I am having no luck trying to compare values in an array passed as a GET to values in a database recordset do/while loop. I'm attempting to make a checkbox checked if any value in the GET array matches a recordset id. It works if you use only one interest id in the URL without a comma. Thank you.
My URLs are:
interestSearch.php?interests=3 (this works)
interestSearch.php?interests=3,8 (doesn't work)
<? require('db.php');
mysql_select_db($database_data);
$query_allInterests = "SELECT * FROM interests";
$allInterests = mysql_query($query_allInterests, $data) or die(mysql_error());
$row_allInterests = mysql_fetch_assoc($allInterests);
$totalRows_allInterests = mysql_num_rows($allInterests);
?>
<form method="get">
<? do { ?>
<input <?
if(isset($_GET['interests']) && $_GET['interests'] != "") {
$theCounter = 0;
$theArray = array($_GET['interests']);
foreach ($theArray as $value) {
// if ($value == $row_allInterests['id']) {$theCounter++;}
if (in_array($row_allInterests['id'], $theArray)) {$theCounter++;}
}
if($theCounter > 0){echo "checked";}
}
?> name="<? echo $row_allInterests['id']; ?>" class="doCheck" type="checkbox" id="<? echo $row_allInterests['id']; ?>" value="<? echo $row_allInterests['id']; ?>" /> <? echo $row_allInterests['interest']; ?><br />
<? } while ($row_allInterests = mysql_fetch_assoc($allInterests)); ?>
</form>
Instead of
$theArray = array($_GET['interests']);
Use
$theArray = explode( ',', $_GET['interests']);
Related
I need to use nested foreach for dependent checkboxes.
<input type="checkbox" name="all[]" value="<?php echo $row_bus_details['busid'];?>" >
<?php
$book_side_result = mysqli_query($db,"select * from advt_sides");
while($book_side_row=mysqli_fetch_array($book_side_result))
{
?>
<input type="checkbox" name="bookingside[]" value="<?php echo $book_side_row['advt_side_id']; ?>" id="<?php echo $book_side_row['advt_side']; ?><?php echo $row_bus_details['busid'];?>" > <?php echo $book_side_row['advt_side']; ?><br/>
<?php } ?>
I need to loop the selected values of second checkbox if the first checkbox is selected.
I wrote the code like
$i = 0;
$busid = isset($_POST['all']) ? $_POST['all'] : array();
foreach ((array)$busid as $item) {
if(!empty($_POST['bookingside'])) {
foreach($_POST['bookingside'] as $side) {
$sql_book_side=mysqli_query($db,"INSERT INTO `advt_book_side`(bus_id,sides_id) VALUES ('$item','$side')");
$i++;
}
}
}
The result I need is just like the image below
You need to save data in serialize array from in data base like:
$sql_book_side=mysqli_query($db,"INSERT INTO advt_book_side(bus_id,sides_id) VALUES ('$item',serialize(array('left'=>1,'right'=>1,'back'=>0)))");
Print check box with check uncheck using below code
$book_side_result = mysqli_query($db,"select * from advt_sides");
while($book_side_row=mysqli_fetch_array($book_side_result))
{
$array = unserialize($book_side_row['sides_id']);
foreach($array[0] as $side){
?>
<input type="checkbox" name="bookingside[]" value="<?php echo ($side)? $side:0; ?>">
<?php }
} ?>
The foreach loop at the end with $_POST['clients'] only returns one value. Whats wrong?
<?php $clients_to_display = Client::find_all(); ?>
<p><?php foreach ($clients_to_display as $key) {
echo $key->name; ?>:<input type='checkbox' name='clients[]' value=<?php $key->name; ?></><br/>
<?php } ?></p>
if(isset($_POST['submit'])){
$job->name = $_POST["job_name"];
$job->description = $_POST["job_description"];
$job->type = $_POST["job_type"];
$job->age = $_POST["job_age"];
foreach ($_POST['clients'] as $key) {
echo $key;
}
}
This code does nothing:
<?php $key->name; ?>
I think you want:
<?php echo($key->name); ?>
Also, it has to be enclosed in quotes:
value="<?php echo($key->name); ?>"
Also the markup is invalid. So, the full line should be:
echo($key->name); ?>:<input type="checkbox" name="clients[]" value="<?php echo($key->name); ?>" /><br/>
I am trying to create a compare option between selected cars.
