Pass parameters from view to model in joomla - php

In a joomla custom made component there are multiple posts on a page, and every post contains multiple comment, so in view i want to call comments by post id. please suggest a good method to make it working.

You have two options. The first, is to attach the comment id as a URL paramater and retrieve it within the model as needed like so:
$comment_id = JRequest::getApplication()->input->get('comment_id');
If you wish to pass in a parameter when calling the model from the view class, you need to get an instance of the MVC path model instead of using the short cut method. So, instead of using this in the JView class:
$this->items = $this->get('Items');
You would do this instead:
$model = $this->getModel();
$this->items = $model->getItems($comment_id);
Hope this helps.

Related

How to call function from controller in different view in cakephp 3?

I have function in ProductsController productsCount(). It give me amount of records in table.
public function productsCount() {
$productsAmount = $this->Products->find('all')->count();
$this->set(compact('productsAmount'));
$this->set('_serialize', ['productsAmount']);
}
I want to call this function in view of PageController. I want to simply show number of products in ctp file.
How can i do this?
You can use a view cell. These act as mini controllers that can be called into any view, regardless of controller.
Create src/View/Cell/productsCountCell.php and a template in src/Template/Cell/ProductsCount/display.ctp
In your src/View/Cell/productsCountCell.php
namespace App\View\Cell;
use Cake\View\Cell;
class productsCountCell extends Cell
{
public function display()
{
$this->loadModel('Products');
$productsAmount = $this->Products->find('all')->count();
$this->set(compact('productsAmount'));
$this->set('_serialize', ['productsAmount']);
}
}
In src/Template/Cell/ProductsCount/display.ctp lay it out how you want:
<div class="notification-icon">
There are <?= $productsAmount ?> products.
</div>
Now you can call the cell into any view like so:
$cell = $this->cell('productsCount');
I think it would make more sense to just find the product count in the PageController. So add something like $productsAmount = $this->Page->Products->find('all')->count(); in the view action of PageController, and set $productsAmount. If Page and Products aren't related, then you can keep the find call as is as long as you include a use for Products.
Also check this out for model naming conventions: http://book.cakephp.org/3.0/en/intro/conventions.html#model-and-database-conventions
Model names should be singular, so change Products to Product.
you can not call controller method from view page. you can create helper, which you can call from view page.
here you will get a proper documentation to creating helpers-
http://book.cakephp.org/3.0/en/views/helpers.html#creating-helpers
It just depend on the kind of call you're making because there are 3 cases for your issue..
1- If you're calling by a link to click you simply do:
<?= $this->Html->link(_('Product number'),['controller' =>'ProductsController', 'action' => 'productsCount']) ?>
The 2 other cases are whether you want to render the result straight in that same view, then there are some workaround to do.
1- first you will need to check what are the associations between the Page table and the product table and use BelongTo or hasMany option to bind them togheter for proper use.
2- If no association between the tables then you will nedd TableRegistry::get('Produts'); to pass data from a model to another, just like this way in the Pages controller:
public function initialize()
{
parent::initialize();
$this->Products = TableRegistry::get('Produts');
}
But i quite believe that the first option is more likely what you described.
Also you can define static method as below
public static function productsCount() {
return = $this->Products->find('all')->count();
}
And use self::productsCount() in other action.
This is useful only if you need to get count multiple time in controller. otherwise you can use it directly in action as below:
$this->Products->find('all')->count();

How to render a form of another class view in Yii?

In Yii, I have a view belonging to class A, and in a view corresponding to this class, I want to add a form to create a model of another class.
So, in protected/views/pictures/myview.php, I have:
<?php
/* #var $this PicturesController */
/* #var $model Pictures */
$objectForm = new Objects();
$newForm = ObjectsController::renderPartial('create',array('model'=>$objectForm),true);
?>
And I am trying to add a form to render protected/views/objects/create.php. But the above code doesn't work since the view is still trying to load the create form from the Pictures class. Since I am obtaining errors saying that same properties of Objects are not defined, because the system is loading the Pictures create form.
How can I add the create form of the Objects model?
Note: I added "applications.controllers.*" to the import array in main.php, but I understand this is a bad practice. Is there any possible solutions that doesn't involve me to do this?
Thanks.
In this case you just needed to link the correct view in the renderPartial:
$objectForm = new Objects();
$newForm = ObjectsController::renderPartial('/objects/create',array('model'=>$objectForm),true); // "/objects/create", and not "create".
Those errors were giving because Yii understood you were rendering to the create view of pictures, and you gave it the model of Objects (rather than the model of Pictures).
If we were talking about a render call in the controller, and you want to render a view from another action that belongs to another controller, you do not render to this view directly. You have to "redirect" to the action of this other controller (that belongs to the other class).
try like this this
$this->renderPartial('application.staff.views.default.create',array());
this is the format
$this->renderPartial('context_text.views.display._display_text');

how to create a method on the fly in ci

I'm writing a control panel for my image site. I have a controller called category which looks like this:
class category extends ci_controller
{
function index(){}// the default and when it called it returns all categories
function edit(){}
function delete(){}
function get_posts($id)//to get all the posts associated with submitted category name
{
}
}
What I need is when I call http://mysite/category/category_name I get all the posts without having to call the get_posts() method having to call it from the url.
I want to do it without using the .haccess file or route.
Is there a way to create a method on the fly in CodeIgniter?
function index(){
$category = $this->uri->segment(2);
if($category)
{
get_posts($category); // you need to get id in there or before.
}
// handle view stuff here
}
The way I read your request is that you want index to handle everything based on whether or not there is a category in a uri segment. You COULD do it that way but really, why would you?
It is illogical to insist on NOT using a normal feature of a framework without explaining exactly why you don't want to. If you have access to this controller, you have access to routes. So why don't you want to use them?
EDIT
$route['category/:any'] = "category/get_posts";
That WOULD send edit and delete to get_posts, but you could also just define those above the category route
$route['category/edit/:num'] = "category/edit";
$route['category/delete/:num'] = "category/delete";
$route['category/:any'] = "category/get_posts";
That would resolve for the edit and delete before the category fetch. Since you only have 2 methods that conflict then this shouldn't really be that much of a concern.
To create method on the fly yii is the best among PHP framework.Quite simple and powerful with Gii & CRUD
http://www.yiiframework.com/doc/guide/1.1/en/quickstart.first-app
But I am a big CI fan not Yii. yii is also cool though.
but Codeigniter has an alternative , web solution.
http://formigniter.org/ here.

