I have a categories table where I have different categories. I have also add Other in the category. When I'm getting the categories to populate the select I want the other option to appear at last. how can I do that?
<select name="category" id="category" class="form-control <?php if (isset($errors['category'])) echo 'form-error'; ?>">
<option value="">Select a category...</option>
<?php while ($category = mysqli_fetch_assoc($categories)) { ?>
<option value="<?php echo h($category['id']); ?>" <?php if (isset($_POST['category']) && h($category['id']) === $_POST['category']) echo 'selected'; ?>><?php echo h($category['name']); ?></option>
<?php } ?>
</select>
If the Id of Other category is fixed, then you have to ignore it in your database query.
Let's say that the Id of that option is 1, our query will be like this:
select * from categories where Id <> 1
This query brings all categories except "other".
After that do the following:
<select name="category" id="category" class="form-control <?php if (isset($errors['category'])) echo 'form-error'; ?>">
<option value="">Select a category...</option>
<?php while ($category =
mysqli_fetch_assoc($categories)) { ?>
<option value="<?php echo h($category['id']); ?>" <?php
if (isset($_POST['category']) && h($category['id']) ===
$_POST['category']) echo 'selected'; ?>><?php echo
h($category['name']); ?></option>
<?php } ?>
<option value="1">Other</option>
</select>
hope it helps
Is there a way to display the $city from the database into a select input ? using a loop or anything ? find my trials below: thank you in advance
PHP CODE
<?php
//get city value
if($city == 'Choose City') {
$city = $row['City'];
}
?>
HTML CODE
<select name="City">
<option value="0" selected>Choose City</option>
<option value="1">Milan</option>
<option value="2">Paris</option>
...
</select>
Here is what I use the $mydata variable being the connection code I can add that if you need it. Tis code will loop round all the cities as many times there are cities.
while($record = mysql_fetch_array($mydata)){
echo $record['City'] ;
echo "<br>";
}
I hope this helps! Ask if you need any other help!
do it simply as:
<select name="City">
<option value="0" selected>Choose City</option>
<?php
//your loop while or any other to fetch city array
//get city value
if($city == 'Choose City')
{ ?>
<option value="<?php echo $row['City']; ?>"><?php echo $row['City']; ?></option>
<?php
}
//end loop
?>
</select>
Here I am listing all cars.customers want to compare car so they will select from this drop down. A person can select multiple cars. At the first time he is selecting 'Audi' and Saab' I will store it into data base next if he came I need to populate Saab and audi as select how I can do this using php
<select name="cars" multiple>
<option value="volvo">Volvo</option>
<option value="saab">Saab</option>
<option value="opel">Opel</option>
<option value="audi">Audi</option>
</select>
Here is my code
<select id="cars" class="multiselect" multiple="multiple" name="cars[]">
<?PHP
if($carslist->num_rows() >0)
{
foreach($carslist->result_array() as $entry):
?> <option value="<?php echo($entry['ID']); ?>" ><?php echo($entry['car_name']); ?></option>
<?php
endforeach;
}
?>
</select>
Following code I tried $resources contain select cars
<select id="cars" class="multiselect" multiple="multiple" name="cars[]">
<?PHP
if($carslist->num_rows() >0)
{
foreach($carslist->result_array() as $entry):
if($resources->num_rows() >0)
{
foreach($resources->result_array() as $car):
if($entry['ID'] == $employee['car_id'])
{
$select = 'selected="selected"';
}
else
{
$select = '';
}
endforeach;
}
?> <option value="<?php echo($entry['ID']); ?>" <?php echo $select;?> ><?php echo($entry['car_name']); ?></option>
<?php
endforeach;
}
?>
</select>
but it showing error
Here, try something like this, and see if it works:
Here is the controller:
<?php
function something(){
$data = array();
$data['cars'] = $this->some_model->some_function_to_return_cars_array();
$data['selected'] = $some_array_of_selected_cars();
$this->load->view('some_view', $data);
}
?>
And this is the view:
<select id="cars" class="multiselect" multiple="multiple" name="cars[]">
<option value="">Select:</option>
<?php
foreach( $cars as $key => $val ){
?>
<option value="<?php echo $val['some_id'] ?>"
<?php
if( in_array( $val['some_id'], $selected ) ) echo ' selected';
?>
><?php echo $val['some_name'] ?></option>
<?php
}
?>
</select>
I need to get selected value from db into select box. please, tell me how to do it. Here is the code.
