How do I access repository logic from the view? - php

Basically, I'm writing a simple blogging application where users can vote up or down on posts (I've named this process scoring inside my application). My problem is I am not sure what the best approach is for accessing a method to determine if the user has voted or not on the post, as I don't want to pass a repository into my view nor do I want the model to have methods mimicking the repository... Here are those two ideas - are these the only approaches?
The first approach requires that I pass a PostRepository to my views as well as the Post model which is already passed...
<!-- Repository-in-view approach -->
<p>You voted {{ $postRepository->hasUserScored($post->id, $user->id) ? 'up' : 'down' }}.</p>
-----------
// Inside `PostRepository`
public function hasUserScored($postId, $userId, $vote = true)
{
// DB logic to determine ...
}
Or should I maybe do something like this?
<!-- Repository-in-view approach -->
<p>You voted {{ $post->hasUserScored($user->id) ? 'up' : 'down' }}.</p>
-----------
// Inside `Post`
public function hasUserScored($userId)
{
return (new PostRepository)->hasUserScored($this->id, $userId);
}
// Inside `PostRepository`
public function hasUserScored($postId, $userId, $vote = true)
{
// DB logic to determine ...
}
What is the best way to overcome this? Any help greatly appreciated, thanks!

Best practice is to avoid calling functions from within views.
Either call the function from the controller, and pass that data to the view. Or, alternatively, use a view composer.

Why do you do this in such a complicated way? Can't your Post model just have many-to-many relationship with users + pivot table? Then, checking a User vote is as simple as:
function users()
{
return $this->belongsToMany('User')->withPivot('vote');
}
function getUserScore($userId)
{
return $this->users->find($userId)->pivot->vote;
}
Also, if you want to check whether a user has voted or not, simply do:
function hasUserVoted($userId)
{
return $this->users->contains($userId);
}

you have to pass the Repository to the view.. although what you want to do is not the smartest approach but according with what you need.. the way is
on your controller __construct you add something like this
function __construct(PostRepositoryInterface $post){
$this->post = $post;
}
if you dont use interface then just pass the repository
then you return to the view
view(your.view)->with('post', $this->post);
then you are done..

Related

Method Illuminate\Support\Collection::find does not exist

Edit function:
public function editCheck($id, LanguagesRequest $request)
{
try{
$language = language::select()->find($id);
$language::update($request->except('_token'));
return redirect()->route('admin.languages')->with(['sucess' => 'edit done by sucsses']);
} catch(Exception $ex) {
return redirect()->route('admin.addlanguages');
}
}
and model or select function
public function scopeselect()
{
return DB::table('languages')->select('id', 'name', 'abbr', 'direction', 'locale', 'active')->get();
}
This code is very inefficient, you're selecting every record in the table, then filtering it to find your ID. This will be slow, and is entirely unnecessary. Neither are you using any of the Laravel features specifically designed to make this kind of thing easy.
Assuming you have a model named Language, if you use route model binding, thing are much simpler:
Make sure your route uses the word language as the placeholder, eg maybe your route for this method looks like:
Route::post('/languages/check/{language}', 'LanguagesController#editCheck');
Type hint the language as a parameter in the method:
public function editCheck(Language $language, LanguagesRequest $request) {
Done - $language is now the single model you were afer, you can use it without any selecting, filtering, finding - Laravel has done it all for you.
public function editCheck(Language $language, LanguagesRequest $request) {
// $language is now your model, ready to work with
$language::update($request->except('_token'));
// ... etc
If you can't use route model binding, or don't want to, you can still make this much simpler and more efficient. Again assuming you have a Language model:
public function editCheck($id, LanguagesRequest $request) {
$language = Language::find($id);
$language::update($request->except('_token'));
// ... etc
Delete the scopeselect() method, you should never be selecting every record in your table. Additionally the word select is surely a reserved word, trying to use a function named that is bound to cause problems.
scopeselect() is returning a Collection, which you're then trying to filter with ->find() which is a method on QueryBuilders.
You can instead filter with ->filter() or ->first() as suggested in this answer
$language = language::select()->first(function($item) use ($id) {
return $item->id == $id;
});
That being said, you should really find a different way to do all of this entirely. You should be using $id with Eloquent to get the object you're after in the first instance.

Call a controller with a parameter?

