laravel redirection to splash page during testing - php

I've spent too many hours messing with this
I'm just starting with laravel and started a new project.
I want to be able to have a system where a certain users can access the site while it is in development. The rest of the public gets forwarded to the splash page.
I plan to create a secret route that sets a toggle in the session. If this toggle is set then the user can use the entire system. Else they are redirected to the splash page.
The issue is I cannot get it to redirect. I have been adding the code in the bootstrap->start.php file. The standard
header('location:www.thesite.com')
starts doing funny things that I do not understand.
If I run
return Redirect::to(htmlspecialchars_decode($url))
it returns the error:
BadMethodCallException
Method [run] does not exist on Redirect.
I have absolutely no idea what is going on or how to fix it.
Why is the redirection script returning an error? Is start.php not the correct location?
If so how can achieve my objective within laravel?

You should do this in your before filter in app/filters.php like so:
App::before(function($request){
if(!$request->is('splash') && Input::get('allow') != '1')
{
return Redirect::to('/splash');
}
);
Where /splash is your splash screen route. You can then do http://www.example.com?allow=1 to bypass the splash screen.
The before filter is a function that is run before every single route in your application.
Let me know if this works for you!

Related

MODx - If not logged in, redirect to a different page

I am in the process of building a website (via MODx), and I don't want "non-logged in" users to be able to see the home page, but instead be redirected to an "under construction" page.
In my snippet, this is what I have so far:
<?php
if (! $modx->user->hasSessionContext($modx->context->get('key')) ) {
$modx->sendRedirect('https://google.com');
} else {
return '';
}
Sadly, this appears to not do anything, regardless of whether or not the user is logged in. (It apppears to be a problem with the second line, the actual redirect worked fine when I tested it)
I am unable to figure out what is wrong, and any help is greatly appreciated!
The snippet that is in the page is [[!notloggedin]]
These are right out of Bob's guides, but basically what you want to do is check to see if the user has an ID or username, if not, they are not logged in.
You probably want to do a bit of digging and see if you can implement your redirect in a plugin rather than a snippet possibly an onRequest event - so you are not rendering the page/resource before you discover that the user needs to be redirected.
There are various methods. One easy method is to use this code:
if ($modx->user->get('username') == '(anonymous)') {
/* user is not logged in */
}
Here is the official method for seeing if the user is logged in to the current context:
if ($modx->user->hasSessionContext($modx->context->get('key'))) {
/* user is logged in */
}
If you know the name of the current context (e.g., web), you can use this method. The name of the context is required:
if $modx->user->isAuthenticated('web') {
/* user is logged in to web context */
}
If your site is simply not yet ready to be publicly available, MODX already allows for this.
See the following System Settings:
site_status
site_unavailable_message
site_unavailable_page
Alternatively, just set all your resources to 'unpublished', except for your custom error page. Logged in users will still be able to view all resources.

CodeIgniter redirect not working?

Ok I have a controller named Login and have an index() function that displays the view user/login. I build the urls with user/login, but with the redirect, I'm doing this:
redirect('/user/login/');
But I've also tried redirect('/login/');
How comes my login won't load? It keeps giving me a 404 error...
I've also tried ('/login/index') and ('/login')
It sounds like you have only one controller, Login, with only one page, index, in it, so why do you need a redirect? Are you just trying to get your index page to show your login view? If so you do that with something like:
$this->load->view('path/to/view');
you can try redirect(site_url("login"));, if you haven't changed the relevant routing in your CI install it will take you to the login controller (and the index() method by default)
edit: I misread the question
Ah.. sorry, my bad. I have an if statement that isn't even letting it get to the redirect part... I'm sorry!

How can I deny users access to parts of my Backbone App if they have not logged in?

So I've got a Backbone application + web homepage. Right now, if you login to my website, I create a global object with your user details from the database. However, you can still just hit one of the routes in the application directly.
How should I handle users who are not "logged in" and redirect them to a "you must login page"?
Is this a standard operation? Basically, I have a REST url setup that returns just
{ sessionId: [php-session-id-here] }
If they are logged in, it would return something more like this:
{
sessionId: [php-sess-id],
userId: [user-id-from-db],
firstName: [f-name],
lastName: [l-name]
}
Ideas? Thanks!
What I've done in the past is to include on every page along with jQuery (actually, added to the jQuery file) an extension on the AJAX method to check for a custom code that I send when a user isn't logged in. When that value was seen it redirected the user to the login page regardless of what was going down.
This was because that site had a time out on login, so a user could get logged out while sitting on a page and then the AJAX request would just fail. If you don't have a timeout on the login the odds of ever seeing this issue are slim. Just ignore requests that come from users that aren't logged in.
If you need help coding this, start here: Extending Ajax: Prefilters, Converters, and Transports.
Really shouldn't require anything as complex as pseudo-code:
JS needs to do some AJAX, so JS talks to server
PHP checks for login if needed
If not logged in, send back the abort message (I used a converter to catch a "notLoggedIn" dataType. However this could also be done with a transport, they are just more complex.)
JS sees the abort message and does a window.location redirect rather than return AJAX message.
If you want, you could load a lightbox with a login form and send that via AJAX to PHP where a re-login can take place, if you remember the AJAX attempt that failed you can send it again after login. Then the user doesn't even need to leave the page to log back in.
If you're using jQuery, you can set a global ajaxSetting that allows you to do certain things upon certain http codes. Some pages I read recommend adding to your JSON a url field to point to where to login, but I figure that's just up to you. So the only modifications you'd need to implement what I've mentioned is 1. change the http code to something reasonable like 401 (unauthorized) and implement the http code handler. But I wouldn't call this standard, I'd just say that's what several people have done (including myself).
<?php
function IsLoggedIn()
{
if(isset($_SESSION['id'])) // Change that to what you want
{
return 1;
}
else
{
return 0;
}
}
?>
Then in your code, you could use something like:
if(isLogged()){ header('Location: http://google.com'); }