Note: 'options' value depends on the category.
<?php
$sql = "select * from mine where username = '$user' ";
$res = mysql_query($sql);
while($list = mysql_fetch_assoc($res)){
$category = $list['category'];
$username = $list['username'];
$options = $list['options'];
?>
<input type="text" name="category" value="<?php echo '$category' ?>" readonly="readonly" />
<select name="course">
<option value="0">Please Select Option</option>
<option value="PHP">PHP</option>
<option value="ASP">ASP</option>
</select>
<?php
}
?>
I think you are looking for below code changes:
<select name="course">
<option value="0">Please Select Option</option>
<option value="PHP" <?php if($options=="PHP") echo 'selected="selected"'; ?> >PHP</option>
<option value="ASP" <?php if($options=="ASP") echo 'selected="selected"'; ?> >ASP</option>
</select>
The easiest way I can think of is the following:
<?php
$selection = array('PHP', 'ASP');
echo '<select>
<option value="0">Please Select Option</option>';
foreach ($selection as $selection) {
$selected = ($options == $selection) ? "selected" : "";
echo '<option '.$selected.' value="'.$selection.'">'.$selection.'</option>';
}
echo '</select>';
The code basically places all of your options in an array which are called upon in the foreach loop. The loop checks to see if your $options variable matches the current selection it's on, if it's a match then $selected will = selected, if not then it is set as blank. Finally the option tag is returned containing the selection from the array and if that particular selection is equal to your $options variable, it's set as the selected option.
for example ..and please use mysqli() next time because mysql() is deprecated.
<?php
$select="select * from tbl_assign where id='".$_GET['uid']."'";
$q=mysql_query($select) or die($select);
$row=mysql_fetch_array($q);
?>
<select name="sclient" id="sclient" class="reginput"/>
<option value="">Select Client</option>
<?php $s="select * from tbl_new_user where type='client'";
$q=mysql_query($s) or die($s);
while($rw=mysql_fetch_array($q))
{ ?>
<option value="<?php echo $rw['login_name']; ?>"<?php if($row['clientname']==$rw['login_name']) echo 'selected="selected"'; ?>><?php echo $rw['login_name']; ?></option>
<?php } ?>
</select>
Just Add an extra hidden option and print selected value from database
<option value="<?php echo $options;?>" hidden><?php echo $options;?></option>
<option value="PHP">PHP</option>
<option value="ASP">ASP</option>
Select value from drop down.
<select class="form-control" name="category" id="sel1">
<?php foreach($data as $key =>$value) { ?>
<option value="<?php echo $data[$key]->name; ?>"<?php if($id_name[0]->p_name==$data[$key]->name) echo 'selected="selected"'; ?>><?php echo $data[$key]->name; ?></option>
<?php } ?>
</select>
THE EASIEST SOLUTION
It will add an extra in your options but your problem will be solved.