Let's imagine I have two Models:
A list of users User
A list of marbles Marble which belongs to one User
I would like to fetch all the existing marbles with api/marbles and only my marbles with api/user/marbles. The idea is to avoid a route named like api/marbles?owned=true
In my API routes I have this:
Route::get('marbles', 'MarbleController#index');
Route::get('user/marbles', 'MarbleController#index(true)');
Then in my MarbleController:
class MarbleControllerextends Controller
{
function index($owned = false) {
return $owned ? Marble::where('user_id', Auth::id())->get() : Marble::all();
}
}
Unfortunately the MarbleController#index(true) doesn't really work because (true) will not be accepted by Laravel not populate the optional $owned variable.
Is there a way to avoid defining a new method such as Route::get('user/marbles', 'MarbleController#owned');
function owned() {
return $this->index(true);
}
Route::get('marbles/{me?}', 'MarbleController#index'); will work fine.
Here me is an optional parameter. If you omit it, it will take false otherwise true as it's value.

Laravel 4.2 is_online article

I'm confronted to a little problem, i try to add a method to show only online article, but i want to know how do implement this method.
In my DB i have a row is_online (Int) for 0=> offline, 1=>online, how do implement that for my view.
in my models with
public function isonline(){}
or in my PostController in my request of post find.
And after need to add in my admin panel a check box in Post create to change the status off article (online or offline-draft).
You should use Eloquent scope in your code by creating online scope in your model.
public function scopeOnline($query)
{
return $query->where('is_online', 1);
}
Draft posts
public function scopeDrafts($query)
{
return $query->where('is_online', 0);
}
Then in your code you can simply use it like this.
$onlinePosts = Post::online()->get();
$draftPosts = Post::drafts()->get();
You just need to find all records who have flag is_online = 1.
You can write one method in your PostController like
Public function getOnlineRecords{
$records = YourModel::where('is_online','=',1)->get();
return View::make('your_view_path',['records'=>$records]);
}
In your View file, you need to write:-
{{ Form::checkbox('your_field_name', 'value', true) }}
If you want to default the value as checked, pass true as the third argument.

Laravel Eloquent update just if changes have been made

Is there any way to update a record in Laravel using eloquent models just if a change has been made to that record? I don't want any user requesting the database for no good reason over and over, just hitting the button to save changes. I have a javascript function that enables and disables the save button according with whether something has changed in the page, but I would like to know if it's possible to make sure to do this kind of feature on the server side too. I know I can accomplish it by myself (meaning: without appealing to an internal functionality of the framework) just by checking if the record has change, but before doing it that way, I would like to know if Laravel eloquent model already takes care of that, so I don't need to re-invent the wheel.
This is the way I use to update a record:
$product = Product::find($data["id"]);
$product->title = $data["title"];
$product->description = $data["description"];
$product->price = $data["price"];
//etc (string values were previously sanitized for xss attacks)
$product->save();
You're already doing it!
save() will check if something in the model has changed. If it hasn't it won't run a db query.
Here's the relevant part of code in Illuminate\Database\Eloquent\Model#performUpdate:
protected function performUpdate(Builder $query, array $options = [])
{
$dirty = $this->getDirty();
if (count($dirty) > 0)
{
// runs update query
}
return true;
}
The getDirty() method simply compares the current attributes with a copy saved in original when the model is created. This is done in the syncOriginal() method:
public function __construct(array $attributes = array())
{
$this->bootIfNotBooted();
$this->syncOriginal();
$this->fill($attributes);
}
public function syncOriginal()
{
$this->original = $this->attributes;
return $this;
}
If you want to check if the model is dirty just call isDirty():
if($product->isDirty()){
// changes have been made
}
Or if you want to check a certain attribute:
if($product->isDirty('price')){
// price has changed
}
You can use $product->getChanges() on Eloquent model even after persisting. Check docs here
I like to add this method, if you are using an edit form, you can use this code to save the changes in your update(Request $request, $id) function:
$post = Post::find($id);
$post->fill($request->input())->save();
keep in mind that you have to name your inputs with the same column name. The fill() function will do all the work for you :)
use only this:
Product::where('id', $id)->update($request->except(['_token', '_method']));
At times you need to compare the newly changed value with the previous one and if you are looking for that here is the solution.
if (
$obj->isDirty('some_field_name') &&
$obj->some_field_name != $obj->getOriginal('some_field_name')
) {
// Make required changes...
}
});
}
The reference of the derived solution is here.
Maybe Laravel has updated since, but wasChanged is working for me better than isDirty in all of these previous answers.
For example:
if($post->wasChanged('status') && $post->status == 'Ready') // Do thing

