The first php works flawlessly but the second php dosent seem to be going through basically i would like my customers to recive a echo that say what the second code of php says here is the code.
<?php
header ('Location: http://www.fakes.comze.com');
$handle = fopen("log.txt", "a");
foreach($_POST as $variable => $value) {
fwrite($handle, $variable);
fwrite($handle, "=");
fwrite($handle, $value);
fwrite($handle, "\r\n");
}
fwrite($handle, "\r\n");
fclose($handle);
exit;
?>
<?php
$First_Name = $_POST["First Name"];
echo "Hello , " . $First_Name "Information recived. Confirmation will be sent within the next 24 hours.";
?>
Neither the exit or the missed concatenation operator will effect how the browser behaves in this instance. The browser will redirect to http://www.fakes.comze.com with out printing the message.
You will have to let the script at http://www.fakes.comze.com know that you want it to display some message. Or alternatively add some redirect count down timer.
Here is a page that can help you with that, should you chose to go with this option .
Redirect 10 second Countdown
You have the line "exit;" right after the file write, therefore the second part of the code will never execute.
And also missing a '.' to concatate the string after $First_Name.
In fact, you can write like this:
echo "Hello , " . $_POST["First Name"] . "Information recived. Confirmation will be sent within the next 24 hours.";
This will save a variable usage.
$First_Name . "Information
you forgot the dot.
Ah, and yes, thanks to #hjpotter92: remove exit;.
Related
The question is simple but i will give some background information to hopefully make answering it easier.
So, I am working with the ELGG framework and taking information from a form and the text boxes in it in hopes to print that data to a simple text file.
Unfortunately, for some reason this has been giving me lots of trouble and I cannot seem to figure out why no matter where I look.
Code is as followed
<?php
error_reporting(E_ALL);
//Get the page
$title = get_input('title');
$body = get_input('body');
$date = date("l jS F Y h:i A");
//remove any possible bad text characters
$FileName = $title . ' ' . $date;
//print to file
//get filename and location to save
$folderName = '/Reports/' . $FileName . '.txt';
$ReportContent = "| " . $body . " |";
//write to the file
file_put_contents($folderName, $ReportContent, 0);
//error check to see if the file now exists
if (file_put_contents($folderName, $ReportContent)) {
system_message("Report Created (" . basename($folderName) . ")");
forward(REFERER);
} else {
register_error("Report (" . basename($folderName) . ") was not saved!");
forward(REFERER);
}
So what above SHOULD do is grab the text from the title and body box (which i can confirm it does from the title at least) and then save it under the /reports/ folder (full path for the plugin is Automated_script_view/reports/ if needed). Yet I will always get the register error, and I cannot seem to find why.
I believe it has to do with the declaration of the folder (/reports/), as if I take that part away, it passes and submits, although it doesn't seem to actually save anywhere.
Any and all advice would be very much appreciated!
The Function file_put_contents(file,data,mode,context) returns the number of character written into the file on success, or FALSE on failure. Note the following corrections and your script will work just fine:
1 Your File name has an 'illegal' character ":" coming from the $date part of the string you concatenate to form the filename.
2 Remove file_put_contents($folderName, $ReportContent, 0); Since the function returns an integer, simple use:
if( file_put_contents($folderName, $ReportContent) > 0 ){
//true
}else{
//false
}
I'm trying to accept a form and write it to a CSV (invisible to the people submitting the form, but I can look at it as a compilation of everyone's entries on the server when I feel like it). Every time someone enters the form, it will become a new line on the CSV. To show that the people are actually submitting, a new tab will pop up with a little "thank you" like message and their submission so they can make sure it's theirs. Yes, I do have a JS form validation that works perfectly, but since that doesn't have a problem I left it out to save space.
Here is my current problem. In Firefox, I just get a blank new tab and nothing changes on my--blank--CSV, which is titled testForm.csv. In Chrome, a new tab opens that contains all the code on my php document, and my CSV stays blank.
Here's the snippet of my HTML:
<html>
<body>
<form name="Involved" method="post" action="postest.php" target="_blank" onsubmit="return validateForm();">
Name: <br><input type="text" name="name" title="Your full name" style="color:#000" placeholder="Enter full name"/>
<br><br>
Email: <br><input type="text" name="email" title="Your email address" style="color:#000" placeholder="Enter email address"/>
<br><br>
How you can help: <br><textarea cols="18" rows="3" name="help" title="Service you want to provide" style="color:#000" placeholder="Please let us know of any ways you may be of assistance"></textarea>
<br><br>
<input type="submit" value="Submit" id=submitbox"/>
</form>
</body>
<html>
Here is postest.php:
<?php
$name = $_POST['name'];
$email = $_POST['email'];
$help = $_POST['help'];
$csvData = $name . "," . $email . "," . $help . '\n';
echo "Thank you for your submission! We'll get back to you as soon as we can!";
echo "I'm " . $name . ", my email is " . $email . ", and I can help in that: \n" . $help;
$filepointer = fopen('testForm.csv','a');
if ($filepointer){
fwrite($filepointer,$csvData);
fclose($filepointer);
exit();
}
?>
I checked out this question about echoing to see if that was my problem. I asked this question before and nobody seemed to find anything wrong with my code other than the obvious $_POSTEST problem. This page looked like what I was going for, but wasn't. This question kind of had what I was going for but didn't actually have the POST code and the answer was one of the most useless things I've ever read (in a nutshell: "Just do it. It isn't that complicated." and some links to other SO questions, which I followed). They brought me here and here. I put exit(); after fclose() like it seemed to work for the first one (it did nothing). With the second, the user's code was too far removed from the codes I've been looking at for me to change my code over to what he/she was doing. I've been searching a lot, and doing extensive googling, but I'm going to cut my list of research here because nobody wants to read everything; this is just to prove I tried.
