Sorting array by value - php

Question

I have this array:
array(
"tour_0" => 1446,
"tour_1" => 1471,
"date-from-1471" => "2014-08-07",
"date-to-1471" => "2014-08-15",
"tour_2" => 30,
"date-from-30" => 2014-08-01,
"date-to-30" => 2014-08-05,
"tour_3" => 10
)
Now, i need it to be sorted to this:
array(
"0" => array("ID" => 1446),
"1" => array("ID" => 1471, "from" => "2014-08-07", "to" => "2014-08-15"),
"2" => array("ID" => 30, "from" => "2014-08-07", "to" => "2014-08-15"),
"3" => array("ID" => 10),
)
How can i accomplish this thing?
I've tried all sorts of things but i can't seem to figure this one out...
Thank's and sorry about the title but i just don't know how to describe it.

Answer 1

How about this?
$ret = [];
foreach($inputArray as $key => $value) {
if (preg_match('/^tour_([0-9]+)/', $key)) {
$ret[$value] = ["ID" => $value];
}
if (preg_match('/date-from-([0-9]+)/', $key, $matches)) {
$ret[$matches[1]]["from"] = $value;
}
if (preg_match('/date-to-([0-9]+)/', $key, $matches)) {
$ret[$matches[1]]["to"] = $value;
}
}
print_r($ret);
/*
Array
(
"1446" => Array ("ID" => 1446),
"1471" => Array ("ID" => 1471, "from" => "2014-08-07", "to" => "2014-08-15"),
"30" => Array ("ID" => 30, "from" => "2014-08-01", "to" => "2014-08-05"),
"10" => Array ("ID" => 10)
)*/
Close enough? (it is quite trival change the keys of the array, considering they are in order (0, 1, 2, 3, ...), if they are not, maybe you can save the order also (in another item of the subarray) and recompose again once this array is formed)