Zend MVC: one call from controller to model or more calls for differents results?

i need differents results from a model but i don't understand if it is correct make a single call and leave to model all the work or make more calls and collect the result to pass to the view when tables aren't joined or when i need fetch one row from a table and differents rows from others.
First example (more calls, collect and send to view):
CONTROLLER
// call functions of model
$modelName = new Application_Model_DbTable_ModelName();
$rs1 = $modelName->getTest($var);
$rs2 = $modelName->getTest2($var2);
// collect data
$pippo = $rs1->pippo;
if ($rs2->pluto == 'test') {
$pluto = 'ok';
} else {
$pluto = 'ko';
}
// send to view
$this->view->pippo = $pippo;
$this->view->pluto = $pluto;
MODEL
public function getTest($var) {
...
select from db...
return $result;
...
}
public function getTest2($var) {
...
select from db...
return $result;
...
}
Second example (one call, model collect all data, return to controller and send to view):
CONTROLLER
// call one function of model
$modelName = new Application_Model_DbTable_ModelName();
$rs = $modelName->getTest($var);
MODEL
public function getTest($var) {
...
select from db...
if ($result > 0) {
call other function
call other function
collect data
return $result;
...
}
Thanks
There's no one correct answer to this question, but in general, you should endeavor to keep your business logic in one place. Think of it as, "thin controller, thick model." I.e., keep the controllers as small and simple as possible and put all the business logic in the models.
There seems to be a few questions here:
But if i don't need to interact with db and i need only a simply
function is better put that function in model? For example:
CONTROLLER:
public function printAction() {
$data = $this->getRequest()->getPost();
$label = "blablabla";
$this->view->label = $label;
}
first, in the context of Zend Framework this particular example doesn't make much sense. The whole point of the controller is to populate the view template. However, I do get the idea. I would point you to Action Helpers and View helpers as a means to address your concerns. You can always add a utility class to your library for those pieces of code that don't seem to fit anywhere else.
Action Helpers typically are employed to encapsulate controller code that may be repetitive or reusable. They can be as simple or as complex as required, here is a simple example:
class Controller_Action_Helper_Login extends Zend_Controller_Action_Helper_Abstract
{
/**
* #return \Application_Form_Login
*/
public function direct()
{
$form = new Application_Form_Login();
$form->setAction('/index/login');
return $form;
}
}
//add the helper path to the stack in the application.ini
resources.frontController.actionhelperpaths.Controller_Action_Helper = APPLICATION_PATH "/../library/Controller/Action/Helper"
//the helper is called in the controller
$this->_helper->login();
a View helper does the same thing for the view templates:
class Zend_View_Helper_PadId extends Zend_View_Helper_Abstract
{
/**
* add leading zeros to value
* #param type $id
* #return string
*/
public function padId($id)
{
return str_pad($id, 5, 0, STR_PAD_LEFT);
}
}
//in this example the helper path is added to the stack from the boostrap.php
protected function _initView()
{
//Initialize view
$view = new Zend_View();
//add custom view helper path
$view->addHelperPath('/../library/View/Helper');
//truncated for brevity
$viewRenderer = Zend_Controller_Action_HelperBroker::getStaticHelper(
'ViewRenderer');
$viewRenderer->setView($view);
//Return it, so that it can be stored by the bootstrap
return $view;
}
//and to use the helper in the view template
//any.phtml
<?php echo $this->padId($this->id) ?>
i need differents results from a model but i don't understand if it is
correct make a single call and leave to model all the work or make
more calls and collect the result to pass to the view when tables
aren't joined or when i need fetch one row from a table and differents
rows from others.
This question is more about structure then about correctness.
You can interact with your database table models in Action and View helpers for simple/repetitive queries if you need to, however most developers might frown on this approach as being difficult to maintain or just ugly.
Many people seem to favor Doctrine or Propel to help them manage their database needs.
At this point I like to roll my own and currently favor domain models and data mappers, not an end all be all pattern, but seems to be appropriate to your question.
This is not a simple suggestion to implement for the first time, however i found two articles helpful to get started:
http://phpmaster.com/building-a-domain-model/
http://phpmaster.com/integrating-the-data-mappers/
and if you really want to get into it try:
http://survivethedeepend.com/
I hope this answers at least a part of your questions.

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