cakephp control dropdown population from database - php

I'm trying to populate a dropdown/select tag in cakephp,fortunately I was able to populate it with the values coming from my database,
however it displays ALL. How can I limit the population to a specific ID?
To make things clear here's what I want to achieve:
Apples:
form start
dropdown-contains only values that are associated with apples from the DB
button
form end
Currently here's how it looks like
Apples:
form start
dropdown-contains all fruits values from the DB
button
form end
Here's my current code tnx any help/suggestions is very much appreciated
Controller:
$fruits = $this->Model1->Model2->find('list',
array('fields' =>
array('id',
'fruit_name',
//'conditions' => array(''=>'')
)));
$this->set('fruitsList', $fruits);
View:
echo $this->Form->input('Model1.salad_fruits_id',
array('type' => 'select',
'options' => $fruitsList,
));

If you have association between models between models it would be easier. Just add conditions to second model.
//if you don't have association between models
$this->Model1->bindModel(array(
'belongsTo' => array( //example binding
'Model2' => array(
'className' => 'Model2',
'foreignKey' => 'model2_id',
)
)
));
$fruits = $this->Model1->find('list', array(
'conditions' => array(
'Model2.name' => 'apple'
),
'fields' => array(
'id','fruit_name',
)
));

Related

Link one model more than once

I have a function where a user can request a project. The request has 2 fields for other employees to be added.
It's got a field for a person who is responsible for the project (person_responsible) and the employee who is supposed to attend the opening meeting (person_attending).
What I want to know is, since both these fields (person_responsible and person_attending) will be pulling it's data from hr_employees table, how would I set this up in my Project-Model.
At the moment I have the one field set up like this:
public $belongsTo = array(
'HrEmployee' => array(
'className' => 'HrEmployee',
'foreignKey' => 'responsible_person',
'fields' => 'HrEmployee.employeename',
)
);
How would I set up the other field?
What I do in this cases is to make two associations. Since cake allow to customize relations, you can have two relations to the same model with different names.
public $belongsTo = array(
'ResponsibleEmployee' => array(
'className' => 'HrEmployee',
'foreignKey' => 'responsible_person',
'fields' => 'HrEmployee.employeename',
),
'AttendingEmployee' => array(
'className' => 'HrEmployee',
'foreignKey' => 'person_attending',
'fields' => 'HrEmployee.employeename',
)
);
Change the names to adjust your needs. Now, if your model is set as containable and you retrieve the Project model with those models in it, you'll get something like
array('Project' => array(/*data project*/),
'ResponsibleEmployee' => array(/*name*/),
'AttendingEmployee' => array(/*name*/)
)
(or another variation of that array depending on how the query was made).

Cakephp $this->request->data returns id of select field instead of value which is needed and shown in the select field

I have a CakePHP controller like this:
$this->loadModel('Project');
$list2 = $this->Project->find( 'list', array(
'fields' => array('Project.project'),
'conditions' => array('Project.user_id' => $userId)
));
$this->set($list2, 'list2');
$this->loadModel('Distance');
if(!empty($this->request->data)){
$this->Distance->create();
if ($this->Distance->save($this->request->data)) {
$this->Session->setFlash('Saved.');
// $this->redirect(array('action' => 'index'));
} else {
$this->Session->setFlash('FAILED');
}
}else{
// $this->Session->setFlash('test');
}
and a view like this:
echo $this->Form->input('Distance.project', array('options' => $list2, 'label' => false, 'empty' => '(choose one)' ;
But I get inserted to the database the id of the project instead of the project name.
I never have such problems working with the fields - just with a list of data.
Any idea why it happens?
It's normal ... The $list2 it's and array ... and the values of the options are the indexes from that array.
If you want to insert only the project name you need to change $list2 with $list2['project_name']. You need to remove or replace the indexes of $list2.
LE: take iexiak example. He change also the code for you.
$list2 = $this->Project->find( 'list', array(
'fields' => array('Project.project'),
'conditions' => array('Project.user_id' => $userId)
)
);
This is because $list2 automatically creates a list of ID => project; and when you use that as input for your form it automatically creates the drop down to reflect this. This is generally the best practice, to link to ID's instead of to descriptions, as ID's do not change as often. The below should get you exactly what you want though:
$list2 = $this->Project->find( 'list', array(
'fields' => array('Project.project','Project.project'),
'conditions' => array('Project.user_id' => $userId)
)
);

