I have total number of trial period in a days.
For example, if i set 60 days as a trial period, then it needs to display 2 month
If i set 45 days as a trial period, then it needs to display 1 month and 15 days.
How can we convert to total number of days to month using php?
This code isn't really correct (and month not always have 30 days, but that's like your example is) but it does what you want:
$days = floor($totalDays / 30);
$months = $totalDays % 30;
echo $months . " months and " . $days . " days";
Related
I need to calculate a duration that is expressed in human readable format (e.g. "3 months 10 days") and make it a timestamp.
My problem is that with my code uses strtotime, so if a month is 30 days long PHP interprets it as 0 months 30 days instead of 31 days.
What I need is to convert, for example, the string "1 month 10 days" to "31 days 10 days" (or "41 days").
$strToTime = strtotime($pMsg);
$unixTimestamp = $strToTime - time();
$unixTimestampM = $unixTimestamp;
$months = floor((float)$unixTimestampM/2678400);
if($months >= 1) {
$unixTimestampM -= $months*2678400;
}
$days = floor((float)$unixTimestampM/86400);
if($days >= 1) {
$unixTimestampM -= $days*86400;
}
and so on for hours and minutes.
With the string "1 month 10 days" I expect the $months to be 1 and $days to be 10, while, in certain periods of the year, $days become 9.
I need to convert 30 days to 1 month .If months and days are means then like 1 years 2 month 2 days
I have tried below but it will return wrong result
echo CarbonInterval::days(30)->cascade()->forHumans();
Can any one help me how i can achieve this ?
I have tried below solution but got only 2 days difference
$convert = '30'; // days you want to convert
$years = ($convert / 365) ; // days / 365 days
$years = floor($years); // Remove all decimals
$month = ($convert % 365) / 30.5; // I choose 30.5 for Month (30,31) ;)
$month = floor($month); // Remove all decimals
$days = ($convert % 365) % 30.5; // the rest of days
// Echo all information set
echo 'DAYS RECEIVE : '.$convert.' days<br>';
echo $years.' years - '.$month.' month - '.$days.' days';
Is there any good solution using carbon
Does it have to be CarbonInterval?
What about Carbon::now()->subDays(1827)->diffForHumans()?
The reason it doesn't work as you're expecting (from https://carbon.nesbot.com/docs/#api-interval):
Default factors are:
1 minute = 60 seconds
1 hour = 60 minutes
1 day = 24 hour
1 week = 7 days
1 month = 4 weeks
1 year = 12 months
CarbonIntervals do not carry context so they cannot be more precise
(no DST, no leap year, no real month length or year length
consideration).
I currently have code that changes the month number and MYSQL table every month automatically but the timer it displays still resets every 24 hours. I need to make it so the timer resets every month instead of every 24 hours. I am not thinking straight and need some help solving this.
Basically I need it so that $month_end_time counts down from 30 days, 0 hours, 0 minutes 0 seconds down to 0 days, 0 hours, 0 minutes 0 seconds and then resets back to the 30 days. Currently it counts down from 30 days to 29 days then resets as it is from a script that resets every 24 hours and I am porting it to monthly.
Credits to #ElmoVanKielmo for the original snippet.
Thanks in advance.
define("FIRST_DAY_STRING", "2014-4-6");
define("SHIFT_DAYS", 'P30D');
define("TIME_SUFFIX", " 0:00:00 GMT+11:00");
$today = new DateTime();
$first_day = new DateTime(FIRST_DAY_STRING);
$interval = $first_day->diff($today);
$days = $interval->format('%R%a days');
$end_date = $today->add(new DateInterval(SHIFT_DAYS));
$month_number = floor(intval($days) / 30 + 1);
$txid = "tx$month_number";
$month_end_time = $end_date->format('Y-n-j');
$month_end_time .= TIME_SUFFIX;
I suspect you're possibly overthinking this, since it includes "dates". When moving around months, it can be tricky, since (as Raptor notes), months have differing number of days between each other.
