read datatable again after clicking the submit Button - php

I want my dataTable to be read again or reload the data from db after clicking update/submit button.
i tried this
$('#ManageForms').dataTable().dataSource.read();
it seemed to work with kendoUI but i guess datatables must have different procedure.

If you want to reload the entire table then fnReloadAjax() is the way to go. It will go to the server, and just grab everything again.
Example:
var table = $('#example').dataTable();
// Example call to load a new file
table.fnReloadAjax( 'media/examples_support/json_source2.txt' );
// Example call to reload from original file
table.fnReloadAjax();
If you want to load only the data that should be displayed, then you need to use the bServerSide parameter, and have the server reply to your request, taking into account, filtering etc.

Related

Run PHP file in the background

I wonder if it is possible to run a PHP file in the background on my website?
What I want to do is to show a form with inputs and dropdowns. The content of the dropdown is taken from a table in a MySQL database. Next to the dropdown is an Edit button which opens a Bootstrap Modal and shows all the content in the table for the dropdown. Here I can make changes to the table. Then I want to go back to the form and apply the changes I jsut made (i.e. select a new post from the dropdown).
I know how to do all of this - BUT - when I save the changes to the dropdown table, a php file is called to perform the SQL syntax and then redirects the user back to the form. Every input you have made in the form is lost since the page is reloaded.
Is there a way to make it work like I want?
I understand that you need to implement Ajax to do the background operation. Ajax request runs in background, its entry and exit is handled through Javascript functions . See here : http://www.w3schools.com/ajax/
As some already noted, Ajax is the way to go in this case.
An idea would be to use ajax to send the modal data to the server (saving the new options for the dropdown) when the user clicks in the "save" button (or anything equivalent). When this ajax call finish successfully, you could reload the dropdown with another ajax call (or even better, save the modal data in a temporary structure in JavaScript and use it to update the dropdown once the first ajax call is successful, hence avoiding some work on the server)
Note that the page won't reload in the whole process.
The simplest and the easiest way to do this is to open the modal in a new window.
example
Modal
And you can attached this to your select option value with a on-click event.

retrive from DB without click any button using onfocus

hi I have some problem with my code!
I have a textbox when the user write in this text box I want to retrieve from DB directly without clicking any button.
then some of my form will completed after writing in this textbox.
my JS code :
function centerIDfocus()
{
var id = document.getElementById("centerID").value;
var data = <?php $center_ID = echo mysql_num_rows(mysql_query("SELECT * FROM 'examcenter' WHERE 'id' = '".id."'")); ?> ;
}
window.onload = addEventsToHTML;
in my form:
<input name="centerID" id="centerID" onfocus="centerIDfocus();">
and that’s not working!
any ideas red face
You mixed 2 languages - javascript is run on client side and php on server side.
What You need to do is:
var data = function_to_get_data(); // in javascript
in that function call ajax request to the address of your php script - and only in that php script call your database to return desired data
You're PHP code will only run once, when the pages is loaded, after that it won't run again because there's nothing happening on the server side. If you want to run it each time you get the focus then you should be using AJAX.
Take a look at AJAX gets, I'm pretty sure that's what you want:
http://api.jquery.com/jQuery.get/
It is rather hard to know what you are intending to do, but...
My guess is that you are confused about when things happen and when "onfocus" is fired.
PHP is run on the server when the page is being constructed. In contrast, javascript is run in the browser, either after the constructed page has arrived (onload) or in response to a user click or other event such as onfocus.
Thus there is no way for the javascript (in the browser) to drop into PHP (on the server). For the same reason (and security) it is impossible for javascript to talk directly to the database.
There are two approaches you might take to do what (I think) you are attempting to do.
You could create a javascript array in PHP, indexed by ID, and containing all possible IDs and their data. Use PHP to read the database, and then echo the javascript to define the array. This would become part of the page sent. Then, in response to the event that means you want to fill the field, you extract the data from the array, and put it where you want it. This would be slow for the page to load, but very quick response to the click that triggered the change.
An alternative is to use ajax. The easiest way is to use jquery to send a GET request to the the server requesting the data related to the ID. The server must respond to that URL by extractign the ID, reading the database and generating the reply. I recommend using JSON. Then, when the jquery request returns, the javascript code can move the data from the JSON into your field. This would make the initial page lighter, but would have a fetch delay to the triggering click.
However I think you may also have an issue with the on-focus event. This fires when the user moves the cursor into the field, before they have entered any data. At that point it will contain the data that was set in the HTML. If you can set the ID at that point, you can also set it to the data from the database.
I think you want two fields - one for the ID and another for the looked up data. Then you run the javascript on the onblur event on the ID field.
Hope that helps.
use something like:
$('.centerID').keyup(function(){
var val = this.val();
var url = '/do.php'; // url to a php script
var val = 'action=checkValue&value='+val; // send it the value
$.getJSON(url, val, function(data){
// Something to do when you get the data back
});
});
then just create a php script that checks the database and returns a JSON answer and then do as you please with it.
BTW - I'm assuming you are ok using jQuery. You can apply this to your JavaScript too.
I used keyup() as one example but you can appy this to keydown(), click(), focus(), focusout() etc...
I have a do.php script that contains a switch statement with the possible value of action= and returns JSON. Everything from logging in, registering, activity monitor, to updating a database field without leaving the page.