Wrong return url in Yii framework

I have used Yii::app()->user->returnUrl but it always redirect me to localhost/index.php. Is there any particular configuration or some pieces of code that other programs that I must write? If you have another solutions let me know it.
#aslingga, can you please explain what you're trying to do with returnUrl? Are you just trying to get back to where you were after logging in, or are you using it somewhere else?
This is from the Yii documentation:
Redirects the user browser to the
login page. Before the redirection,
the current URL (if it's not an AJAX
url) will be kept in returnUrl so that
the user browser may be redirected
back to the current page after
successful login. Make sure you set
loginUrl so that the user browser can
be redirected to the specified login
URL after calling this method. After
calling this method, the current
request processing will be terminated.
In other words, if the page you're trying to request requires authentication, the URI of the page you're on gets stored in a session variable. Then, once you've logged in, it takes you back to that page.
One way I'd recommend troubleshooting is to do a print_r($_SESSION); just to make sure the returnUrl is actually being stored. Then you'll be able to check if index.php is being stored as returnUrl or if you're just being redirected there for some reason.
Looking at the CWebUser methods getState and setState might also be helpful.
I know this question is old but maybe this will help someone out since I didn't couldn't find a decent answer anywhere.
How getReturnUrl works
Setting a default return URL for your Yii app requires a bit of customization. The way it works out of the box is that you specify the default return URL each time you call it:
Yii::app()->user->getReturnUrl('site/internal');
The idea being that if a user were to visit a page that requires authentication, they will get redirected to the login page, but not before the site running
Yii::app()->user->setReturnUrl('site/visitedpage');
Now when the user logs in, they will be returned to the page they intended to go to.
While I like that functionality, having to set the default return URL each time is dumb. If you want to change the default return URL, you have to go find it throughout your code. I suppose you could set the value in a site parameter and call
Yii::app()->user->getReturnUrl(Yii::app()->params['defaultReturnUrl']);
I don't think I have to explain why that solution is annoying too.
My Solution
So when getReturnUrl is called without any parameters, it returns either '/index.php' or just '/'. This is fine in some cases, but not always. This is better IMO.
First, extend the CWebUser class and add the following extras
class WebUser extends CWebUser {
// default return URL property
public defaultReturnUrl;
// override the getReturnUrl method
public function getReturnUrl($defaultUrl=NULL) {
if ($defaultUrl === NULL) {
$defaultReturnUrl = $this->defaultReturnUrl;
}
else {
$defaultReturnUrl = CHtml::normalizeUrl($defaultUrl);
}
return $this->getState('__returnUrl',$defaultReturnUrl);
}
}
Now, let's add a couple items to the user component array.
'user' => array(
'class' => 'WebUser',
'defaultReturnUrl' => 'site/internal'
)
Not only does this allow you to set a default return URL in the config, but also maintains the ability to set a different default return URL and use the setReturnUrl functionality.
I think, you must set it:
Yii::app()->user->setReturnUrl('controller/action');

Zend scripts not setup correctly I think

When Ive created a new controller, ie in this case Authenticate, Ive also created the folder and file application/views/scripts/authentication/index.phtml
Not a problem when hitting the url http://dev.local/authentication/ but when calling any action ie http://dev.local/authentication/login, I get the error below.
Message: script 'authentication/login.phtml' not found in path (C:\Sites\application\views\scripts\)
Regardless of any changes Im going to make to the login action it shouldnt automatically ask for a new page right? or am I wrong?
By default, each action requires its corresponding view (phtml page). If you want to disable a view/layout for a given action, you can use the following code :
$this->_helper->layout()->disableLayout();
$this->_helper->viewRenderer->setNoRender(true);
EDIT in response to the comment:
I usually don't need to do this, because the actions I have that don't need a view script are redirected/forwared to other actions. For example, once your user is authenticated (i.e. when /authentication/login succeeds), you can redirect him to the home page (or whatever page he was trying to access. Similarly, if the login failed, I simply set an error message in the view and forward to the action that shows the login form.
The only actions for which I use the above code is for actions that are typically called using AJAX and that output some JSON code, for example.

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