<?php
if(isset($_POST['compares'])) {
$id_nums = array($_POST['cBox']);
//$id_nums = array(1,6,12,18,24);
$id_nums1 = implode(", ", $id_nums);
$query = "SELECT * FROM wp_cars WHERE id in ($id_nums1)";
$cCars = mysql_query($query) or mysql_error();
while($car = mysql_fetch_array($cCars)) {
echo $car['cartitle']."<br/>";
echo $car['saleprice']."<br/>";
}
} else {
$query1 = "SELECT * FROM wp_cars";
$allcars = mysql_query($query1) or die(mysql_error()); `
while($car1 = mysql_fetch_array($allcars)) {
echo "<input type='checkbox' value=".$car1['id']." name='cBox[]' />";
echo $car1['cartitle']."<br/>";
echo $car1['saleprice']."<br/>";
}
}
?>
How to pass the checkbox name(cBox[]) array based on checkboxes selection.
<form action="compares.php" method="post">
<button name="compares">Select Cars to Compare</button>
</form>
$id_nums = array($_POST['cBox']);
$_POST['cBox'] is already an array, you are making a 2d array. Doing
$id_nums1 = implode(", ", $_POST['cBox']);
would do what you want. Although it is wide open to SQL injection.
From your HTML part, send inputs this way:
<form action="compares.php" method="post">
<?php foreach (mysql_fetch_array($allcars) as $car: ?>
<input type="checkbox" value="<?php echo $car['id']; ?>" name="cBox[]" />
<?php echo $car['cartitle']; ?><br />
<?php echo $car['saleprice']; ?><br />
<?php endforeach; ?>
</form>
And in your PHP part, receive inputs this way:
$id_nums = implode(",", $_POST['cBox']);
I've problem with multiple form at one page. At page index I include 4 forms
include('./poll_1a.php');
include('./poll_2a.php');
include('./poll_3a.php');
include('./poll_4a.php');
The form code at every poll page is the same. I include some unique markers ($poll_code) for every scripts but the effect is when I use one form - the sending variable are received in the others. But I would like to work each form individually.
The variable $poll_code is unique for every script -> 1 for poll_1, 2 for poll_2 etc.
The same situation is with $cookie_name
$cookie_name = "poll_cookie_".$poll_code;
than, as I see, cookies have different names.
$poll_code = "1"; // or 2, 3, 4
?>
<p>
<form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post" name="<?php echo $poll_code; ?>">
<input type="hidden" name="poll_cookie_<?php echo $poll_code; ?>" value="<?php echo $poll_code; ?>">
<table>
<?php
//print possible answers
for($i=0;$i<count($answers);$i++){
?><tr><td style="\text-allign: left;\"><input type="radio" name="vote_<?php echo $poll_code; ?>" value="<?php echo $i; ?>"> <?php echo $answers[$i]; ?></td></tr><?php
}
echo "</table>";
echo "<br>";
if ($_COOKIE["$cookie_name"] == $poll_code ) {
echo "<br> nie można głosować ponownie ...";
} else {
?>
<p><input type="submit" name="submit_<?php echo $poll_code; ?>" value="głosuj !" onClick="this.disabled = 'true';"></p>
<?php
}
?>
</form>
</p>
Q: how to make this forms to work individually at one page?
//------------------- EDIT
the receiving part of the script
$votes = file($file);
$total = 0;
$totale = 0;
$poll_cookie = 0;
if (isset($_POST["vote_$poll_code"]) && isset($_POST["poll_cookie_$poll_code"])) {
$vote = $_POST["vote_$poll_code"];
$poll_cookie = $_POST["poll_cookie_$poll_code"];
}
//submit vote
if(isset($vote)){
$votes[$vote] = $votes[$vote]+1;
}
//write votes
$handle = fopen($file,"w");
foreach($votes as $v){
$total += $v;
fputs($handle,chop($v)."\n");
}
fclose($handle);
Of course, the $file have the unique declaration too (at top of the script, under the $poll_code declaration).