View live updates from MySQL database?

I want to create a page where people can insert some text, hit enter, and the text be stored in a MySQL database. I can do this, but I want to be able to load a page, enter a password, and see a list of all the info in said database, then whenever something is added to the database, it's added to the list on the page, without me needing to refresh the page or setup some javascript code to refresh the page every five seconds.
I believe Satya has it correct in suggesting that you use Ajax in order to refresh the data without refreshing the page. You can have it request updated information from a php script which queries your database for the data you wish to display, and then sets the elements on your page accordingly.
this is probably the best way for you to implement ajax calls using javascript
http://api.jquery.com/jQuery.ajax/
Or you an simly do it with the help of setInterval() function. You can call an html code in a div using
$('#id').html("<htmlcode></htmlcode>");
Example : http://jsfiddle.net/ipsjolly/995PJ/6/

Reloading Page Data after PHP Submit

ok folks,
I have created a PHP page that is querying a database, and through a whileloop, displays the contents of that database table with a REMOVE and PUSH button. The REMOVE button removes it from the database entirely, and the PUSH button pushes that entry into another database and sets a variable that the entry has been pushed.
What I'm running into is that I can't quite get the page to refresh, in turn running an new query of the first database and displaying only those entries that have not been removed or pushed.
I can only get the query to run correctly if I manually refresh the page, whether it be F5 or control+r (command+r).
What is the proper way to refresh the page so that the query will run again on page load?
If you want to reload the page using Javascript, try this:
window.location.reload(true);
You can also see this answer:
How to reload a page using JavaScript?
there are two ways
If putting extra load on db is not a problem, use jquery methods likes $.get()
$.get('url',{},function(data){
//load results in appropriate div;
});
If you don't want to put any extra load on database just hide the row when it is removed or pushed.
$('.remove').click(function{
$(this).css('display','none');
});
similarly make it for pushed
Do you have some extreme caching setup on your web hosting solution?
If maintaining nice-looking URLs on this page is a non-issue you could always set a timestamp in PHP and append it to the string.
I'm not big on PHP but a javascript example would look something like this.
ts = new Date();
urltorefresh += '?timestamp=' + ts.getTime();
location.href = urltorefresh;
This would make sure the page is absolutely not in the browser cache since this specific URL have never been requested before.

Page refresh without reloading a page and calling external files in php ajax

I have a profile page where im showing the friends of that user from db, I'm using auto scroller that works fine if I place that data directly in main file not an external file, Also I have a drop down that on selection will sort the friends records accordingly, but as I have moved the code to main file, I need to make ajax call to same file not an external, to repopulate data with required sorting.
Please let me know how can i do this on same file with ajax. On selection of drop down value.
Have you considered using Jquery?
Its surprisingly easy. You just need to do $('#contentdiv').load('contentyouwant') where you bind the event for the ddl.
If you must use the same file, place the code that will be ran by ajax, in a function. then at the beginning of the page, evaluate if this was the ajax call or the whole file.
Hope it helps.

Categories