However, based on your comments, you're actually looking for the number of 30-day periods between one date and another. This can be accomplished with basic math and Unix timestamps:
$start = strtotime('2012-04-12 00:00:00 GMT');
$today = strtotime('00:00:00 GMT');
$days = ($today - $start) / 60 / 60 / 24;
$months = $days / 30;
echo "<pre>
Days: $days
Months: $months
";
This will give:
Days: 723
Months: 24.1
http://codepad.viper-7.com/KBVfqq
And if you're trying to figure out how many days:
$start = strtotime('2012-04-12 00:00:00 GMT');
$today = strtotime('00:00:00 GMT');
$days = ($today - $start) / 60 / 60 / 24;
$months = $days / 30;
$months_days = floor($months) . " months, " . ($days - (floor($months) * 30)) . " days";
echo "<pre>
Days: $days
Months: $months
Months and Days: $months_days
";
Giving:
Days: 723
Months: 24.1
Months and Days: 24 months, 3 days
http://codepad.viper-7.com/AdnFsu
Which means that between the start and today's date, there have been 24 full 30-day periods, and we are currently in the 25th period (ceil($months)). This seems sufficient for what you are after, although the specific use of the period value may require better explanation.
I'm comparing dates with this code:
$date1 = new DateTime("2007-03-24 12:10:00");
$date2 = new DateTime("2009-06-26 14:00:30");
$interval = $date1->diff($date2);
If I echo this: echo $interval->m." months and".$interval->d." days."; I get the output 3 months and 2 days.. Now, I want to echo the difference between the dates but include the amount of months in the day count, so a difference of 1 month (with 30 days in it) and 5 days would be 35 days, not 1 month and 5 days. How do I do this?
I'm using PHP version 5.3+.
You should be able to use:
$interval->days;
See: http://www.php.net/manual/en/class.dateinterval.php#dateinterval.props.days
echo "There are ".$interval->days." days between the two dates.";
Your $interval variable is of type DateInterval.
Therefore, $interval->days should yeld the desired output.
I am completely stuck here. I am trying to get how many days hours and minutes to echo from a calculation from the current time to 7 days from now at 6pm. I look at the amount of seconds produced from my $difference variable and when I do the math to convert it to days hours and minutes it is correct but for some reason when I call the specific days, hours, and minutes in my output statement it is incorrect. What am I doing wrong. Here is the code.
<?php
date_default_timezone_set('America/New_York');
$nextWeek = strtotime('+7 days');
$m = date('n', $nextWeek);
$d = date('j', $nextWeek);
$y = date('Y', $nextWeek);
$difference = mktime(18,0,0,$m,$d,$y) - time();
echo '<p>Current date and time is' .date(' l F d, Y '). 'at '.date('g:i a').' You have an appointment in a week on '.date(' n/j/Y ', $nextWeek).' at 6pm. There are ' .date(' j ', $difference).' days, ' .date(' g ', $difference).' hours, and ' .date(' i ', $difference).' minutes until your appointment.</p>';
echo mktime(18,0,0,$m,$d,$y),"\n";
echo $difference;
?>
The problem is that you're using PHP's date() function on a number that doesn't represent a date. Your variable $difference represents the difference between the two dates, in seconds. To get the right output, you should write your own function to convert these seconds to number of days, hours, minutes, etc.
It might look something like this:
function getTimeText($seconds)
{
$return = array();
$return["days"] = floor($seconds/86400); // 86400 seconds in a day
$seconds -= ($return["days"]*86400);
$return["hours"] = floor($seconds/3600); // 3600 seconds in an hour
$seconds -= ($return["hours"]*3600);
$return["minutes"] = floor($seconds/60); // 60 seconds in a minute
return $return;
}
Try checking out this. The example part way down the page shows you how to find the difference between two dates in days. You should be able to use it to return the difference between the current time and the time in 7 days at 18:00 by changing the format.