Foreward: beginner PHP here.
I have a large table I have created on a page that is dynamically created from user defined settings. It is about 1600 rows and 15 columns. I have also populated an array with this data where Key 0 = All the values of row 1 separated by commas. Key 1 = all the values of row 2 separated by commas.
The Array was populated from a loop as the table was created and has the name/structure:
$CSVOut[$CSVKey]
I have confirmed the array is populated and displaying properly on the first page.
I have a button that calls 'textexport.php' with the following code:
<?php
header("Content-type: text/csv");
header("Content-Disposition: attachment; filename=file.csv");
header("Pragma: no-cache");
header("Expires: 0");
outputCSV(array(
array("name 1", "age 1", "city 1"),
array("name 2", "age 2", "city 2"),
array("name 3", "age 3", "city 3")
));
function outputCSV($data) {
$output = fopen("php://output", "w");
foreach ($data as $row) {
fputcsv($output, $row); // here you can change delimiter/enclosure
}
fclose($output);
}
?>
The sample array in TestExport.php accurately exports a CSV of the hardcoded array. I have searched and tried multiple ways for multiple days on how to get the array $CSVOut from my first page to this page and use the function to populate my CSV but it is not coming together for me.
I've tried POST methods (I've been able to successfully POST other user variables on this page so I kind of understand how it works) and tried SESSIONS (but don't fully grasp this concept yet)
I have a couple questions:
1) How bad of a method is this to try and export a dynamically created html table as a CSV?
2) What would be the best (easiest?) method?
3) Anybody have some guidance/example on how to do this?
4) Is it possible to do it in reverse - just call this function on the first page with the populated array?
For everything else in this project I've been able to find existing examples to adapt for my project but I haven't been able to really get this one right. Any help would be much appreciated.
If you don't want to (or don't have time to) bother with back end data storage and user sessions the best solution may simply be to use JavaScript/jQuery to slice and dice the dynamic output that the user has created into a CSV formatted string that the user can copy and paste out. Simply grabbing the table that they have made and processing each row should suffice...using jQuery will make it easier.
var rows = $('#example tbody').find('tr');
var output_string = '';
rows.each(function() {
var column_data = jQuery.map( $(this).find('td'), function(datum) {
return $(datum).text().replace(/\s/gi,'');
});
output_string += column_data.join(',')+'\n';
});
$('#output').val(output_string);
The above code will grab the body portion of an HTML table (ignoring any table headings you have defined) and turn each table row into a line of comma-separated values terminated with a newline.
It then dumps the created output into a textarea.
JSFiddle Example
This is not as fancy as temporarily saving the content to Mongo/MySQL and serving it back to the user with the click of a button - but it can be done quickly and without having to sort out data storage, sessions, authentication, etc. However those are fairly common parts of a full web stack so I suggest you take some time to familiarize yourself with them at some point. Here are some useful links.
Wamp or XAMPP are full service PHP,MySQL and Apache stacks which are great for getting up and running with Development without wasting a lot of time fiddling with server configs.
And here is a basic explanation/tutorial of Sessions in PHP. Also consider a little light reading, there are many security pitfalls that starting PHP Developers can fall into and this book covers the most avoidable ones.
Related
I really need help. I'm using an API to gather artist information depending on the artist name ($artist_name = $_GET['artistname']).
I need to add the API results into an array and store it into a file (NOT a database). This file will be ever growing as more and more artist entries are added to it.
Once I have an array in the file, I need to be able to read it and parse it. That way I can display the information without repeatedly using the API.
I have figured out how to add an array to a file with one entry, but how can I add more keys into the same array?
This is what I'm using now...
//ARRAY
$artist_info_location_array = array($artist_name => $location_entry);
//FILE
$artist_location_file = get_template_directory()."/Database/Artists/info-location.json";
//GET ARRAY FILE
$get_location_array[] = json_decode(file_get_contents($artist_location_file), true);
if (is_array($get_location_array)) {
if (!array_key_exists($artist_name, $get_location_array)) {
file_put_contents($artist_location_file, json_encode($artist_info_location_array));
}
}
It prints this to the file:
{"Imagine Dragons":"Las Vegas, NV, US"}
That's cool, but I need to be able to add more artists to this SAME ARRAY. So the result should look like this with another artist added:
{"Imagine Dragons":"Las Vegas, NV, US", "Adele":"London, UK"}
That shows Imagine Dragons and Adele both added to the same array.
Can someone help me "append" or add extra keys and values to the same array as they are added to the file?
Thanks.
EDIT 1 (In response to Martin):
I have a panel on the side of the page in question. This panel will show relevant information about the artist that has been searched for. Let's say you search for the artist "Adele". $artist_name would = Adele.