<?php
if ($editing == Yes) {
echo "<option value=\".$MyValue.\" SELECTED>".$MyValue."</option>";
}
?>
$option = $result['semester'];
<option >Select</option>
<option value="1st" <?php if($option == "1st") echo 'selected = "selected"'; ?>>1st</option>
<option value="2nd" <?php if($option == "2nd") echo 'selected = "selected"'; ?>>2nd</option>
<option value="3rd" <?php if($option == "3rd") echo 'selected = "selected"'; ?>>3rd</option>
<option value="4th" <?php if($option == "4th") echo 'selected = "selected"'; ?>>4th</option>
<option value="5th" <?php if($option == "5th") echo 'selected = "selected"'; ?>>5th</option>
<option value="6th" <?php if($option == "6th") echo 'selected = "selected"'; ?>>6th</option>
<option value="7th" <?php if($option == "7th") echo 'selected = "selected"'; ?>>7th</option>
<option value="8th" <?php if($option == "8th") echo 'selected = "selected"'; ?>>8th</option>
</select>
BEST code and simple
<select id="example-getting-started" multiple="multiple" name="category">
<?php
$query = "select * from mine";
$results = mysql_query($query);
while ($rows = mysql_fetch_assoc(#$results)){
?>
<option value="<?php echo $rows['category'];?>"><?php echo $rows['category'];?></option>
<?php
}
?>
</select>
You can also do like this ....
<?php $countryname = $all_meta_for_user['country']; ?>
<select id="mycountry" name="country" class="user">
<?php $myrows = $wpdb->get_results( "SELECT * FROM wp_countries order by country_name" );
foreach($myrows as $rows){
if( $countryname == $rows->id ){
echo "<option selected = 'selected' value='".$rows->id."'>".$rows->country_name."</option>";
} else{
echo "<option value='".$rows->id."'>".$rows->country_name."</option>";
}
}
?>
</select>
Answer is simple.
when u pass value from dropdown.
Just use as if else.
for eg:
foreach($result as $row) {
$GLOBALS['output'] .='<option value="'.$row["dropdownid"].'"'.
($GLOBALS['passselectedvalueid']==$row["dropwdownid"] ? ' Selected' : '').'
>'.$row['valueetc'].'</option>';
}
<?php
$sql = "select * from mine where username = '$user' ";
$res = mysql_query($sql);
while($list = mysql_fetch_assoc($res)){
$category = $list['category'];
$username = $list['username'];
$options = $list['options'];
?>
<input type="text" name="category" value="<?php echo '$category' ?>" readonly="readonly" />
<select name="course">
<option value="0">Please Select Option</option>
<option value="PHP" <?php echo $options == 'PHP' ? 'selected' : ''; ?> >PHP</option>
<option value="ASP" <?php echo $options == 'ASP' ? 'selected' : ''; ?> >ASP</option>
</select>
<?php
}
?>
USING PDO
<?php
$username = "root";
$password = "";
$db = "db_name";
$dns = "mysql:host=localhost;dbname=$db;charset=utf8mb4";
$conn = new PDO($dns,$username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "select * from mine where username = ? ";
$stmt1 = $conn->prepare($sql);
$stmt1->execute(array($_POST['user']));
$all = $stmt1->fetchAll(); ?>
<div class="controls">
<select data-rel="chosen" name="degree_id" id="selectError">
<?php
foreach($all as $nt) {
echo "<option value =$nt[id]>$nt[name]</option>";
}
?>
</select>
</div>
I'm using eval() PHP function like this:
My PHP code:
$selOps1 = $selOps2 = $selOps3 = '';
eval('$selOps'. $dbRow["DBitem"] . ' = "selected";');
Then in my select box I use it like this:
<select>
<option <?=$selOps1?> value="1">big</option>
<option <?=$selOps2?> value="2">Middle</option>
<option <?=$selOps3?> value="3">Small</option>
</select>
Put value from db into a variable and check like following code example
<select class="form-control" name="currency_selling" required >
<option value="">Select Currency</option>
<option value="pkr" <?=$selected_currency == 'pkr' ? ' selected="selected"' : '';?> >PKR</option>
<option value="dollar" <?=$selected_currency == 'dollar' ? ' selected="selected"' : '';?> >USD</option>
<option value="pounds" <?=$selected_currency == 'pounds' ? ' selected="selected"' : '';?> >POUNDS</option>
<option value="dirham" <?=$selected_currency == 'dirham' ? ' selected="selected"' : '';?> >DRHM</option>
</select>
This may help you.
