I have googled for a day without a luck. Can anyone help please??
I have an AJAX request which loads more categories at home page. The code is
$json=array();
$template = new Template();
$template->data['categories'] = $this->data['categories'];
$html = $template->fetch($this->config->get('config_template') . '/template/common/category_load.tpl');
$json['success'] = $html;
$json['output'] = $this->render();
$this->response->setOutput(json_encode($json));
While I check the function it gives the correct output. But while trying to load through AJAX it gives the error saying
failed to open stream: Success in /var/www/html/boomrc/system/engine/controller.php on line 82
Have I done any mistake? I'm new to OpenCart.
if (file_exists(DIR_TEMPLATE . $this->config->get('config_template') . '/template/common/category_load.tpl')) {
$this->template = $this->config->get('config_template') . '/template/common/category_load.tpl';
}
$json['content'] = str_replace("\r\n", "", $this->render());
echo json_encode($jdata);
Try this one..
Please use Browser-Debug-Console.
Be sure, that you doesn't do a cross-domain-request for your ajax.
There are some security-limitations, so you can't do cross-domain request for ajax.
Maybe post your controlle.php (or simplified code of it) here.
Related
My case is, I want to scrap a website, which is success, and I'm using PHP cURL. The problem start when I want to use the DOM Parser to get the content I want. Here is the warning came out:
the error image is here
And the code I use is here. Before this code, I scrap a website using cURL, it's working, but just this part got error :
include 'simple_html_dom.php';
//Here is where I scraping, no need to show it
$fp = fopen(dirname(__FILE__) . '/airpaz.html', 'w');
//$html contain the page I scrap
fwrite($fp, $html);
fclose($fp);
$html_content = file_get_contents(dirname(__FILE__) . '/airpaz.html');
echo $html_content;
$html2 = new simple_html_dom();
$html2->load_file($html_content);
Hope you guys can help, thanks
It looks like you are trying to read a file 3 times:
$read_file = fread($fr, filesize(dirname(__FILE__) . '/airpaz.html'));
and:
$html_content = file_get_contents($read_file);
and:
$html2->load_file($html_content);
In the last two instances, instead of a file-name you pass html contents to the function so that will not work.
You should read the file only once and use string functions on the contents you receive. Or you open the url directly in $html2->load_file().
try this code
include 'simple_html_dom.php';
$html_content = file_get_html(dirname(__FILE__) . '/airpaz.html');
echo $html_content;
$html2 = new simple_html_dom();
$html2->load_file($html_content);
I am working on a website and am looking to retrieve the 6 most recent photos from an instagram account and make the caption the hover text. My code below works, but what I notice is that after I refresh the page once or twice, I start getting this error:
Warning: file_get_contents(http://instagram.com/green_tree_relief): failed to open stream: HTTP request failed! HTTP/1.1 503 No server is available for the request on line 14
I assume this is instagram blocking me for my behavior?
I am looking for a way around this, if possible. I tried to spoof a user agent and that didn't work. If I am not misunderstanding their API deprecation, they won't allow you to use it to get even public content. I can see this as an ethically gray area I suppose, so abandoning this functionality altogether is an option, but I would like to get this to work.
Anyways, on my main page there is an ajax call to this PHP script which then inserts the generated HTML upon success:
function scrape_insta($username) {
$insta_source = file_get_contents('http://instagram.com/'.$username);
$shards = explode('window._sharedData = ', $insta_source);
$insta_json = explode(';</script>', $shards[1]);
$insta_array = json_decode($insta_json[0], TRUE);
return $insta_array;
}
$my_account = 'green_tree_relief';
$photostreamHTML = '';
$results_array = scrape_insta($my_account);
for($i = 0; $i < 6; $i++) {
if(isset($results_array['entry_data']['ProfilePage'][0]['graphql']['user']['edge_owner_to_timeline_media']['edges'][$i]['node']['edge_media_to_caption']['edges'][0]['node']['text'])) {
$caption = $results_array['entry_data']['ProfilePage'][0]['graphql']['user']['edge_owner_to_timeline_media']['edges'][$i]['node']['edge_media_to_caption']['edges'][0]['node']['text'];
}
if(isset($results_array['entry_data']['ProfilePage'][0]['graphql']['user']['edge_owner_to_timeline_media']['edges'][$i]['node']['display_url'])) {
$photostreamHTML .= '<div style="height: 84px;">
<a href="https://www.instagram.com/' . $my_account . '" target="_blank">
<img src="'
. $results_array['entry_data']['ProfilePage'][0]['graphql']['user']['edge_owner_to_timeline_media']['edges'][$i]['node']['display_url'] . '"
class ="img-responsive" title = "' . $caption . '">
</a>
</div>';
}
}
As I said, it works the first couple of times I load the page when I haven't been working on the site for a few hours but then it fails after that.
Any suggestions would be appreciated.
I am having some trouble with a url I encoded, I am getting this error and I don't know how to fix it.
Warning: file_get_contents(%27http%3A%2F%2Fapi.steampowered.com%2FISteamUser%2FGetPlayerSummaries%2Fv0002%2F%3Fkey%3D%27+..+%27%26steamids%3D%27+..) [function.file-get-contents]: failed to open stream: No such file or directory.
Is it not looking outside my home directory? Anyone know how to make the url function?
Any help would be awesome!
<?php
$url= "'http://api.steampowered.com/ISteamUser/GetPlayerSummaries/v0002/?key=' .$apikey. '&steamids=' .$keyword.";
$string=file_get_contents(urlencode($url));
$json_a=json_decode($string,true);
$json_o=json_decode($string);
//array method
foreach($json_a[personaname] as $p)
{
echo '
<p>
Name: '.$p[response][players][personaname].'