Lets say I'd like to store all artist locations, I would use the example I posted to store each artist location in the file called info-location.json ($artist_location_file).
So every time an artist page is loaded, the artist name and location would be added to the array in the file.
If my example doesn't make any sense, please show me an example on how to add multiple entries into ONE ARRAY. I am using an API and would like to cache this information to use instead of requesting the API on each load.
Hope this makes sense. :)
I might be misunderstanding your question, but if you just want to read in a json file, add an associative array key to it if it does not exist and then put it back into the json file why dont you do something like this:
if (is_array($get_location_array)) {
if (!array_key_exists($artist_name, $get_location_array)) {
$get_location_array[$artist_name] = $location;
file_put_contents($artist_location_file, json_encode($artist_info_location_array));
}
}
file_put_contents will overwrite an existing file (pretty sure). But your best option is to use a database. If you can't do that, then I suggest to prevent writing to the file while you are doing this I suggest you use fopen, flock, and fwrite and then fclose
This code works, but I just hacked it together with my limited knowledge of PHP and I'm sure there's a more elegant and efficient way to go about it. If you'd be so kind as to point out how I can improve, that would be great!
So I have a CSV file, structured like so:
Code Class Value Status Date Created Date Redeemed
========================================================================
a51f3g45 gold 50 valid 2012-08-20
4f6a2984 silver 200 redeemed 2012-08-23 2012-08-27
gf3eb54b gold 150 valid 2012-08-30
etc...
The user fills out a form to change the Class, Value, and Status fields of a given line. I cobbled together the following code to replace the old values with the new ones:
$file = 'codes.csv';
$old_csv_string = file_get_contents($file);
preg_match('/('.$_POST['code'].',.*,.*,.*,.*,.*)\n/',$old_csv_string,$matches);
$old_row = $matches[1];
preg_match('/'.$_POST['code'].',(.*,.*,.*),.*,.*\n/',$old_csv_string,$matches_part);
$old_row_part = $matches_part[1];
$new_row_part = $_POST['class'].",".$_POST['value'].",".$_POST['status'];
$new_row = str_replace($old_row_part,$new_row_part,$old_row);
$new_csv_string = str_replace($old_row,$new_row,$old_csv_string);
file_put_contents($file,$new_csv_string);
So can I do better than 10 lines of code? Any advice would be greatly appreciated :)
Note: I tried using fgetcsv, but I couldn't figure out how to find the unique code within a 2D array, then replace its siblings.
Why are you doing this ?
I think you should store the data in a SQL table.
Each time user update data, do it in the table.
If you want the CSV to be downloadable at any moment. Use a .htaccess to redirect your.csv to csv_generator.php only if your.csv does not exist.
csv_generator.php will regenerate the whole csv if it does not exist, save it on hard drive for later use, and send it with correct mime/type in header (so it's transparent for user). User don't see he is requesting a php page.
Then you need to delete the csv on hard drive each time someone update the data (so it will be regenerated on next request)
I think this is the way to have an always ready to download csv online.
Do you know google doc does this ? Users can change data in a spreadsheet wich is available to download as a csv from a url (you need to publish this spreadsheet as a csv file).
Try using split like that for each line:
list($code, $class, $value, $status, $created, $redeemed) = split(",", $line, 6) ;
Thus you will have each field in separate variable.
Of course you need to take care of the first row in case you don't want to copy header.
I am doing this flash banners for multiple clients and one major request is to have some sort of counter so they know how many times the banner has been clicked.
I know how to do it in ActionScript 3.0, I make a simple var:int and i increase it +1 when a click is made on the banner. What do I do with the value of this var(say its 121) where do I store it online so its safe and can be changed by multiple flash banners(as3).
But how do I save this information so next time when the banner is loaded(on diffrent webpages) the number of clicks is whatever it was last time it was loaded.
Should I look into PHP for that ? I have no clue how to do this... some examples, tutorials, whatever works... would be much appreciated.(I am a designer, not programmer...please dont speak php-ish, or you know... :D)
I've googled a bit, and found some help, but i am still confused, and much of it its not AS3, I'm thinking maybe stuff has evolved a bit since the stuff that I found(2008)...
Thank you very much.
You'd have to store (and fetch) the value somewhere - either in the DB, in a text-file, ...
I'd go search for a tutorial on PHP+MySQL. If you don't like PHP-ish, you're probably better of finding another solution though :p
Example tutorial: http://www.freewebmasterhelp.com/tutorials/phpmysql
You need to store the data you want be retrievable/update-able from multiple clients, to be stored on a server.
You can use any server side language with a database.
Server Languages : PHP, ASP.net, JSP, ColdFusion
Database : MySQL, MSSQL, PostgreSQL, Oracle, DB2 etc..
Use whatever combination you are comfortable with.
