preg_replace multiple times in same string - php

I have a text and I want to do something like Wiki code, creating links with [[]] and stuffs.
I am using this preg_replace to do that, and it seems to work:
<?=preg_replace("/\{\{([^\*]+)\|([^\*]+)\|([^\*]+)\}\}/", "<a href='$1.php#$2'>$3</a>", $conditions['pattern']); ?>
The problem is that when I have this text "can[not] build at %{{types|location|location}}% %{{some|other|stuff}}%" it outputs this:
can[not] build at %stuff%
It's like only the last one gets replaced, but wrong.
Any idea? Thanks


Fixed!
I changed the regular expression to /\{\{([a-zA-Z]+)\|([a-zA-Z]+)\|([a-zA-Z ]+)\}\}/ and now it works :D

Related

How to do this PHP find-replace

I think I need to use the preg_replace function but not sure exactly how to type in the patterns I want to find and replace. Basically, I want to replace this:
: u"x"x",
with this:
: u"x'x",
x means that any characters can go there. But I don't know how to write the x in PHP.
Thank you!
Edit: basically, I want to replace that middle double-quote with a single-quote. And I'll be searching through a big JSON file to do it. Probably should have said this at the start.

You could use this regular expression:
$result = preg_replace('#(: u".*?)"(.*?")#', "$1'$2", $string);

PHP: How would I remove parts of a string between 2 chunks of characters without removing too much?

This problem is driving me nuts. Let's say I have a string:
This is a &start;pretty bad&end; string that I want to &start;somehow&end; display differently
I want to be able to remove the &start; and &end; parts as well as everything in between so it says:
This is a string that I want to display differently
I tried using preg_replace with a regular expression but it took off too much, ie:
This is a display differently
The question is: how do I remove the stuff just between sets of &start; and &end; pairs and make sure that it doesn't remove anything between any &end; and &start; segments?
Keep in mind, I'm working with hundreds of strings that are very different to each other so I'm looking for a flexible solution that'll work with all of them.
Thanks in advance for any help with this.
Edit: Replaced dollar signs with ampersands. Oops!

Try this regex /\&start;(.+?)\$end;/g
It looks like it works as desired: https://regex101.com/r/MW5nom/2

I quickly tried it on chrome console using JS, tried converting it into PHP:
"This is a &start;pretty bad$end; string that I want to &start;somehow$end; display differently".replace(/\&start;(.+?)\$end;/g, "")

PHP preg_replace cuts of my $subject string

I was working on this project of mine when I encountered the following problem. I have a link which goes to:
file.php?page=1&color=all&pos=all&nat=all&mine=all&tree=all
Now, I wanted to change the color to 'gold' so I looked around on Google and found this php function called preg_replace(). So I implemented it in my code like this:
$pre='?page=1&color=all&pos=all&nat=all&mine=all&tree=all';
preg_replace('/color=(.*)&/', 'color=gold&', $pre);
For some reason my output is ?page=1&color=gold&tree=all so it seems that it cut of the middle of the code somehow.
This is the link I expect as my output: ?page=1&color=gold&pos=all&nat=all&mine=all&tree=all
Can anybody tell me what it is I'm doing wrong? Thanks!

Regular Expressions (regex) are greedy. You said "find color=" and then "get as much as you can until you see a &". What you want is "get as much as you can as long as it is not a &". That would be:
preg_replace('/color=[^&]*/','color=gold',$pre);
The [^&] means "anything except &". Also - you aren't using the match, so you don't need the parenthesis.

Regular expression for a redirect

I'm trying to write a regular expression for a redirect and not having any luck. In this example, an old URL might exist like this:
example.com/about-us/Default.asp
example.com/the-team/Default.asp
Which I want to redirect to:
example.com/about-us/
example.com/the-team/
I've come up with this:
/(\d*)/Default.asp
Which doesn't work...
I've also tried this:
/(\d*)/Default\.asp
As I thought there might be a problem with not having an escape char for the '.', still no luck. Can anyone see what I'm doing wrong?

Got it working thanks to what minitech pointed out:
/(.*)/Default.asp$
worked a treat! Thanks

Since you only need to remove the "Default.asp", you only have to search for that. The regex would look something like this
/Default\.asp/
The dot being escaped since the dot is a special character.
If you're using php, you can do a simple preg_replace
preg_replace('/Default\.asp/', '', 'example.com/about-us/Default.asp');

preg_match and remove multiple characters in string?

Hi I'm using php to program my site and I've been reading loads about preg_match and trying lots of examples. What I'm trying to do is something like below...
if(preg_match('These characters'), $myVariable, matches)){
Find and remove found characters from $myVariable;
}
I'm pretty sure this is obvious to php experts but it's had me stuck after hours of trying and reading.
Thanks in advance

You don't need to check for a match before doing a replace. It's like if you were to do:
str_replace("A","B","ZZZZZZZ");
It just won't replace anything. Same goes for preg_replace: If there is no match, it just does nothing.

It sounds like you should be using preg_replace. If you wanted to remove all y's and o's for example you would do this:
$string = 'hey you guys!';
$ans = preg_replace('/[yo]/','',$string);
print_r($ans); //outputs 'he u gus!'
Whatever characters you want to remove, just put them between the brackets [...]

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