$file = "poll_".$poll_code.".txt";
I think the issue might be that <?php echo $poll_code; ?> is outside the loop so maybe that it's always using the same value assigned to it, maybe put it inside the loop
I would like a change from the drop down to the checkbox, I want to change it because I want firstly select the list in the array can be selected before store to database via the checkbox, so the dropdown script was as follows
<?php
session_start();
define('DEFAULT_SOURCE','Site_A');
define('DEFAULT_VALUE',100);
define('DEFAULT_STC','BGS');
include('class/stockconvert_class.php');
$st = new st_exchange_conv(DEFAULT_SOURCE);
if(isset($_GET['reset'])) {
unset($_SESSION['selected']);
header("Location: ".basename($_SERVER['PHP_SELF']));
exit();
}
?>
<form action="do.php" method="post">
<label for="amount">Amount:</label>
<input type="input" name="amount" id="amount" value="1">
<select name="from">
<?php
$stocks = $st->stocks();
asort($stocks);
foreach($stocks as $key=>$stock)
{
if((isset($_SESSION['selected']) && strcmp($_SESSION['selected'],$key) == 0) || (!isset($_SESSION['selected']) && strcmp(DEFAULT_STC,$key) == 0))
{
?>
<option value="<?php echo $key; ?>" selected="selected"><?php echo $stock; ?></option>
<?php
}
else
{
?>
<option value="<?php echo $key; ?>"><?php echo $stock; ?></option>
<?php
}
}
?>
</select>
<input type="submit" name="submit" value="Convert">
</form>
and i Changed it to the checkbox as follows
<?php
session_start();
define('DEFAULT_SOURCE','Site_A');
define('DEFAULT_VALUE',100);
define('DEFAULT_STC','BGS');
include('class/stockconvert_class.php');
$st = new st_exchange_conv(DEFAULT_SOURCE);
if(isset($_GET['reset'])) {
unset($_SESSION['selected']);
header("Location: ".basename($_SERVER['PHP_SELF']));
exit();
}
?>
<form action="do.php" method="post">
<label for="amount">Amount:</label>
<input type="input" name="amount" id="amount" value="1"><input type="submit" name="submit" value="Convert">
<?php
$stocks = $st->stocks();
asort($stocks);
foreach($stocks as $key=>$stock)
{
if((isset($_SESSION['selected']) && strcmp($_SESSION['selected'],$key) == 0) || (!isset($_SESSION['selected']) && strcmp(DEFAULT_STC,$key) == 0))
{
?>
<br><input type="checkbox" id="scb1" name="from[]" value="<?php echo $key; ?>" checked="checked"><?php echo $stock; ?>
<?php
}
else
{
?>
<br><input type="checkbox" id="scb1" name="from[]" value="<?php echo $key; ?>"><?php echo $stock; ?>
<?php
}
}
?>
</form>
but does not work, am I need to display Other codes related?
Thanks if some one help, and appreciated it
UPDATED:
ok post the first apparently less obvious, so I will add the problem of error
the error is
Fatal error: Call to undefined method st_exchange_conv::convert() in C:\xampp\htdocs\test\do.php on line 21
line 21 is $st->convert($from,$key,$date);
session_start();
if(isset($_POST['submit']))
{
include('class/stockconvert_class.php');
$st = new st_exchange_conv(DEFAULT_SOURCE);
$from = mysql_real_escape_string(stripslashes($_POST['from']));
$value = floatval($_POST['amount']);
$date = date('Y-m-d H:i:s');
$_SESSION['selected'] = $from;
$stocks = $st->stocks();
asort($stocks);
foreach($stocks as $key=>$stock)
{
$st->convert($from,$key,$date);
$stc_price = $st->price($value);
$stock = mysql_real_escape_string(stripslashes($stock));
$count = "SELECT * FROM oc_stock WHERE stock = '$key'";
$result = mysql_query($count) or die(mysql_error());
$sql = '';
if(mysql_num_rows($result) == 1)
{
$sql = "UPDATE oc_stock SET stock_title = '$stock', stc_val = '$stc_price', date_updated = '$date' WHERE stock = '$key'";
}
else
{
$sql = "INSERT INTO oc_stock(stock_id,stock_title,stock,decimal_place,stc_val,date_updated) VALUES ('','$stock','$key','2',$stc_price,'$date')";
}
$result = mysql_query($sql) or die(mysql_error().'<br />'.$sql);
}
header("Location: index.php");
exit();
}
Why I want to change it from dropdown to checkbox?
because with via checkbox list I will be able to choose which ones I checked it was the entrance to the database, then it seem not simple to me, I looking for some help< thanks So much For You mate.
You have not removed the opening <select> tag.
But you removed the <submit> button.
You changed the name from "from" to "from[]".
EDIT: After your additions:
Using the dropdown list you were only able to select one value for from. Now you changed it to checkboxes and thus are able to select multiple entries. This results in receiving an array from[] in your script in do.php. Your functions there are not able to handle arrays or multiple selections in any way.
You have to re-design do.php, change your form back to a dropdown list or use ratio buttons instead.