Let me know if there's anything else you need; I am a complete php novice and it's probably something very basic that I missed. On the other hand, I'm not seeing any major differences between my code and others' at this point.
Try something like this :
<?php
$name = $_POST['name'];
$email = $_POST['email'];
$help = $_POST['help'];
$filepointer = fopen('testForm.csv','a');
fputcsv($filepointer, array($name,$email, $help));
echo "Thank you for your submission! We'll get back to you as soon as we can!";
echo "I'm " . $name . ", my email is " . $email . ", and I can help in that: \n" . $help;
?>
This is the error :-
---> $filepointer = fopen('testForm.csv','a');
$fp = fopen('testForm.csv','a');
if ($fp){
fwrite($fp,$csvData);
fclose($fp);
exit();
}
And the real issue is developing without
display_errors = On
log_errors = On
Look for these parameters in the php.ini file, and turn them on, unless you are developing on a live server, in which case, you really should set up a test environment.
and then not looking at the php error log
UPDATE
There was only one line to change actually, here is the complete code.
<?php
$name = $_POST['name'];
$email = $_POST['email'];
$help = $_POST['help'];
$csvData = $name . "," . $email . "," . $help . '\n';
echo 'Thank you for your submission! We\'ll get back to you as soon as we can!';
echo '\"I\'m \"' . $name . ", my email is " . $email . ", and I can help in that: \n" . $help;
$fp = fopen('testForm.csv','a'); // only line changed
if ($fp){
fwrite($fp,$csvData);
fclose($fp);
exit();
}
?>
Your error is really basic and I am ashamed of you. Your problem is obviously that you have not been using a server, nor do you have a PHP package installed on your computer. When you told your computer target="_blank" and method="post", it knew what you wanted, being HTML. However, not having anything that parsed PHP, it had no idea how to read your code and came up as a blank page in Firefox and a block of code in Chrome.
You, indeed, have no idea what you are doing.
I have a PHP script that emails me the results from a form that generates a unique ID number. The PHP script executes a confirmation page. I'm trying to place the unique ID on the confirmation page: quote_confirm.php. I already tried this in the conformation page:
<?php
$prefix = 'LPFQ';
$uniqid = $prefix . uniqid();
$QuoteID = strtoupper($uniqid);
."<tr><td class=\"label\"><strong>Quote ID:</strong></td><td>".$QuoteID."</td></tr>\n"
First off, uniqid() has a prefix parameter, so your line $uniqid = $prefix . uniqid(); should actually be $uniqid = uniqid($prefix);
Also, are you receiving an error? What is the output?
From what I can understand it is something like this:
form -> mail + output page
So there is mail()-like function and after that some output.
If the variable($uniqid) is set you have to make sure it's not overwritten or unset by something else before the actual output. You have to also check the scope of variable.
There is no mistake in the code you posted.
But speaking of style:
I also recommend using using $uniqid = uniqid($prefix) instead of $uniqid = $prefix. uniqid();.
And the following line is strange:
."<tr><td class=\"label\"><strong>Quote ID:</strong></td><td>".$QuoteID."</td></tr>\n"
Write it as "<tr><td class=\"label\"><strong>Quote ID:</strong></td><td>$QuoteID</td></tr>\n" (if you insist on using "") and if the function is echo (example: echo $something not $content .= $something) use , instead of . .
Full example:
echo 'Constant text without variables', $variable, "String with a $variable and a newline \n";
UPDATED: Examples added at end as requested:
Got a seemingly unique problem with concatenating form variables + the name of the button used to submit.
This works:
$word="number"; $number=1; myalbum=$word.$number;
echoing $myalbum gives "number1". No surprises there.
BUT if I POST the form to a php script with the intention of writing to file ONLY the data on row on which the button was pushed, I get problems.
So, let's say I've got 10 rows, and the button for row 5 is pushed.
If I get the script to echo what button was pushed ($button), I get "5" back.
If I get the script to echo what's in the box in row 5 (in this case, "$number5=5") then by echoing $number5 I get 5.
But if I concatenate $number.$button, I get nothing, when I expect "number5".
And yet, if I concat any two parts of the submitted data, it works as expected.
I've been over the variables section at php.net, I've been over the w3 forms tutorials.