';
}
?>
Assign your URL enclosed in only one type of quotes:
$url= "http://api.steampowered.com/ISteamUser/GetPlayerSummaries/v0002/?key=" . $apikey . '&steamids=' . $keyword;
Hi I have been having problems with the google weather api having errors Warning: simplexml_load_string() [function.simplexml-load-string]: Entity: line 2: parser error ....
I tried to use the script of the main author(thinking it was my edited script) but still I am having this errors I tried 2
//komunitasweb.com/2009/09/showing-the-weather-with-php-and-google-weather-api/
and
//tips4php.net/2010/07/local-weather-with-php-and-google-weather/
The weird part is sometimes it fixes itself then goes back again to the error I have been using it for months now without any problem, this just happened yesterday. Also the demo page of the authors are working but I have the same exact code any help please.
this is my site http://j2sdesign.com/weather/widgetlive1.php
#Mike I added your code
<?
$xml = file_get_contents('http://www.google.com/ig/api?weather=jakarta'); if (! simplexml_load_string($xml)) { file_put_contents('malformed.xml', $xml); }
$xml = simplexml_load_file('http://www.google.com/ig/api?weather=jakarta');
$information = $xml->xpath("/xml_api_reply/weather/forecast_information");
$current = $xml->xpath("/xml_api_reply/weather/current_conditions");
$forecast_list = $xml->xpath("/xml_api_reply/weather/forecast_conditions");
?>
and made a list of the error but I can't seem to see the error cause it's been fixing itself then after sometime goes back again to the error
here is the content of the file
<?php include_once('simple_html_dom.php'); // create doctype $dom = new DOMDocument("1.0");
// display document in browser as plain text
// for readability purposes //header("Content-Type: text/plain");
// create root element
$xmlProducts = $dom->createElement("products");
$dom->appendChild($xmlProducts);
$pages = array( 'http://myshop.com/small_houses.html', 'http://myshop.com/medium_houses.html', 'http://myshop.com/large_houses.html' ) foreach($pages as $page) { $product = array(); $source = file_get_html($page); foreach($source->find('img') as $src) { if (strpos($src->src,"http://myshop.com") === false) { $product['image'] = "http://myshop.com/$src->src"; } } foreach($source->find('p[class*=imAlign_left]') as $description) { $product['description'] = $description->innertext; } foreach($source->find('span[class*=fc3]') as $title) { $product['title'] = $title->innertext; } //debug perposes! echo "Current Page: " . $page . "\n"; print_r($product); echo "\n\n\n"; //Clear seperator } ?>
When simplexml_load_string() fails you need to store the data you're trying to load somewhere for review. Examining the data is the first step to diagnose what it causing the error.
$xml = file_get_contents('http://example.com/file.xml');
if (!simplexml_load_string($xml)) {
file_put_contents('malformed.xml', $xml);
}
I read several similar posts but I don't see my fault.
index.php looks like:
<head>
<title>Demo Title</title>
</head>
<body>
<?php
require_once "footer.php";
?>
</body>
footer.php looks like:
<?php
/*
* _$ Rev. : 08 Sep 2010 14:52:26 $_
* footer.php
*/
$host = $_SERVER['SERVER_NAME'];
$param = $_SERVER ['REQUEST_URI'];
$url = "http://".$host.$param;
echo $url;
$file = # fopen($_SERVER[$url],"r") or die ("Can't open HTTP_REFERER.");
$text = fread($file,16384);
if (preg_match('/<title>(.*?)<\/title>/is',$text,$found)) {
$title = $found[1];
} else {
$title = " -- no title found -- ";
}
?>
A request for the URL http://127.0.0.1/test/index.php results in:
http://127.0.0.1/test/index.phpCan't open HTTP_REFERER.
or for http://127.0.0.1/test/
http://127.0.0.1/test/Can't open HTTP_REFERER.
Any hints appreciated.
$_SERVER is an array which contains a bunch of fields relating to the server config. It does not contain an element named "http://".$host.$param, so trying to open that as a filename will result in the fopen call failing, and thus going to the die() statement.
More likely what you wanted to do was just open the file called "http://".$host.$param. If that's what you want, then just drop the $_SERVER[] bit and it should work better.
Note that because it's a URL, you will need your PHP config to allow opening of remote files using fopen(). PHP isn't always configured this way by default as it can be a security risk. Your dev machine may also be configured differently to the system you will eventually deploy to. If you find you can't open a remote URL using fopen(), there are alternatives such as using CURL, but they're not quite as straightforward as a simple fopen() call.
Also, if you're reading the whole file, you may want to consider file_get_contents() rather than fopen() and fread(), as it replaces the whole thing into a single function call.
try this:
$file = # fopen($url,"r") or die ("Can't open HTTP_REFERER.");
Try
<?php
$dom = new DOMDocument();
$host = $_SERVER['SERVER_NAME'];
$param = $_SERVER ['REQUEST_URI'];
$url = "http://".$host.$param;
echo 'getting title for page: "' . $url . '"';
$dom->loadHTML($url);
$dom->getElementsByTagName('title');
if ($dom->length)
{
$title = $dom->item(0);
echo $title;
}
else
{
echo 'title tag not found';
}
?>
I can see your trying to track the referral's title
You need to use $_SERVER['HTTP_REFERER']; to get that
what you want to do is something like this
$referrer = (!empty($_SERVER['HTTP_REFERER']) && !substr($_SERVER['SERVER_NAME']) ? $_SERVER['HTTP_REFERER'] : false);
if($referrer)
{
try
{
if(false !== ($resource = fopen($referrer,"r")))
{
$contents = '';
while($contents .= fread($resource,128))
{}
if(preg_match('/<title>(.*?)<\/title>/is',$contents,$found))
{
echo 'Referrer: ' $found[1];
}
}
}catch(Exception $e){}
}