pick out only files that were uploaded from the $_FILES array - php

Question

I've noticed when uploading multiple files using php, that the array contains data for all input fields from the form.
Suppose I have a from with 3 input fields, and a user were to upload only 2 files, how can I pick out only those two files from the array, maybe using some array function or anything else, so I can only loop thru those files.
I was trying using array_filer on tmp_name but cannot figure how to proceed.
if($_FILES && isset($_POST['handle'])) {
$numFiles = count(array_filter($_FILES['file']['tmp_name']));
if( $numFiles <= 2 ) {
// files that were uploaded will not have a blank value
$filesUploaded = array_filter($_FILES['file']['tmp_name']);
print_r($filesUploaded);// for testing
// loop through the above array
foreach($filesUploaded as $key) {// stuck
//echo each files attributes
echo $_FILES['file']['tmp_name'][$key].'<br>';
echo $_FILES['file']['name'][$key].'<br>';
echo $_FILES['file']['type'][$key].'<br>';
echo $_FILES['file']['size'][$key].'<br>';
echo $_FILES['file']['error'][$key].'<br>';
// proceed with the rest of the processing
}
} else {
echo 'Too may files uploaded';
}
} else {
echo 'Error A';
}

Answer 1

you are expecting like this?
To check whether the file uploaded or not:
if(is_uploaded_file($_FILES['image']['tmp_name'])) {}
Edited:
$fileUploads=$_FILES['file']['tmp_name'];
$countUpload=0;
foreach($fileUploads as $fileUpload){
if($countUpload>2) {
echo $_FILES['file']['tmp_name'];
//move_upload_file
}
$countUpload=$countUpload+1;
}

Answer 2

Check error status:
if ($_FILES['file']['error'][$key] == 0) {
echo $_FILES['file']['tmp_name'][$key];
}