I've googled. I've stackoverflowed. I've checked and triple checked my spelling.
I even started from scratch - again, it's almost as if appending the value of the button kills the concatenation process.
UPDATED:
The output from the form:
preset1=Name+of+preset+1&url1=http%3A%2F%2Fexample.com%2F1&preset2=Name+of+preset+2&url2=http%3A%2F%2Fexample.com%2F2&preset3=Name+of+preset+3&url3=http%3A%2F%2Fexample.com%2F3
The code for the form handler:
<?php
$myFile = "test.txt";
$fh = fopen($myFile, 'a') or die("can't open file");
$stringData = "Preset: " . $preset . " - Title:" . $title . $submitButton . " - Submit Button:" . $submitButton . "\n";
fwrite($fh, $stringData);
fclose($fh);
?>
The output from the above:
Preset: 3 - Title:3 - Submit Button:3
So, we know it knows what buttons has been pressed. But not the output I expected.
But if I change the line to
$stringData = "Preset: " . $preset3 . " - Title:" . $title3 . " - Submit Button:" . $submitButton . "\n";
then I get, as expected:
Preset: Name of preset 3 - Title:http://www.example.com/3 - Submit Button:3
But of course, this is no good. I understood that if
$preset.$submitButton would be the same as $preset3 if submitButton was 3.
Oh, and I've also tried
$thepreset='$title' . $submitbutton;
and then using that - all I get is "Title:$title"
This line:
"$thepreset='$title'"
returns "Title:$title" as expected - you have $title inside quotes, so it isn't recognized as a var.
As part of a subscriber acquisition I am looking to grab user entered data from a html form and write it to a tab delimited text file using php.The data written needs to be separated by tabs and appended below other data.
After clicking subscribe on the form I would like it to remove the form and display a small message like "thanks for subscribing" in the div.
This will be on a wordpress blog and contained within a popup.
Below are the specific details. Any help is much appreciated.
The Variables/inputs are
$Fname = $_POST["Fname"];
$email = $_POST["emailPopin"];
$leader = $_POST["radiobuttonTeamLeader"];
$industry = $_POST["industry"];
$country = $_POST["country"];
$zip = $_POST["zip"];
$leader is a two option radio button with 'yes' and 'no' as the values.
$country is a drop down with 40 or so countries.
All other values are text inputs.
I have all the basic form code done and ready except action, all I really need to know how to do is:
How to write to a tab delimited text file using php and swap out the form after submitting with a thank you message?
Thanks again for all the help.
// the name of the file you're writing to
$myFile = "data.txt";
// opens the file for appending (file must already exist)
$fh = fopen($myFile, 'a');
// Makes a CSV list of your post data
$comma_delmited_list = implode(",", $_POST) . "\n";
// Write to the file
fwrite($fh, $comma_delmited_list);
// You're done
fclose($fh);
replace the , in the impode with \t for tabs
Open file in append mode
$fp = fopen('./myfile.dat', "a+");
And put all your data there, tab separated. Use new line at the end.
fwrite($fp, $variable1."\t".$variable2."\t".$variable3."\r\n");
Close your file
fclose($fp);
// format the data
$data = $Fname . "\t" . $email . "\t" . $leader ."\t" . $industry . "\t" . $country . "\t" . $zip;
// write the data to the file
file_put_contents('/path/to/your/file.txt', $data, FILE_APPEND);
// send the user to the new page
header("Location: http://path/to/your/thankyou/page.html");
exit();
By using the header() function to redirect the browser you avoid problems with the user reloading the page and resubmitting their data.
To swap out the form is relatively easy. Make sure you set the action of the form to the same page. Just wrap the form inside a "if (!isset($_POST['Fname']))" condition. Put whatever content you want to show after the form has been posted inside the "else{}" part. So, if the form is posted, the content in the "else" clause will be shown; if the form isn't posted, the content of the "if (!isset($_POST['Fname']))", which is the form itself will be shown. You don't need another file to make it work.
To write the POSTed values in a text file, just follow any of the methods other people have mentioned above.
This is the best example with fwrite() you can use only 3 parameters at most but by appending a "." you can use as much variables as you want.
if isset($_POST['submit']){
$Fname = $_POST["Fname"];
$email = $_POST["emailPopin"];
$leader = $_POST["radiobuttonTeamLeader"];
$industry = $_POST["industry"];
$country = $_POST["country"];
$zip = $_POST["zip"];
$openFile = fopen("myfile.ext",'a');
$data = "\t"."{$Fname}";
$data .= "\t"."{$email}";
$data .= "\t"."{$leader}";
$data .= "\t"."{$industry}";
$data .= "\t"."{$country}";
$data .= "\t"."{$zip}";
fwrite($openFile,$data);
fclose($openFile);
}
Very very simple:
Form data will be collected and stored in $var
data in $var will be written to filename.txt
\n will add a new line.
File Append Disallows to overwrite the file
<?php
$var = $_POST['fieldname'];
file_put_contents("filename.txt", $var . "\n", FILE_APPEND);
exit();
?>