Passing two arrays from controller in cakePHP

I'm trying my best to learn MVC and cakePHP and I had a question about passing arrays to the view. Currently, I have some basic code below.
class AwarenesscampaignsController extends AppController {
public function view($id = null) {
$this->Awarenesscampaign->id = $id;
$this->set('data', $this->Awarenesscampaign->read());
}
This is what I "think" is currently happening.
AwarenesscampaignsController is set up. The view paramater requests id and matches it up with the Model, Awarenesscampaign. This matches up with the database and returns an array which is set to the variable "$data", and then the view is loaded.
My first question: is my understanding accurate?
What I would like to do is with this is to be able to pass another array, from a different model. For instance, I would like to query the table Posts (Controller: PostsController/ Model: Post).
For instance, my first attempt was to do the following inside the function:
$this->Post->find('all');
But this yields the error:
Indirect modification of overloaded property AwarenesscampaignsController::$Post has no effect [APP/Controller/AwarenesscampaignsController.php, line 20]
Additionally, I'm not sure how I would send both variables to the view.
To recap:
Was my understanding accurate?
How do I query a variable from another controller/model?
How do I sent this array to the appropriate view for that controller?
Thanks,
-M
You're on the right lines, and aren't doing it wrong per se. I would say your understanding is pretty good for a beginner.
By default Cake automatically loads a model that it thinks is directly related to the controller. So in AwarenesscampaignController, you can automatically access Awarenesscampaign (the model).
It doesn't know about any other model, though. One way you might solve this is by adding the following property to your controller:
// This has to contain ALL models you intend to use in the controller
public $uses = array('Awarenesscampaign', 'Post');
This goes at the top of the class, before you start declaring the functions. It tells Cake that you want to use other models except the 'default' one, but you have to add that one to the array too, or you'll lose access to it.
You can also use loadModel inside your action, if it's a one-off. It's then accessed the same way as you would access a model normally:
public function view($id = null) {
$this->loadModel('Post');
$posts = $this->Post->find('all');
...
}
To send this to your view, you can call set again, but you might want to change data to something more readable, and to prevent confusion:
public function view($id = null) {
...
$this->set('campaign', $this->Awarenesscampaign->read());
$this->set('posts', $this->Post->find('all'));
}
They'll be accessible as $campaign and $post respectively.
One tweak I would make, though, is to not use 'read' unless you intend to edit something. You can use findByColumnName to get the same data. Since you're using just an id, you can call findById:
$campaign = $this->Awarenesscampaign->findById($id);
There's quite a lot of magic going on there. It just means you can search for a particular value in a more short-hand format.
http://book.cakephp.org/2.0/en/models/retrieving-your-data.html
Finally, while you can access other models (as demonstrated), you can't, or generally shouldn't, try and access one controller from another. If you have code that you want to use in more than one controller, but can't go in the model, you can create Components.
http://book.cakephp.org/2.0/en/controllers/components.html#creating-a-component
The manual is fairly comprehensive. While sometimes hard to navigate, it will often have an answer to most of your questions.
http://book.cakephp.org/2.0/en/
1) Your understanding is good enough. What this is doing is basically mapping a row of database table with object. So after setting the Model id $this->Awarenesscampaign->id = $id, now Model is pointing to the row of database table that has id equals to what has been passed to view action.
2) you can query another table by calling the methods of that particular Model. If your model is somehow associated with the current Model that you are in, you can use chaining to call that Model's action. e.g. if your in Posts controller and Post Model is associated with Comment Model t get the data you can chain through.
$comments = $this->Post->Comment->find();
If however your Model of interest is not associated with current Model, there are couple of ways to perform operations of other Model. A good option is to use Class Registry. Say for example you want to use Customer Model which is not related to your current Model. In your controller you will do
$customer= ClassRegistry::init("Customer");
$customers= $customer->find();
3) to set multiple variables for the view you can set them via compact function or using associated row.
$posts = $this->Post->find();
$comments = $this->Post->Comment->find();
$this->set(compact('posts', 'comments'));
// or
$this->set('posts' => $posts, 'comments' => $comments);

CakePHP: Get model instance by url string

I have a CakePHP website and navigaton links are stored in database. What i want is for some navigation entries to call custom function which will return some additional, dynamic data about the link: I want to add a count of articles for link "Vacancies". I could call a function on a model that would return total count. This link is to be rendered on every page.
So i need to get appropriate models instance, but not for the current request, but the request where url points to.
So basically i have url "/en/vacancies". I can get controller name by:
$urlInfo = Router::parse("/en/vacancies");
$controllerName = $urlInfo['controller'];
What would be the reliable way to do that?
Any other solutions for the problem are welcome.
Assuming you have the method to gather the navigation link data in a Model.
App::import('Controller', $controllerName);
$controller = new $controllerName;
$controller->loadModel('YourModel');
$yourModel = $controller->YourModel;
$yourData = $yourModel->your_method();
There are a variety of other ways to do this. But, without knowing more about where you're actually going to be calling this function I can't really provide anymore suggestions.

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