Writing ForEach Loop to database - php

Question

This is a stupid question, but I can't seem to find an answer.
I have a foreach loop, that finds all the images on a particular link. I would like to encode all those images, and then write them to the database. If I put the sql query inside the foreach loop, then a new row is created for every images, if I put the sql query outside the foreach loop, only the first image is written. If I try to write the images and the rest of the data separately, the insert sees $newimage as null and overwrites the values. Any advice would be appreciated?
foreach($html->find('img') as $images) {
$newimage = json_encode($images->src);
echo $newimage;
}
$sql="INSERT INTO data (headline, images, email, date, category, area, number, crawled, lastcrawled, description)
VALUES ('$headline', '$newimage', '$email','$date','$category','$area','$number', '$crawled', '$dt', '$description')";

Answer 1

This should give you what you're looking for, based on your comment:
// create an array to hold the image sources
$store_images = array();
foreach($html->find('img') as $images) {
// add the image sources to the array
$store_images[] = $images->src;
}
// encode the entire array of images
$json_store_images = json_encode($store_images);
// store the encoded images along with the other data
$sql="INSERT INTO data (headline, images, email, date, category, area, number, crawled, lastcrawled, description)
VALUES ('$headline', '$json_store_images', '$email','$date','$category','$area','$number', '$crawled', '$dt', '$description')";

Answer 2

Hope this would be helpful to you.
$newimages = array();
foreach($html->find('img') as $images) {
$newimages[] = $images->src;
}
$newimage = json_encode($newimages);
Same sql then -
$sql="INSERT INTO data (headline, images, email, date, category, area, number,
crawled, lastcrawled, description) VALUES ('$headline', '$newimage',
$email','$date','$category','$area','$number', '$crawled', '$dt', '$description')";