I'm working on a project in which I need to match two dates. One stored in the database and one is the current date time. I've decided to use unix timestamp for this. I'll convert these both values to unix timestamp and would then compare.
I used the below code to generate the unixtimestamp, but it gave me the following error :-
A non well formed numeric value encountered
I have gone through half a dozen questions on stack overflow, but none helped my case.
$date =date("Y-m-d H:i:s A");
echo mktime($date);
What might be the solution ?
You are using the wrong function, you don't want to use mktime but strtotime
$date =date("Y-m-d H:i:s A");
echo strtotime($date);
But the format of the date you are passing isn't currently supported by PHP. You'll have to drop A (PM and AM).
To drop the AM/PM:
echo strtotime(substr($date, 0, -2));
If you want to generate the current unix time, just use mktime() with no arguments. Check out http://php.net/manual/en/function.mktime.php
Related
I want to parse the date 1938 1938+02:00 using date() & strtotime().
My code:
echo date("Y", strtotime("1938+02:00"));
gives me as result "2014"..
What am i doing wrong?
For something like this just get the first four characters of the string. No need to work with dates and such:
echo substr('1938+02:00', 0, 4);
Demo
But if you insist on using date functionality you'll need to use DateTime::createFromFormat() as that date string is not a standard format.
$date = DateTime::createFromFormat('YP', '1938+02:00');
echo $date->format('Y');
Demo
date("Y"); only return the year. That's what the Y does.
See the Manual page for date for other options.
EDIT
Another thing to consider, is that timestamps only go back to 1970. That's what a timestamp is (the number of seconds since 1970).
So, that's going to give you a negative value for the timestamp.
Your date string is not in an acceptable format. here is a list of acceptable formats for strtotime
I want to change given date and time or date only into Unix time.
I tried like this:
mktime("Jan-12-2012 2:12pm");
But it’s not working:
Even in PHP documentation I looked at many examples and many of them don’t consist the matter that I want.
And when I try:
$user_birthday=$_POST["user_birthday"];
$db_user_birthday=empty($user_birthday)?"":mktime($user_birthday);
$_POST["user_birthday"] was given value from form that is jan-12-2012 2:12pm
it show error like this:
Notice: A non well formed numeric value encountered in C:\Program
Files (x86)\Ampps\www\admin\index.php on line 76
How do I fix it or display time into Unix?
Use this one:
date("M-d-Y h:i:s", strtotime($user_birthday));
You should be using strtotime instead of mktime:
Parse about any English textual datetime description into a Unix
timestamp.
So your code would be this:
$user_birthday = $_POST["user_birthday"];
$db_user_birthday = empty($user_birthday) ? "" : strtotime($user_birthday);
Then you can process that date like this to get it formatted as you want it to:
echo date("M-d-Y h:ia", $db_user_birthday);
So your full code would be this:
$user_birthday = $_POST["user_birthday"];
$db_user_birthday = empty($user_birthday) ? "" : strtotime($user_birthday);
echo date("M-d-Y h:ia", $db_user_birthday);
Note I also added spaces to your code in key points. The code will work without the spaces, but for readability & formatting, you should always opt to use cleaner code like this.
You should take a look at this answer: convert date to unixtime php
Essentially, you have mixed up mktime() with strtotime(). strtotime() allows you to parse an English textual string into a Unix timestamp. mktime() constructs a unix datetime based on integer arguments.
For example (again taken from the question above)
echo mktime(23, 24, 0, 11, 3, 2009);
1257290640
echo strtotime("2009-11-03 11:24:00PM");
1257290640
In my PHP script I've got a function handling birthdays like so:
$dateTime = \DateTime::createFromFormat('U', $time);
The problem is that this returns false with negative $time numbers (i.e. dates before 1-1-1970). In the PHP docs there's a comment saying that indeed
Note that the U option does not support negative timestamps (before
1970). You have to use date for that.
I'm unsure of how to use Date to get the same result as DateTime::createFromFormat() gives though. Does anybody have a tip on how to do this?