cakePHP assign selected values from 2 arrays using the html input helper

I create 2 arrays from a model, 1 being already selected values from the user, and the 2nd available values which the user can then also select. This is for an edit page. I want to populate a multi-select input box with the values of both models, but want the already chosen values (1st array) highlighted. It creates the models fine, and using array_merge() I merge both the arrays as the options, but the selected does not highlight the correct fields. Any tips?
// Controller:
$ivrNumbersAvail = $this->Survey->SurveyIvrNumber->find("list",array("conditions" => array("OR" => array("SurveyIvrNumber.survey_id" => array($id)))));
$ivrNumbersSelected = $this->Survey->SurveyIvrNumber->find("list",array("conditions" => array("OR" => array("SurveyIvrNumber.survey_id" => array(0)))));
// In the view:
echo $this->Form->input('SurveyIvrNumbers.id',array(
'empty' => '-- Select IVR Number(s) --',
'options' => array_merge($ivrNumbersAvail,$ivrNumbersSelected),
'selected' => $ivrNumbersSelected,
'class' => 'textbox',
'multiple' => true,
'div' => array(
'class' => 'field'
),
'label' => array(
'class' => 'label-tooltip',
'title' => '', //tool tips
'text' => 'IVR Numbers: (you can select multiple numbers)'
),
'after' => '<p class="field-help"></p>'
));
If you set $this->request->data to the record you are currently editing CakePHP will automatically populate this data for you!
// CONTROLLER
// this line sets the data
$this->request->data = $this->Survey->read(null, $id);
// this passes the SurveyIvrNumbers to the view, (you can put any options on to this)
$this->set('SurveyIvrNumber',$this->Survey->SurveyIvrNumber->find('all'));
// VIEW
// CakePHP does the rest
echo $this->Form->input('SurveyIvrNumbers',array(
'empty' => '-- Select IVR Number(s) --', // plus other options
);

