results wont display properly - php

Question

<?php
$connection = #mysql_connect ("localhost","root","");
#mysql_select_db ("streamurl" , $connection) or die ('Error in DB Connection');
$select_all= "SELECT * FROM url";
$array = mysql_query($select_all, $connection);
if(isset($_POST['btn'])){
$mysql_query_rename = "UPDATE url SET ST_NAME='$_POST[name]', URL='$_POST[url]', ID='$_POST[id]' WHERE ID='$_POST[hidden2]' AND ST_NAME='$_POST[hidden3]' AND URL='$_POST[hidden1]' ";
if(mysql_query($mysql_query_rename, $connection)){
echo 'Changes were applied Successfully';
} else {
echo 'Changes Could not be Applied';
};
};
while ($show = mysql_fetch_array($array)){
echo "<form action=deletestation.php method=post>";
echo "<input type=text name=id value=$show[ID] >";
echo "<input type=text name=name value=$show[ST_NAME] >";
echo "<input type=text name=url value=$show[URL] >";
echo "<input name=hidden1 type=hidden value=$show[URL] >";
echo "<input name=hidden2 type=hidden value=$show[ID] >";
echo "<input name=hidden3 type=hidden value=$show[ST_NAME] >";
echo "<input name=btn type=submit value=UPDATE>";
echo "</form>";
};
mysql_close($connection);
?>
First of all im new to PHP and MYSQL
the above code is used to update a table in mysql database and i have echoed out the results in text boxes . there are only few information in the table ( Station name , ID and URL ). the problem is only the 1st result is updateable and the other results can not be updated . Except 1st result the other wont display the full Station name (ST_NAME) .
Kindly point out the the Error in my code.

Answer 1

<?php
$connection = mysql_connect ("localhost","Sithira","1sithiraM");
mysql_select_db ("streamurl" , $connection) or die ('Error in DB Connection');
$select_all= "SELECT * FROM url";
$array = mysql_query($select_all, $connection);
if(isset($_POST['btn'])){
$mysql_query_rename = "UPDATE url SET ST_NAME='$_POST[name]', URL='$_POST[url]', ID='$_POST[id]' WHERE ID='$_POST[hidden]' ";
if(mysql_query($mysql_query_rename, $connection)){
echo 'Changes were applied succesfully';
} else {
echo 'Changes Could not be Applied';
};
};
while ($show = mysql_fetch_array($array)){
echo "<form action=deletestation.php method=post >";
echo "<input type=text name=id value=$show[ID] >";
echo "<input type=text name=name value=$show[ST_NAME] >";
echo "<input type=text name=url value=$show[URL] >";
echo "<input name=hidden type=hidden value=$show[ID] >";
echo "<input name=btn type=submit value=UPDATE>";
echo "</form>";
};
mysql_close($connection);
?>
finally i got it working :)