("SELECT * FROM index");
$row = mysql_fetch_array($sql);
echo $row['title'];
You're passing a wrong argument to mysql_fetch_array(). Modify it as follows.
$result = mysql_query("SELECT * FROM index");
$row = mysql_fetch_array($result);
echo $row['title'];
You need to pass $result and not $sql with the mysql_fetch_array()function.
Try:
$row = mysql_fetch_array($result);
print_r($row); ///see what you get
The fastest solution would be mysql_result
$result = mysql_query('SELECT title FROM index LIMIT 1');
$field = mysql_result($result, 'title');
You may want to add LIMIT or check your database against something
$result = mysql_query("SELECT * FROM index WHERE id='$someid' LIMIT 1");
I'm trying to get a single result from my database, just one name.
I tried using;
$row = mysql_fetch_array(mysql_query("SELECT * FROM persons WHERE id = '$id'"));
echo $row['name'];
But that din't work, any other way to simply show only one result?
Thanks in advance!
[EDIT:]
(I'm using PHP 5.3)
<?php
include("connection.php");
$id = $_GET['deletid'];
$result = mysql_query("SELECT * FROM persons WHERE id = '$id' LIMIT 1");
if(!$result){
echo mysql_error();
}
if ($row = mysql_fetch_array($result)){
echo $row['name'];
}
echo "<p>id:$id</p>";
?>
If you need just the name and you need just one result you should rewrite your query as follow:
$row = mysql_fetch_array(mysql_query("SELECT name FROM persons WHERE id = '". (int) $id ."' LIMIT 1"));
Now to get the result you should just get it with a
$row['name'];
EDIT
Now that you posted your entire code i got what's wrong: You are deleting that result before getting its name. Basically you delete that user and then you attempt to get its name.
EDIT
<?php
include("connection.php");
if (empty($_GET['deleteid'])) {
exit('"deleteid" is empty');
}
$id = mysql_real_escape_string($_GET['deletid']);
$result = mysql_query("SELECT name FROM persons WHERE id = '". (int) $id ."' LIMIT 1");
if(!$result){
echo mysql_error();
}
$row = mysql_fetch_assoc($result); // for just one result you don't need of any loop
echo $row['name'];
echo "<p>id:". htmlspecialchars($id) ."</p>";
?>
try
$row = mysql_fetch_array(mysql_query("SELECT name FROM persons WHERE id = ". (int) $id));
echo $row['name'];