I have problem in sending message to my client via socket,the string that I would like to send is like this "##w32,12345678,xxx,5*zy\r\n"
$msg = $_POST['comm_input']; //"##w32,12345678,xxx,5*zy\r\n"
if this is posted i get the value of $msg which is "##w32,12345678,xxx,5*zy\r\n"
but my client will not accept this kind of message..but if I manually do like this without posting the comm_input;
$testmsg = "##w32,12345678,xxx,5*zy\r\n";
It works fine,I tried to look at in firebug there is no double quotes and \r\n.and it works fine.
if I post the comm_input.and look at in the firebug there is double quotes and \r\n,how can I remove this.
You can use str_replace function to remove \r\n.
DEMO
<?php
$testmsg = "##w32,12345678,xxx,5*zy\r\n"; <-- $_POST value
$order = "\r\n";
$replace = "";
$newstr = str_replace($order, $replace, $testmsg);
echo $newstr; //outputs ##w32,12345678,xxx,5*zy
?>
using str_replace, you need to escape the \ with and extra \, hence, \r as string becomes \\r
$msg = $_POST['comm_input']; //"##w32,12345678,xxx,5*zy\r\n" ;
$new_msg = str_replace("\\r\\n", "", $msg);
Edit: to remove double quotes
$new_msg = str_replace('"', "", $new_msg);
Consider reading this article : Escape Sequence in PHP
you can use
$msg = "##w32,12345678,xxx,5*zy\r\n";
$str = rtrim($msg);
Refer trim() and rtrim()
Related
My code simply displays a random line from a text file,
But in my text file most of the proxies look like this: "11.15.19.15:80" I need help how to display only the address on the site, and remove the quotation marks.
<?php
$message_array = file("proxies.txt");
$message = array_rand($message_array);
echo "$message_array[$message]";
?>
All you need to do is wrap the string in a trim():
<?php
$message_array = file("proxies.txt");
$message = array_rand($message_array);
echo trim($message_array[$message], "\""); // 11.15.19.15:80
?>
Note that the second argument in trim() is needed, because your string contains the " characters, rather than uses them to denote the string itself. Adding an escaped backslash ("\"") removes the quotation marks from what is inside the string itself.
I've created a simple demonstration of this at 3v4l.org here.
I think you can use a regex like so:
preg_replace('/["]*/g', '', $message);
Use str_replace. Here is an example:
$message = str_replace('"', '',$message);
You can use the trim function if you just need to remove the double quotes:
$message = trim($message, '"');
Also str_replace:
$message = str_replace('"', '', $message);
This is a little complicated to explain but I'll try my hardest, I'm trying to create a tool to edit channel descriptions for TeamSpeak 3, to do this you use a feature called channeledit.
example usage: channeledit channel_description=My\sDescription
Presumably \s = space \n = newline, is there any possible way from using a textarea to php script to have it output the line as:
My\sDescription\nWelcome\sto\smy\sServer
Rather than appearing as:
My Description
Welcome to my Server
If there is spacing or line breaks, this kills the command and stops it working. Can anyone give me a bit of help here?
Code for this is:
$name = "Test
Test
Test test test";
$ts3_VirtualServer->execute("channeledit cid=" . $current_cid . " channel_description=" . $name);
$name = "Test Test
Test test test";
(string)$newname = str_replace(' ', '\\s', $name);
$newname = urldecode(str_replace('%0A', "\\n", urlencode($newname)));
You need to escape (\) the backslash (\). %0A 's are easier to find.
My output:
Test\sTest\nTest\stest\stest
$name=STR_replace(" ","/s",$name)
$name= str_replace("\n", '\n', $name);
If you want to replace spaces and carriage returns with literal \n and \s. I would do the following:
$name = urldecode(str_replace("%0D%0A","\\n",str_replace("+","\\s",urlencode($name))));
I am trying to go through the array string I called out from database and filtered to a readable state. The string could have a lot of \' and \", below is just an example.
$content = 'It\'s go to somewhere \"GREAT\"!';
I am trying to use str_replace but it is not working...
