PHP - Using $_POST after a link [closed] - php

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Closed 8 years ago.
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I have a form with a textbox with name="name".
In my code, I use a direct image hosted on another website in the format:
$grav_url = "http://yourwebsitehere.com/avatarimage.php?username=YourUsername";
I want the YourUsername part to be replaced with the input of the textbox.
For this to work, i'm trying the following code:
$grav_url = "http://yourwebsitehere.com/avatarimage.php?username="+ $_POST['name'];
What am I doing wrong? PHP noob here


in php . is used for concatenate string not +
here try this
$grav_url = "http://yourwebsitehere.com/avatarimage.php?username=".$_POST['name'];

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problem using anchor button in server(cent os) [closed]

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Closed 4 years ago.
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In my project i am using anchor button based on if else condition. In windows it's working perfectly.
HTML
<?php
$actionbutton = $row['status'] == 'success' ?
anchor('Users/getpdf/'.$row['appno'],'Generate Pdf') :
anchor('Users/validate/'.($row['appno']),'Pending') ;
?>
<td align="center"><?php $actionbutton;?></td>
after uploading in server (cents os) the button not displayed. how to solve this error?

On your first command, it assigns the value to your $actionbutton variable.
Your 2nd command, I think you want to echo the $actionbutton.
Maybe you want this <?=$variable?>.
So, in your case <?=$actionbutton?>
Codeigniter Documentation 👈 about alternative syntax.

What is the "returnto" in this piece of code [closed]

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Closed 7 years ago.
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header("Location: {$TBDEV['baseurl']}/login.php?returnto=" . urlencode($_SERVER["REQUEST_URI"]));
Is it a variable? PHP reserved word? something to do with HTML?

It's a $_GET parameter. When you submit the code, the page receiving it will be able to use $_GET['returnto'] to return you to the page you're currently on.
Take some time to learn about $_GET

Php help find where is syntax error [closed]

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foreach($db->fetch_array("SELECT id_categories FROM csn_categories_join_kartes where id_kartes===".$card['id']."") as $kat){
echo (kat['id_categories']);
}
table cols and values are all matched, something is wrong in this part of code
I tried adding $ before kat and using only one "=", sill doesnt work
NEW LINK
http://pastebin.com/RPK7vEaJ

this
where id_kartes===".$card['id']."
would be
where id_kartes=".$card['id']."
and missing $
echo $kat['id_categories'];
so full code :-
foreach($db->fetch_array("SELECT id_categories FROM csn_categories_join_kartes where id_kartes='".$card['id']."'") as $kat){
echo $kat['id_categories'];
}
best practice if you store your query result in a variable and loop over this variable.

foreach($db->fetch_array("SELECT id_categories FROM csn_categories_join_kartes where id_kartes=".$card['id']."") as $kat)

PHP error for login session [closed]

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Closed 8 years ago.
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I have an error in a single line of code but I can't seem to find it. I've tried changing the quotes to all match but that doesn't do anything. Please help. here is where the error is
$managerID = preg_replace('#[^0-9]#i',",$_SESSION["id"]);

try this :
$managerID = preg_replace('#[^0-9]#i','',$_SESSION["id"]);
btw i dont know what you are trying to do i just solved your syntax error ;)

T String When using a reference [closed]

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I am using this as a reference
$jpsupp1 = '<?=$gamesss['jackpot']?>';
How can I use this without the 'jackpot' giving me t_string errors?

It should be:
$jpsupp1 = $gamesss['jackpot'];
You don't need <?= when you're already executing PHP code. That's used for embedding PHP in HTML.

Use double quotes
$jpsupp1 = "<?=$gamesss['jackpot']?>";
or
$jpsupp1 = "<?={$gamesss['jackpot']}?>";
Depending on what you want to store.

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