Retain Checkbox values in Yii gridview pagination

I have a gridview which contains a checkbox column and also uses pagination. When I check some checkboxes in the first page and navigate to the second page and check another one in the second page, the options I checked in the first page is not retained there. Is it posssible to retain the checkbox values during pagination?
Code for Gridview is
$widget = $this->widget('zii.widgets.grid.CGridView', array(
'dataProvider' => $model->search(),
'cssFile' => Yii::app()->baseUrl . '/media/js/admin/css/admingridview.css',
//'filter' => $model,
'ajaxUpdate' => true,
'enablePagination' => true,
'columns' => array(
array(
'name' => 'id',
'header' => '#',
'value' => '$this->grid->dataProvider->pagination->currentPage * $this->grid->dataProvider->pagination->pageSize + ($row+1)',
),
array(
'class' => 'CCheckBoxColumn',
'selectableRows' => '2',
'header' => 'Selected',
),
array(
'name' => 'fb_user_id',
'header' => 'FaceBook Id',
'value' => 'CHtml::encode($data->fb_user_id)',
),
array(
'name' => 'first_name',
'header' => 'Name',
'value' => 'CHtml::encode($data->first_name)',
),
array(
'name' => 'email_id',
'header' => 'Email',
'value' => 'CHtml::encode($data->email_id)',
),
array(
'name' => 'demo',
'type' => 'raw',
'header' => "Select",
'value' => 'CHtml::checkBox("email[]","",array("class"=>"check","value"=>$data->email_id))',
),
),
));
Edit:
Extension for remembering the selected options in gridview,check this link Selgridview
Thanks to bool.dev
You could use sessions/cookies to store the checked values. I'm not very sure how to make cookies work, so i'll tell you how to do it with sessions. Specifically the user session that yii creates.
Now to use sessions we need to pass the checked (and unchecked) ids to the controller, therefore we'll modify the data being sent to the controller on every ajax update(i.e between paginations), to do this we exploit the beforeAjaxUpdate option of CGridView.
I'm also using CCheckBoxColumn instead of the following in your code(of course you can modify the solution to suit your own needs):
array(
'name' => 'demo',
'type'=>'raw',
'header' => "Select",
'value' => 'CHtml::checkBox("email[]","",array("class"=>"check","value"=>$data->email_id))',
),
GridView Changes:
<?php $this->widget('zii.widgets.grid.CGridView', array(
// added id of grid-view for use with $.fn.yiiGridView.getChecked(containerID,columnID)
'id'=>'first-grid',
'dataProvider'=>$model->search(),
'cssFile' => Yii::app()->baseUrl . '/media/js/admin/css/admingridview.css',
// added this piece of code
'beforeAjaxUpdate'=>'function(id,options){options.data={checkedIds:$.fn.yiiGridView.getChecked("first-grid","someChecks").toString(),
uncheckedIds:getUncheckeds()};
return true;}',
'ajaxUpdate'=>true,
'enablePagination' => true,
'columns' => array(
array(
'name' => 'id',
'header' => '#',
'value' => '$this->grid->dataProvider->pagination->currentPage * $this->grid->dataProvider->pagination->pageSize + ($row+1)',
),
array(
'name' => 'fb_user_id',
'header' => 'FaceBook Id',
'value' => 'CHtml::encode($data->fb_user_id)',
),
array(
'name' => 'first_name',
'header' => 'Name',
'value' => 'CHtml::encode($data->first_name)',
),
array(
'name' => 'email_id',
'header' => 'Email',
'value' => 'CHtml::encode($data->email_id)',
),
/* replaced the following with CCheckBoxColumn
array(
'name' => 'demo',
'type'=>'raw',
'header' => "Select",
'value' =>'CHtml::checkBox("email[]","",array("class"=>"check","value"=>$data->email_id))',
),
*/
array(
'class' => 'CCheckBoxColumn',
'selectableRows' => '2',
'header'=>'Selected',
'id'=>'someChecks', // need this id for use with $.fn.yiiGridView.getChecked(containerID,columnID)
'checked'=>'Yii::app()->user->getState($data->email_id)', // we are using the user session variable to store the checked row values, also considering here that email_ids are unique for your app, it would be best to use any field that is unique in the table
),
),
));
?>
Pay special attention to the code for beforeAjaxUpdate and CCheckBoxColumn, in beforeAjaxUpdate we are passing checkedIds as a csv string of all the ids(in this case email_ids) that have been checked and uncheckedIds as a csv string of all the unchecked ids, we get the unchecked boxes by calling a function getUncheckeds(), which follows shortly. Please take note here, that when i was testing i had used an integer id field (of my table) as the unique field, and not an email field.
The getUncheckeds() function can be registered like this anywhere in the view file for gridview:
Yii::app()->clientScript->registerScript('getUnchecked', "
function getUncheckeds(){
var unch = [];
/*corrected typo: $('[name^=someChec]') => $('[name^=someChecks]') */
$('[name^=someChecks]').not(':checked,[name$=all]').each(function(){unch.push($(this).val());});
return unch.toString();
}
"
);
In the above function pay attention to the selectors and each and push function.
With that done, we need to modify the controller/action for this view.
public function actionShowGrid(){
// some code already existing
// additional code follows
if(isset($_GET['checkedIds'])){
$chkArray=explode(",", $_GET['checkedIds']);
foreach ($chkArray as $arow){
Yii::app()->user->setState($arow,1);
}
}
if(isset($_GET['uncheckedIds'])){
$unchkArray=explode(",", $_GET['uncheckedIds']);
foreach ($unchkArray as $arownon){
Yii::app()->user->setState($arownon,0);
}
}
// rest of the code namely render()
}
That's it, it should work now.
For developing that scheme you would need to know working of what happens when you navigate.
When ever you navigate to a pagination page ajax calls are made and new data is received and it is fetched from CActive Record or what ever the data source. New data is in accordance of database records or source records. when you come back to previous page again Ajax call is made and content is updated so same comes as it is in database.
what i feel is you should save data of checked items temporary and make it permanent if action is made.
You can do something like this
<script type="text/javascript">
$("input:checkbox").click(function () {
var thisCheck = $(this);
if (thisCheck.is (':checked')){
// do what you want here, the way to access the text is using the
// $(this) selector. The following code would output pop up message with
// the selected checkbox text
$(this).val());
}
});
</script>
you can save temporary storage somewhere
Also make this work on normal form submit:
I wanted to add this as a comment on bool.dev's answer, but I do not have enough reputation to do that yet. So I had to put it in a separate answer.
bool.dev, your answer is great and it works well, thanx.
However, as intended, it only works when ajax calls update the gridview. I have the gridview forming part of a form, so I wanted it to also work on normal submission of the form, otherwise the checkboxes are not loaded again when there are other validation errors on the form.
So, in ADDITION to what you did, I added hidden fields on my form e.g.:
<input type="hidden" name='checkedBox1' id='checkedBox1' value=''>
<input type="hidden" name='uncheckedBox1' id='uncheckedBox1' value=''>
Then, before submitting the form, my sumbit button runs your getChecked() and getUncheckeds() functions and store their results in the hidden fields:
if ($('#checkedBox1').length >0) {$('[name=checkedBox1]').val(getChecked());}
if ($('#uncheckedBox1').length >0) {$('[name=uncheckedBox1]').val(getUncheckeds());}
In the controller, besides from checking for $_GET['checkedIds'], you also check for $_POST['checkedBox1'] and store its values to session in the same way you do for $_GET['checkedIds'], using the same session variable.
Do the same with $_POST['uncheckedBox1'].
That should work.

