Adding spaces in converted hex - php

I have this example data to be converted into hex
$converToHex = "##X27,5556789,A89,2*";
$convertedHex = bin2hex($converToHex);
how do I add spaces so that i can output something like this
23 23 58 32 37 2c 35 35 35 36 37 38 39 2c 41 38 39 2c 32 2a
Thank you in advance.

Use chunk_split() function in php to split the string into smaller parts.Use the code below :
<?php
$converToHex = "##X27,5556789,A89,2*";
$convertedHex = bin2hex($converToHex);
echo chunk_split($convertedHex, 2, ' ');
?>
Hope this helps you.

You can use the str_splitt function
In your case :
$converToHex = "##X27,5556789,A89,2*";
$convertedHex = bin2hex($converToHex);
$hexTab = str_split($convertedHex,2);
foreach($hexTab as $b){
echo $b." ";
}

Related

How to read a float from binary WebM file?

I'm trying to learn binary and create a simple WebM parser in PHP based on Matroska.
I read TimecodeScale, MuxingAppm WritingApp, etc. with unpack(format, data). My problem is when I reach Duration (0x4489) in Segment Information (0x1549a966) I must read a float and based on TimecodeScale convert it to seconds: 261.564s->00:04:21.564 and I don't know how.
This is a sample sequence:
`2A D7 B1 83 0F 42 40 4D 80 86 67 6F 6F 67 6C 65 57 41 86 67 6F 6F 67 6C 65 44 89 88 41 0F ED E0 00 00 00 00 16 54 AE 6B`
TimecodeScale := 2ad7b1 uint [ def:1000000; ]
MuxingApp := 4d80 string; ("google")
WritingApp := 5741 string; ("google")
Duration := 4489 float [ range:>0.0; ]
Tracks := 1654ae6b container [ card:*; ]{...}
I must read a float after (0x4489) and return 261.564s.
The duration is a double precision floating point value (64-bits) represented in the IEEE 754 format. If you want to see how the conversion is done check this.
The TimecodeScale is the timestamp scale in nanoseconds.
In php you can do:
$bin = hex2bin('410fede000000000');
$timecode_scale = 1e6;
// endianness
if (unpack('S', "\xff\x00")[1] === 0xff) {
$bytes = unpack('C8', $bin);
$bytes = array_reverse($bytes);
$bin = implode('', array_map('chr', $bytes));
}
$duration = unpack('d', $bin)[1];
$duration_s = $duration * $timecode_scale / 1e9;
echo "duration=${duration_s}s\n";
Result:
duration=261.564s

Parse error: syntax error, unexpected (T_VARIABLE)

I am executing some queries and am getting the following the error:
Parse error: syntax error, unexpected '$section2' (T_VARIABLE) on line
22
Line 22 is:
$section2 = $db->prepare("INSERT INTO learning_style_scores VALUES (5,12,4)");
I don't have a clue why I am getting this, I have checked my syntax and all seems to be correct. It basically doesn't like anything after the $section1 query is executed
EDIT:
I understand this is prone to SQL injection but I am doing it like this for testing purposes only.
<?php
session_start();
try {
$db = new PDO("mysql:dbname=questionnaire;host=localhost", "root", "");
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch(Exception $e)
{
echo 'Caught exception: ', $e->getMessage(), "\n";
}
$session = md5(session_id());
// insert section1 data into database
$section1 = $db->prepare('INSERT INTO section1 VALUES (7,"test")');
$section1->execute();​
// insert learning style score into database
$section2 = $db->prepare("INSERT INTO learning_style_scores VALUES (5,12,4)");
$section2->execute();​
?>
Your code has some weird characters after the semicolon of this line:
$section1->execute();​
$section2->execute();​ //same for this line
If you look into a hex editor you see this:
24 73 65 63 74 69 6f 6e 31 2d 3e 65 78 65 63 75 74 65 28 29 3b e2 80 8b
//^^^^^^^^This bit right here
//And it should look like this:
24 73 65 63 74 69 6f 6e 31 2d 3e 65 78 65 63 75 74 65 28 29 3b
See here:
(Yeah I know my circles aren't the nicest)
And this is how it should look like:
Solution?
Just write the statement new with your keyboard and your fingers.

Convert from ascii to hex in php

I'm trying to convert from ASCII to HEX in PHP but get a different result to some of the online tools that are available. I know the result I'm looking for so the online tool's result appear to be correct and my code incorrect but I can't work out why.
String: 2Ffbj?DoyXOU
Correct output: 32 46 66 62 6a 3f 44 6f 79 58 4f 55 (from linked site above)
My output: 32 46 66 62 6a 3f 44 6f 79 58 4f 75
My script:
echo bin2hex(utf8_decode("2Ffbj?DoyXOU"));
Where is the fault?
Use that:
function ascii2hex($ascii) {
$hex = '';
for ($i = 0; $i < strlen($ascii); $i++) {
$byte = strtoupper(dechex(ord($ascii{$i})));
$byte = str_repeat('0', 2 - strlen($byte)).$byte;
$hex.=$byte." ";
}
return $hex;
}
The result:
Try this:
function ascii2hex($arg){
return implode(" ",array_map(fn($x) => sprintf("%02s",strtoupper(dechex(ord($x)))),str_split($arg)));
}
Thanks Patrick Maciel for the good answer.
Now if use PHP 7.4, there maybe an error message "Array and string offset access syntax with curly braces is no longer supported". Using "[" and "]" to replace "{" and "}" can solve the problem.
Reference:
Array and string offset access syntax with curly braces is deprecated

PHP Problem reading the hex values between these addresses?