In general:
You have a web app that increments the counter in the database
call the page using URLLoader from your AS3 banner.
Database
counter_table
-------------
counter INT
PHP File
$db = mysql_connect('localhost', 'mysql_user', 'mysql_password');
mysql_select_db('database_name');
mysql_query('UPDATE counter_table SET counter = counter + 1');
AS3 Banner
// url request with your php page address
var scriptRequest:URLRequest = new URLRequest("http://www.example.com/script.php");
// loader
var scriptLoader:URLLoader = new URLLoader();
// load page to trigger database update
scriptLoader.load(scriptRequest);
Do you also want to retrieve the value of the number of clicks in Banner ?
Easy solution (really not the best :) You should use one of the other answers.. anyways, make a php file that reads txt file containing the count of visits.. and in your flashbanner just call the php file. It'll add one hit per call..
PHP:
<?php
/**
* Create an empty text file called counterlog.txt and
* upload to the same directory as the page you want to
* count hits for.
*
*
* #Flavius Frantz: YOU DONT NEED THESE:
* Add this line of code on your page:
* <?php include "text_file_hit_counter.php"; ?>
*/
// Open the file for reading
$fp = fopen("counterlog.txt", "r");
// Get the existing count
$count = fread($fp, 1024);
// Close the file
fclose($fp);
// Add 1 to the existing count
$count = $count + 1;
// Display the number of hits
// If you don't want to display it, comment out this line
//echo "<p>Page views:" . $count . "</p>";
// Reopen the file and erase the contents
$fp = fopen("counterlog.txt", "w");
// Write the new count to the file
fwrite($fp, $count);
// Close the file
fclose($fp);
?>
Example code from: (google: php counter file) http://www.totallyphp.co.uk/text-file-hit-counter
Code is not tested, but looks ok. I only commented just a little..
OK, here's my dilemma:
I've read all over about how many guys want to be able to display a set of images from Flickr using PHPFlickr, but lament on how the API for PhotoSets does not put individual photo descriptions. Some have tried to set up their PHP so it will pull the description on each photo as the script assembles the gallery on the page. However, the method has shown how slow and inefficient it can be.
I caught an idea elsewhere of creating a string of comma separated values with the photo ID and the description. I'd store it on the MySQL database and then call upon it when I have my script assemble the gallery on the page. I'd use explode to create an array of the photo ID and its description, then call on that to fill in the gaps...thus less API calls and a faster page.
So in the back-end admin, I have a form where I set up the information for the gallery, and I hand a Set ID. The script would then go through and make this string of separated values ("|~|" as a separation). Here's what I came up with:
include("phpFlickr.php");
$f = new phpFlickr("< api >");
$descArray = "";
// This will create an Array of Photo ID from the Set ID.
// $setFeed is the set ID brought in from the form.
$photos = $f->photosets_getPhotos($setFeed);
foreach ($photos['photoset']['photo'] as $photo) {
$returnDesc = array();
$photoID = $photo['id'];
$rsp = $f->photos_getInfo($photoID);
foreach ($rsp as $pic) {
$returnDesc[] = htmlspecialchars($pic['description'], ENT_QUOTES);
}
$descArray .= $photoID."|~|".$returnDesc[0]."|~|";
}
The string $descArray would then be placed in the MySQL string that puts it into the database with other information brought in from the form.
My first question is was I correct in using a second foreach loop to get those descriptions? I tried following other examples all over the net that didn't use that, but they never worked. When I brought on the second foreach, then it worked. Should I have done something else?
I noticed the data returned would be two entries. One being the description, and the other just an "o"...hence the array $returnDesc so I could just get the one string I wanted and not the other.
Second question is if I made this too complicated or not. I like to try to learn to write cleaner/leaner code, and was looking for opinions.
Suggestions on improvement are welcome. Thank you in advance.
I'm not 100% sure as I've just browsed the source for phpFlickr, and looked the the Flickr API for the getInfo() call. But let me have a go anyway :)
First off, it looks like you shouldn't need that loop, like you mention. What does the output of print_r($rsp); look like? It could be that $rsp is an array with 1 element, in which case you could ditch the inner loop and replace it with something like $pic = $rsp[0]; $desc = $pic['description'];
Also, I'd create a new "description" column in your database table (that has the photo id as the primary key), and store the description in their on its own. Parsing db fields like that is a bit of a nightmare. Lastly, you might want to force htmlspecialchars to work in UTF8 mode, cause I don't think it does by default. From memory, the third parameter is the content encoding.
edit: doesn't phpFlickr have its own caching system? Why not use that and make the cache size massive? Seems like you might be re-inventing the wheel here... maybe all you need to do is increase the cache size, and make a getDescription function:
function getDescription ($id)
{
$rsp = $phpFlickr->photos_getInfo ($id);
$pic = $rsp[0];
return $pic['description'];
}
After spending 3 days on internet and struggling with so many different forums , i have found a match and similar case of my problem here.