?php
$sql = "select * from mine where username = '$user' ";
$res = mysql_query($sql);
while($list = mysql_fetch_assoc($res))
{
$category = $list['category'];
$username = $list['username'];
$options = $list['options'];
?>
<input type="text" name="category" value="<?php echo '$category' ?>" readonly="readonly" />
<select name="course">
<option value="0">Please Select Option</option>
// Assuming $list['options'] is a coma seperated options string
$arr=explode(",",$list['options']);
<?php foreach ($arr as $value) { ?>
<option value="<?php echo $value; ?>"><?php echo $value; ?></option>
<?php } >
</select>
<?php
}
?>
This question was asked already, but my question is very simple.
In the my account page, I have the employee country in a dropdown.
How to select a value in the combo, when in edit mode?
Let's assume you have the user's country in $user_country and the list of all countries in $all_countries array:
<select id="country">
<?php
foreach ( $all_countries as $country ):
$selected = "";
if ( $country == $user_country )
$selected = "selected";
?>
<option value="<?php echo $country; ?>"
selected="<?php echo $selected; ?>">
<?php echo $country; ?>
</option>
<?php
endforeach; ?>
</select>
should work.
An option tag will be the default for a select list when the selected attribute is set. In the following code option 2 will show up as the current selected option when the page loads:
<select>
<option value="1">1</option>
<option value="2" selected="selected">2</option>
<option value="3">3</option>
</select>
To achieve this in your PHP code conditionally display the selected attribute on your options against what the current value is:
<option value="1"<?php if($user['country'] == '1') { ?> selected="selected"<?php } ?>>1</option>
<option value="2"<?php if($user['country'] == '2') { ?> selected="selected"<?php } ?>>2</option>
<option value="3"<?php if($user['country'] == '3') { ?> selected="selected"<?php } ?>>3</option>
function p_edit_combo($cCurstatus,$h_code_default,$h_name=NULL){
<select name="<?php echo $cCurstatus;?>" id="<?php echo $cCurstatus;?>" class="main_form_select">
<option value="">Select</option>
<?php
$sql_h = "SELECT h_code,h_name FROM med_hl WHERE status = 1";
$sql_h_result = mysql_query($sql_h);
while($row=mysql_fetch_array($sql_h_result)){
$h_code = $row['h_code'];
$h_name = $row['h_name'];
?>
<option <?php if($h_code_default==$h_code){ ?> selected="selected" <?php }?> value='<?php echo $h_code; ?>' >
<?php echo $h_code."|".$h_name; ?>
</option>
<?php } ?>
</select>
<?php
}
**i have two table
" users" colmns(fname,lname,...as on ohther_infomation,hobbies datatype(int))
"info" columns (id (primary_key),hobbies(varchar 200)); in which i stored for hobbies name
In my case i am storing values in from (1,2,3,4) in hobbies (int) filled of users table which i matached them through join after time of fetch them,
in my info table i stored hobbies by their name (reading, writing,playing,gyming)
$row has our users selected hobbies (int)
$rows has list of our hobbies(varchar)
edit.php i need Dropdown value selected :==== And i am Doing Like this :--- (100% Working)**
<div class="form-control">
<label for="hobbies">Hobbies</label>
<select name="hobbies">
<?php
$query = "SELECT * FROM info";
$results = mysqli_query($connect, $query);
while ($rows = mysqli_fetch_array($results)) {
?>
<option <?php if ($rows['id'] == $row['hobbies']) { ?> selected="selected" <?php } ?> value='<?php echo $rows['id']; ?>'>
<?php echo $rows['hobbies']; ?>
</option>
<?php
}
?>
</select>
<span class="text-danger"><?php if (isset($err_hobbies)) echo $err_hobbies; ?></span>
</div>