If you just need to format a UNIX timestamp as a readable date, date is simple to use:
// make sure to date_default_timezome_set() the timezone you want to format it in
echo date('Y-m-d H:i:s', -12345);
If you want to create a DateTime instance from a negative UNIX timestamp, you can use this form of the regular constructor:
$datetime = new DateTime('#-12345');
Hallo, I want to find the difference between today and another date,
convert todays date into unix time format here
<?php
echo '1st one'.strtotime(date("d.m.Y")).'<br>';
echo '2nd one'.strtotime(date("m.d.Y")).'<br>';
?>
The first echo is producing some value, but not the second one. What is the bug in it...please help..
strtotime makes assumptions based on the date format you give it. For instance
date("Y-m-d", strtotime(date("d.m.Y"))) //=> "2010-09-27"
date("Y-m-d", strtotime(date("m.d.Y"))) //=> "1969-12-31"
Note that when given an invalid date, strtotime defaults to the timestamp for 1969-12-31 19:00:00, so when you end up with an unexpected date in 1969, you know you're working with an invalid date.
Because strtotime is looking for day.month.year when you use . as the delimiter, so it sees "9.27.2010" as the 9th day of the 27th month, which obviously doesn't exist.
However, if you change it to use / as the delimiter:
date("Y-m-d", strtotime(date("d/m/Y"))) //=> "1969-12-31"
date("Y-m-d", strtotime(date("m/d/Y"))) //=> "2010-09-27"
In this case, strtotime expects dates in month/day/year format.
If you want to be safe, Y-m-d is generally a good format to use.
It's worth pointing out that strtotime() does accept words like "today" as valid input, so you don't need to put a call to date() in there if all you want is today's date. You could just use strtotime('today');.
Come to think of it, a simple call to time(); will get you the current time stamp too.
But to actually answer the question, you need to consider that d.m.Y and m.d.Y are ambiguous - if the day of the month is less than the 12th, it is impossible to tell which of those two date formats was intended. Therefore PHP only accepts one of them (I believe it uses m/d/Y if you have slashes, but for dots or dashes it assumes d-m-Y.
If you're using strtotime() internally for converting date formats, etc, there is almost certainly a better way to do it. But if you really need to do this, then use 'Y-m-d' format, because it's much more universally reliable.
On the other hand, if you're accepting date input from your users and assuming that strtotime() will deal with anything thrown at it, then sadly you're wrong; strtotime() has some quite big limitations, of which you've found one. But there are a number of others. If you plan to use strtotime() for this sort of thing then you need to do additional processing as well. There may also be better options such as using a front-end Javascript date control to make it easier for your users without having to rely on strtotime() to work out what they meant.
strtotime does not consider 09.27.2010 to be a valid date...
You could check it like this:
<?php
// will return false (as defined by the docs)
echo var_dump(strtotime("09.27.2010"));
?>
The function expects to be given a string containing a US English date format and will try to parse that format into a Unix timestamp. US time format is : MM DD YYYY
look here for the Information about which formats are valid http://www.php.net/manual/en/datetime.formats.php. But what do you mean with deference between 2 dates? You mean the Timespan between 2 dates?
echo (time() - strotime("- 2 days")) . " seconds difference";
Something like that?
strtotime would not take the d.m.y format. good way is Y-m-d
To change 2009-12-09 13:32:15 to 09/12/2009
here:
echo date("d/m/Y", strtotime('2009-12-09 13:32:15'))
You can use strtotime to get the timestamp of the first date, and date to convert it to a string using the format you want.
$timestamp = strtotime('2009-12-09 13:32:15');
echo date('d/m/Y', $timestamp);
And you'll get :
09/12/2009
[edit 2012-05-19] Note that strtotime() suffers a couple of possibly important limitations:
The format of the date must be YYYY-MM-DD; it might work in some other cases, but not always !
Also, working with UNIX Timestamps, as done with date() and strtotime() means you'll only be able to work with dates between 1970 and 2038 (possibly a wider range, depending on your system -- but not and illimited one anyway)
Working with the DateTime class is often a far better alternative:
You can use either DateTime::__construct() or DateTime::createFromFormat() to create a DateTime object -- the second one is only available with PHP >= 5.3, but allows you to specify the date's format, which can prove useful,
And you can use the DateTime::format() method to convert that object to any date format you might want to work with.
Using the date() method.
print date("d/m/Y", strtotime("2009-12-09 13:32:15"));
$long_date = '2009-12-09 13:32:15';
$epoch_date = strtotime($long_date);
$short_date = date('m/d/Y', $epoch_date);
The above is not the shortest way of doing it, but having the long date as an epoch timestamp ensures that you can reuse the original long date to get other date format outputs, like if you wanted to go back and have just the time somewhere else.