Friends, I am zero in PHP, but still i have managed to do something to fulfill my requirement.
I am stuck with one thing now..So i need help on....
I am using one html+php form to submit database into mysql.
I created a display of that table through php script on a webpage.
Now i want a datepicker option on that displayed page by which i should able to select the date range and display the data of that date range from my mysql table.
And then take a export of data displayed of selected date range in excel.
This displayed page is login protected, so i want after login the next thing comes in should show a sate selection option which should be fromdate to to date , and then records should displayed from the database and i can take export of those displayed results in excel file.
The code i am using on this page is below which do not have any thing included for excel export and date picker script, I am pasting the code here and request you to please include the required code in it as required.
Thanks In advance
<?php
//database connections
$db_host = 'localhost';
$db_user = '***********';
$db_pwd = '*************';
$database = 'qserves1_uksurvey';
$table = 'forms';
$file = 'export';
if (!mysql_connect($db_host, $db_user, $db_pwd))
die("Can't connect to database");
if (!mysql_select_db($database))
die("Can't select database");
// sending query
$result = mysql_query("SELECT * FROM {$table} ORDER BY date desc");
if (!$result) {
die("Query to show fields from table failed");
}
$num_rows = mysql_num_rows($result);
$fields_num = mysql_num_fields($result);
echo "$num_rows";
echo "<h1></h1>";
echo "<table border='1'><tr>";
// printing table headers
for($i=0; $i<$fields_num; $i++)
{
$field = mysql_fetch_field($result);
echo "<td>{$field->name}</td>";
}
echo "</tr>\n";
// printing table rows
while($row = mysql_fetch_row($result))
{
echo "<tr>";
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
foreach($row as $cell)
echo "<td>$cell</td>";
echo "</tr>\n";
}
mysql_free_result($result);
?>
</body></html>
This isn't a "write my code for me, please" site, so you're going to need to be a little more engaging and pro-acive. But we can certainly provide some guidance. Let's see...
Currently you have a page which displays all records from a given table, is that correct? And you need to do two things:
Before displaying any records, have the user select a date range. And keep the date range selection on the page so the user can re-select.
Provide a button which lets the user export the selected records to Excel.
For either of these, you're going to need to add an actual form to the page. Currently there isn't one. For the date picker, I recommend (naturally) using the jQuery UI datepicker. So the form for that would look something like this:
<form method="POST" action="myPHPFile.php">
<input type="text" id="fromDate" name="fromDate" />
<input type="text" id="toDate" name="toDate" />
<input type="submit" name="filterDate" value="Submit" />
</form>
<script>
$(function() {
$("#fromDate").datepicker();
$("#toDate").datepicker();
});
</script>
You may have to wrap the JavaScript in a $(document).ready(){} in order to make it work correctly, you'll want to test that. Anyway, this will give you a form to submit the dates to your script. Wrap the parts of your script which output data in a conditional which determines if the form values are present or not. If they're not, don't fetch any records. If they are, do some basic input checking (make sure the values are valid values, make sure fromDate is before toDate, etc.) and construct your SQL query to filter by date range. (Do take care to avoid SQL injection vulnerabilities here.)
For the Excel output, you may be able to find a ready-made solution for you that just needs a little tinkering. If I were to create one from scratch, I'd probably just output to a .csv file rather than a full Excel file. Most users don't know/care the difference. In that case, you'd just want to either create a second script which is nearly identical to the existing one or add a flag to the existing one which switches between HTML and CSV output, such as via a hidden form field.
For the output of the CSV, first make sure you set your response headers. You'll want to write a header to tell the browser that you're outputting a CSV file rather than text/html, and possibly suggest a file name for the browser to save. Then, the form inputs the SQL query will all be pretty much the same as before. The only difference is in the "HTML" that's being output. Rather than HTML tags, you'd wrap the records in commas, double-quotes (where appropriate), and carriage returns.
There's really nothing special to outputting a "file" vs. "HTML" because the HTTP protocol has no distinction between the two. It's always just text with headers.
Now, I'm sure you have more questions regarding this. And that's fine. In fact, we like to encourage asking (and, of course, answering) questions here. So please feel free to ask for clarification either in comments on this answer (or other answers), or by editing and refining your original question, or by asking an entirely new question if you have a specific topic on which you need help. Ideally, a good question on Stack Overflow consists of sample code which you are trying to write, an explanation of what the code is supposed to be doing, a description of the actual resulting output of the code, and any helpful information relevant to the code. As it stands right now, your question provides code somewhat unrelated to what you're asking, and you're just requesting that we add some features to it outright for you.