Exposing a table to Views

I have a table that's been created by a module. I need to include some of its fields into an existing view.
I tried using the table wizard module, but all it does is create a separate view for that table. I'd like to be able to choose fields from that table to be added into an existing view as additional fields, or through relationships or something like that. Is there a workaround to do what I'm trying to do?
Ah. Views. Took me a while as well. This answer is for Drupal 6 and in the abstract shows how to define fields as well as using a relationship to allow the fields to link to the node table.
Inside modulename.module, you want a function that goes:
function modulename_views_api() {
return array(
'api' => 2,
);
}
Then you want to make a file called modulename.views.inc and define a function like this:
function modulename_views_data() {
$data['modulename_table'] = array(
'table' => array(
'group' => 'ModuleName',
'title' => 'Module name title',
),
'join' => array(
// to join to node, we'll use a field in modulename_table called 'nid'
'node' => array(
'left_field' => 'nid',
'field' => 'nid',
),
),
);
// now we define the fields in the table like this
// check out modules/views/handlers to see more specific handlers
$data['modulename_table']['fieldname'] = array(
'title' => 'fieldname',
'help' => 'fieldname description',
'field' => array(
'handler' => 'views_handler_field',
),
);
$data['modulename_table']['nid'] = array(
'title' => 'related node',
'help' => 'the field that relates back to {node}',
// here we implement a relationship to nid
'relationship' => array(
'base' => 'node',
'field' => 'nid',
'handler' => 'views_handler_relationship',
'label' => 'modulename row node',
),
// this relationship can be turned on in views
);
return $data;
}
You can use hook_views_data to define your table in code. As long as you don't want views to do special manipulations, it's almost as simple as defining the table with the schema API.
Your other option is to use table wizard to expose the tables to the database and then use the migrate module to create the views. http://drupal.org/project/migrate
I have found that the Views Custom Field module lets me do just about anything I need as far as adding oddball fields to views .. maybe it'd help ..

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