$content1= str_replace('\\\'', "'", $content );
$newcontent= str_replace('\\\"', '"', $content1 );
Output should be
It's go to somewhere "GREAT"!
instead.. I get
It\'s go to somewhere \"GREAT\"!
I looked at preg_replace, but I don't quite get all the /.. or where to start on it.
Please help.
Here's how
$content = 'It\'s go to somewhere \"GREAT\"!';
$content = stripslashes($content);
echo $content;
What you want to use is stripslashes($str).
Returns a string with backslashes stripped off. (\' becomes ' and so on.) Double backslashes (\) are made into a single backslash ().
$str = "Is your name O\'reilly?";
// Outputs: Is your name O'reilly?
echo stripslashes($str);
I am trying to pass a string to a javascript function which opens that string in an editable text area. If the string does not contain a new line character, it is passed successfully. But when there is a new line character it fails.
My code in PHP looks like
$show_txt = sprintf("showEditTextarea('%s')", $test_string);
$output[] = '<a href="#" id="link-'.$data['test'].'" onclick="'.$show_txt.';return false;">';
And the javascript function looks like -
$output[] = '<script type="text/javascript">
var showEditTextarea = function(test_string) {
alert(test_string);
}
</script>';
The string that was successfully passed was "This is a test" and it failed for "This is a first test
This is a second test"
Javascript does not allow newline characters in strings. You need to replace them by \n before the sprintf() call.
You are getting this error because there is nothing escaping your javascript variables... json_encode is useful here. addslashes will also have to be used in the context to escape the double quotes.
$show_txt = sprintf("showEditTextarea(%s)", json_encode($test_string));
$output[] = '<a href="#" id="link-'.$data['test'].'" onclick="'.htmlspecialchars($show_txt).';return false;">';
Why don't you try replacing all spaces in the php string with \r\n before you pass it to the JavaScript function? See if that works.
If that does not work then try this:
str_replace($test, "\n", "\n");
Replacing with two \ may work as it will encapsulate.
I would avoid storing HTML or JS in PHP variables as much as possible, but if you do need to store the HTML in a PHP variable then you will need to escape the new line characters.
try
$test_string = str_replace("\n", "\\\n", $test_string);
Be sure to use double quotes in the str_replace otherwise the \n will be interpreted as literally \n instead of a new line character.
Try this code, that deletes new lines:
$show_txt = sprintf("showEditTextarea('%s')", str_replace(PHP_EOL, '', $test_string));
Or replaces with: \n.
$show_txt = sprintf("showEditTextarea('%s')", str_replace(PHP_EOL, '\n', $test_string));
So when I run json_encode, it grabs the \r\n from MySQL aswell. I have tried rewriting strings in the database to no avail. I have tried changing the encoding in MySQL from the default latin1_swedish_ci to ascii_bin and utf8_bin. I have done tons of str_replace and chr(10), chr(13) stuff. I don't know what else to say or do so I'm gonna just leave this here....
$json = json_encode($new);
if(isset($_GET['pretty'])) {
echo str_replace("\/", "/", jsonReadable(parse($json)));
} else {
$json = str_replace("\/", "/", $json);
echo parse($json);
}
The jsonReadable function is from here and the parse function is from here. The str_replaces that are already in there are because I am getting weird formatted html tags like </h1>. Finally, $new is an array which is crafted above. Full code upon request.
Help me StackOverflow. You're my only hope
Does the string contain "\r\n" (as in 0x0D 0x0A) or the literal string '\r\n'? If it's the former, this should remove any newlines.
$json = preg_replace("!\r?\n!", "", $json);
Optionally, replace the second parameter "" with "<br />" if you'd like to replace the newlines with a br tag. For the latter case, try the following:
$json = preg_replace('!\\r?\\n!', "", $json);
Don't replace it in the JSON, replace it in the source before you encode it.
I had a similar issue, i used:
$p_num = trim($this->recp);
$p_num = str_replace("\n", "", $p_num);
$p_num = str_replace("\r", ",", $p_num);
$p_num = str_replace("\n",',', $p_num);
$p_num = rtrim($p_num, "\x00..\x1F");
Not sure if this will help with your requirements.