<?php
$file = 'file.dat';
$file_contents = file_get_contents($file);
for ($i = 0x000481; $i <= 0x00048B; $i++) {
print $i;
}
?>
I am creating an online file analyzer but I have a small problem. It outputs (which is the actual position the hex is in)
1153 1154 1155 1156 1157 1158 1159 1160 1161 1162 1163
when it should be
44 72 48 79 64 72 61 6C 69 73 6B
which his hex for DrHydralisk (me). Can anyone help me output the latter or just have it strait output ASCII (but hex is fine, I can just convert it)?
edit
Here is an image of what I am trying to do that I think will help.
http://imgur.com/nwenA.png
Here is the file I am trying to read, its a Starcraft replay (file.SC2Replay). Just search for DrHydralisk in a hex editor and that is where I am trying to read from.
http://www.mediafire.com/?6w8wi35q3o6ix8q
It should be (if clear text is in the file):
for( $i=0x481; $i<0x48D; $i++ ) {
printf("%X ", ord($file_contents[$i]));
}
Note the loop boundaries: 0x481 .. 0x48D
Result:
44 72 20 48 79 64 72 61 6C 69 73 6B
If the file contains hexadecimal numbers, this would be impossible because you need two bytes per hex char for the ascii character value range. So what is really in the file?
Edit
After reading your file, i did:
...
$file = 'file.SC2Replay';
$file_contents = file_get_contents($file);
for( $i=0x438; $i<0x443; $i++) {
printf("%X ", ord($file_contents[$i]));
}
for( $i=0x438; $i<0x443; $i++) {
printf("%s ", $file_contents[$i]);
}
...
And it says:
72 48 79 64 72 61 6C 69 73 6B
and
D r H y d r a l i s k
You messed up the file position ;-)
Regards
rbo
EDIT:
Thanks for providing the file, helped a lot! Beleive I got it working too:
//Do binary safe file read
$filename = 'file.SC2Replay';
$file = fopen($filename, "rb");
$contents = fread($file, filesize($filename));
fclose($file);
//position 1080 - 1091
for ($i = 0x438; $i < 0x443; $i++)
echo $contents[$i];
The reasons you were probably having problems is that first of all, a binary safe file read in php automatically replaces the bytes with the correct ASCII characters, so that threw off what position you actually needed to start reading from. Intead of 1153, it starts at 1080.
Could you explain how you are using the file you read in? Because the hex equivalent of:
11531154115511561157115811591160116111621163
is:
481 482 483 484 485 486 487 488 489 48a 48b
Also, there are two php functions you may find helpful
chr(int): returns the ascii character associated with the integer provided - http://php.net/manual/en/function.chr.php
dechex(int): returns the hex value of the integer provided - http://php.net/manual/en/function.dechex.php

PHP utf encoding problem

How can I encode strings on UTF-16BE format in PHP? For "Demo Message!!!" the encoded string should be '00440065006D006F0020004D00650073007300610067006'. Also, I need to encode Arabic characters to this format.
First of all, this is absolutly not UTF-8, which is just a charset (i.e. a way to store strings in memory / display them).
WHat you have here looks like a dump of the bytes that are used to build each characters.
If so, you could get those bytes this way :
$str = utf8_encode("Demo Message!!!");
for ($i=0 ; $i<strlen($str) ; $i++) {
$byte = $str[$i];
$char = ord($byte);
printf('%02x ', $char);
}
And you'd get the following output :
44 65 6d 6f 20 4d 65 73 73 61 67 65 21 21 21
But, once again, this is not UTF-8 : in UTF-8, like you can see in the example I've give, D is stored on only one byte : 0x44
In what you posted, it's stored using two Bytes : 0x00 0x44.
Maybe you're using some kind of UTF-16 ?
EDIT after a bit more testing and #aSeptik's comment : this is indeed UTF-16.
To get the kind of dump you're getting, you'll have to make sure your string is encoded in UTF-16, which could be done this way, using, for example, the mb_convert_encoding function :
$str = mb_convert_encoding("Demo Message!!!", 'UTF-16', 'UTF-8');
Then, it's just a matter of iterating over the bytes that make this string, and dumping their values, like I did before :
for ($i=0 ; $i<strlen($str) ; $i++) {
$byte = $str[$i];
$char = ord($byte);
printf('%02x ', $char);
}
And you'll get the following output :
00 44 00 65 00 6d 00 6f 00 20 00 4d 00 65 00 73 00 73 00 61 00 67 00 65 00 21 00 21 00 21
Which kind of looks like what youy posted :-)
(you just have to remove the space in the call to printf -- I let it there to get an easier to read output=)
E.g. by using the mbstring extension and its mb_convert_encoding() function.
$in = 'Demo Message!!!';
$out = mb_convert_encoding($in, 'UTF-16BE');
for($i=0; $i<strlen($out); $i++) {
printf("%02X ", ord($out[$i]));
}
prints
00 44 00 65 00 6D 00 6F 00 20 00 4D 00 65 00 73 00 73 00 61 00 67 00 65 00 21 00 21 00 21
Or by using iconv()
$in = 'Demo Message!!!';
$out = iconv('iso-8859-1', 'UTF-16BE', $in);
for($i=0; $i<strlen($out); $i++) {
printf("%02X ", ord($out[$i]));
}

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